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Trigonometry Lesson 3 Aims:

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Presentation on theme: "Trigonometry Lesson 3 Aims:"— Presentation transcript:

1 Trigonometry Lesson 3 Aims:
• To know and learn 3 special trig identities. • To be able to prove various trig identities • To be able to solve angle problems by using Pythagoras rule and using the trig identities.

2 Trigonometric identities
Earlier in the course you met the following trigonometric identities: We can rearrange these to give the identities in terms of sec θ, cosec θ and cot θ below! If necessary, remind students of the difference between an equation and an identity.

3 Problems involving reciprocal trig functions
Given that x is an acute angle and tan x = find the exact values of cot x, sec x and cosec x. Using the identities: Using a right-angled triangle, we could define sec x as hypotenuse/adjacent, cosec x as hypotenuse/opposite and cot x as adjacent/opposite. Therefore cot x = sec x = cosec x =

4 Problems involving reciprocal trig functions
Given that x is an acute angle and tan x = find the exact values of cot x, sec x and cosec x. An alternative method! Using the following right-angled triangle: The length of the hypotenuse is x So tan x = cos x = sin x = Using a right-angled triangle, we could define sec x as hypotenuse/adjacent, cosec x as hypotenuse/opposite and cot x as adjacent/opposite. Therefore cot x = sec x = cosec x =

5 Problems involving reciprocal trig functions
Given that cos B = is an obtuse angle . Find cot B. Making use of the identity : We chose the –ve square root because the angle is obtuse and the graph is negative between 90 and 180. Using a right-angled triangle, we could define sec x as hypotenuse/adjacent, cosec x as hypotenuse/opposite and cot x as adjacent/opposite.

6 Problems involving reciprocal trig functions
Given that cos B = is an obtuse angle . Find cot B. Draw a right-angled triangle with cos B = : The missing length is B So tan B = Therefore Using a right-angled triangle, we could define sec x as hypotenuse/adjacent, cosec x as hypotenuse/opposite and cot x as adjacent/opposite. cot B =

7 On W/b – choose your favoured method
Given that x is an acute angle and cos x = find the exact values of sec x, cosec x and cot x Using a right-angled triangle, we could define sec x as hypotenuse/adjacent, cosec x as hypotenuse/opposite and cot x as adjacent/opposite. cosec x = sec x = cot x = Do Exercise B, page 57,qu 9 & 10

8 On W/b – choose your favoured method
Given that x is an obtuse angle and cos x = find the exact values of sec x, cosec x and cot x Using a right-angled triangle, we could define sec x as hypotenuse/adjacent, cosec x as hypotenuse/opposite and cot x as adjacent/opposite. cosec x = sec x = cot x = Do Exercise B, page 57,qu 9 & 10

9 Problems involving reciprocal trig functions
Trig match puzzle Prove that At home do Exercise B, qu’s 5,6 & 7 Using sin2x + cos2x = 1 Explain that this identity can be proved by rearranging the left-hand side (LHS) to give the right-hand side (RHS).


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