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8-7 Surface Area of Prisms and Cylinders Warm Up Problem of the Day

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Presentation on theme: "8-7 Surface Area of Prisms and Cylinders Warm Up Problem of the Day"— Presentation transcript:

1 8-7 Surface Area of Prisms and Cylinders Warm Up Problem of the Day
Lesson Presentation Course 3

2 8-7 Surface Area of Prisms and Cylinders Warm Up
Course 3 8-7 Surface Area of Prisms and Cylinders Warm Up 1. A triangular pyramid has a base area of 1.2 m2 and a height of 7.5 m. What is the volume of the pyramid? 2. A cone has a radius of 4 cm and a height of 10 cm. What is the volume of the cone to the nearest cubic centimeter? Use 3.14 for p. 3 m3 167 cm3

3 8-7 Surface Area of Prisms and Cylinders Problem of the Day
Course 3 8-7 Surface Area of Prisms and Cylinders Problem of the Day An ice cream cone is filled halfway to the top. The radius of the filled part is half the radius at the top. What fraction of the cone’s volume is filled? 1 8

4 8-7 Learn to find the surface area of prisms and cylinders.
Course 3 8-7 Surface Area of Prisms and Cylinders Learn to find the surface area of prisms and cylinders.

5 Insert Lesson Title Here
Course 3 8-7 Surface Area of Prisms and Cylinders Insert Lesson Title Here Vocabulary surface area lateral face lateral surface

6 8-7 Surface Area of Prisms and Cylinders
Course 3 8-7 Surface Area of Prisms and Cylinders Surface area is the sum of the areas of all surfaces of a figure. The lateral faces of a prism are parallelograms that connect the bases. The lateral surface of a cylinder is the curved surface.

7 Course 3 8-7 Surface Area of Prisms and Cylinders

8 Additional Example 1: Finding Surface Area
Course 3 8-7 Surface Area of Prisms and Cylinders Additional Example 1: Finding Surface Area Find the surface area of each figure to the nearest tenth. Use 3.14 for p. A. S = 2pr2 + 2prh = 2p(42) + 2p(4)(6) = 80p in2  in2 B. S = 2B + Ph = 2( • 8 • 3) + (18)(10) 1 2 = 204 ft2

9 8-7 Surface Area of Prisms and Cylinders Check It Out: Example 1
Course 3 8-7 Surface Area of Prisms and Cylinders Check It Out: Example 1 Find the surface area of each figure to the nearest tenth. Use 3.14 for p. 15 cm A. S = 2pr2 + 2prh 3 cm = 2p(152) + 2p(15)(3) = 540p in2  cm2 7 cm 7 cm 6 cm B. S = 2B + Ph = 2( • 7 • 6) + (21)(10) 1 2 10 cm 7 cm = 252 cm2

10 Additional Example 2: Exploring the Effects of Changing Dimensions
Course 3 8-7 Surface Area of Prisms and Cylinders Additional Example 2: Exploring the Effects of Changing Dimensions A cylinder has diameter 8 in. and height 3 in. Explain whether tripling the height would have the same effect on the surface area as tripling the radius. They would not have the same effect. Tripling the radius would increase the surface area more than tripling the height.

11 8-7 Surface Area of Prisms and Cylinders Check It Out: Example 2
Course 3 8-7 Surface Area of Prisms and Cylinders Check It Out: Example 2 A cylinder has diameter 6 in. and height 2 in. Explain whether doubling the height would have the same effect on the surface area as doubling the radius. Original Dimensions Double the Height Double the Radius S = 2pr2 + 2pr(2h) S = 2pr² + 2prh S = 2pr2 + 2p(2r)h = 2p(3)2 + 2p(3)(4) = 2p(3)2 + 2p(3)(2) = 2p(6) 2 + 2p(3)(2) = 30p in2 ≈ 94.2 in2 = 42p in2 ≈ in2 = 84p in2 ≈ in2 They would not have the same effect. Doubling the radius would increase the surface area more than doubling the height.

12 Additional Example 3: Application
Course 3 8-7 Surface Area of Prisms and Cylinders Additional Example 3: Application A cylindrical soup can is 7.6 cm in diameter and 11.2 cm tall. What is the area of the label that covers the side of the can? Only the lateral surface needs to be covered. L = 2rh = 2(3.8)(11.2) Diameter = 7.6 cm, so r = 3.8 cm. ≈ cm2

13 8-7 Surface Area of Prisms and Cylinders Check It Out: Example 3
Course 3 8-7 Surface Area of Prisms and Cylinders Check It Out: Example 3 A cylindrical storage tank that is 6 ft in diameter and 12 ft tall needs to be painted. The paint will cover 100 square feet per gallon. How many gallons will it take to paint the tank? S = 2r2 + 2rh The diameter is 6 ft, so r = 3 ft. = 2(32) + 2(3)(12) ≈ ft2 Move the decimal point 2 places to the left to divide by 100. ≈ gal

14 Insert Lesson Title Here
Course 3 8-7 Surface Area of Prisms and Cylinders Insert Lesson Title Here Lesson Quiz Find the surface area of each figure to the nearest tenth. Use 3.14 for p. 1. the triangular prism 2. the cylinder 360 cm2 320.3 in2 3. All outer surfaces of a box are covered with gold foil, except the bottom. The box measures 6 in. long, 4 in. wide, and 3 in. high. How much gold foil was used? 84 in2


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