Download presentation
Presentation is loading. Please wait.
1
Ksp Values that indicate how soluble a solution is.
Leads us to calculate the molarity of ions in solution.
2
Solubility Equilibrium
All compounds ionize to some extent: PbCl2(s) ↔ Pb+2(aq) + 2Cl-1(aq) NaCl(s) ↔Na+(aq) + Cl-(aq) Solubility constants are known values for the relative solubility in room temp Ksp for PbCl2 = 1.6 x 10-5 Ksp for NaCl = 36 smaller number = less soluble
3
Which substance is more soluble?
The larger the number the more soluble the substance is CaCO3 Ksp = 4.7 x10-9 Mg(OH)2 Ksp = 8.8 x 10-12
4
Solubility Product Expression
Is written from the ionization of the compound PbCl2(s) ↔ Pb+2(aq) + 2Cl-1(aq) Ksp = [Pb+2][Cl-1]2 multiply
5
Practice problem The solubility product constant of lead chloride is 1.6 x 10-5 at 25oC. Calculate concentrations of the lead & chloride ions in solution. Step 1: write ionization reaction Step 2: assign Xs Step 3: solubility product expression Step 4: substitute using Xs & solve [Pb+2] = 1.59x10-2 [Cl-] = 3.17x10-2
6
The [Ni2+] in a saturated solution of nickel II hydroxide is 2.2x10-12. What is the Ksp?
7
The Ksp of silver chromate is 1. 1 x 10-12 at 25oC
The Ksp of silver chromate is 1.1 x at 25oC. Calculate the concentrations of the silver & chromate ions in a saturated solution. [Ag+1] = [CrO4 -2] = 6.5 ✕ 10-5
8
The ENd
Similar presentations
© 2024 SlidePlayer.com Inc.
All rights reserved.