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ACIDS and BASES Operational ACIDS BASES Sour Electrolyte – makes ions

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Presentation on theme: "ACIDS and BASES Operational ACIDS BASES Sour Electrolyte – makes ions"— Presentation transcript:

1 ACIDS and BASES Operational ACIDS BASES Sour Electrolyte – makes ions
in solutions Perform single replacement Rxns: Table J Any metal above H2 will react with an acid to produce H2(g) Where found –Table K Bitter Electrolyte – makes ions in solutions Referred to as caustic alkaline “Feel slippery” Where found –Table L Operational (properties) List: HI, HBr, HCl, H2SO4, HNO3 Any group 1 metal bound to OH- NaOH, KOH, LiOH Strong

2 “D” INDICATORS: ACIDS BASES Acids turn litmus RED ACID “B”
Bases turn litmus BLUE BASE BLUE Litmus Colorless Phenolphthalein PINK pH < 7 (below 7) [H3O+] > [OH-] pH Note: H+ = H3O+ pH > 7 (above 7) [H3O+] < [OH-] Neutral pH=7 is when [H3O+] = [OH-] H3O+ is called Hydronium ion Comes from H+ + H2O H3O+ OH- is called hydroxide ion

3 ACIDS BASES Types of Acids/Bases Produces OH- PRODUCE H+
H+: is the only positive ion in solution Ex. HCl H+ + Cl- Produces OH- OH- : is the only negative ion in solution Ex. NaOH Na+ + OH- Arrhenius Neutralization It’s when pH =7 Pure water Net ionic result : It’s also double replacement reaction Acid + Base Salt + water Hx__ + MetalOH Metal with nonmetal + water H+ + OH H2O HI + KOH KI + H2O Ionic

4 ACIDS BASES PROTON DONOR (gives an H ) PROTON ACCEPTOR
H+: is “given” to an acceptor moves from acid to base Ex. CH3COOH can give up that Might see it written HC2H3O2 PROTON ACCEPTOR H+ : is accepted by the base and makes a coordinate covalent bond Ex. NH3 + H NH4+ The NH3 is the acceptor Bronsted- Lowry Conjugate Acid/Base Pairs Appear on opposite sides of the equation (opposite sides of arrow) Differ only in an H If it’s an acid on the left side becomes the base on the right side of arrow If it’s a base on the left side becomes the acid on the right Acid/base pairs NH HSO NH SO42- B A

5 NAMING ACIDS Type of Acid How you name it Binary
2 elements In compound Hx___y Ex. H2S, HCl Always start with “hydro” Hydro____________ic acid Route name of second element Ex. HCl - hydrochloric acid H2S – hydrosulfuric acid Going backwards – hydrobromic acid - HBr Tertiary 3 or more elements In compound Hx___y___z TABLE E **NO HYDRO Look at anion ending in table E Ends in –ate, change ending to -ic acid Ex. HClO3—chlorate---becomes chloric acid Ends in –ite, change ending to –ous acid Ex. HNO2 – nitrite----becomes nitrous acid Writing formula-phosphoric acid –PO43-: H3PO4

6 NAMING BASES Type of Base How you name it Any Metal + OH- contains the
OH- ion **Name metal then add hydroxide Ex. NaOH—sodium hydroxide Ex. Ca(OH)2—calcium hydroxide Writing formula -- Magnesium Hydroxide (criss-cross) Mg2+ OH- :: Mg(OH)2 organic Not CH3OH Make sure There is a metal

7 Equilibrium constants and pH
Kw – Is the equilibrium constant for water H2O(l) + H2O(l) H3O+(aq) + OH-(aq) Kw = [H3O+][OH-] = 1.0 x @ 25ºC pH + pOH = 14 What is the hydroxide ion concentration if th hydronium ion concentration is 1.0 x 10-5M? 1.0 x 10-5M[OH-] = 1.0 x 10-14 [OH-] = 1.0 x 10-14 1.0 x 10-5 = 1.0 x 10-9 Determining pH – always use concentration of H+ ion pH= -log[H+] Another way to look at it [H+] = 1.0 x 10 -pH The numerical value of exponent = value of pH pH is a log scale. Each number change is a 10 fold change (factor of 10) 1 14 Acid Base 7 Neutral H+ OH- As you go H+ decrease, OH- increase, pH increase As you go H+ increase, OH- decrease, pH decreases If the pH changes from 4 to 8, what is the change in H+ concentration 4 to 5 to 6 to 7 to 8 10 10x10x10x10=10,000 fold change DECREASE in H+

8 Practice problems What is the pH of 1.0 x 10-3 M solution of NaOH?
What is the pH of 1.0 x 10-3 M solution of HCl? HCl – is an acid so = [H+] [H+] = 1.0 x 10-3 pH = 3 What is the pH of 1.0 x 10-3 M solution of NaOH? NaOH – is a base so = [OH-] Concentration of [OH-][H+]=1x10-14 [H+] = 1 x 10-11 pH = 11 What is the pH of M solution of HCl? M = 1 x 10-5 =[H+] pH = 5 What is the pH of M solution of NaOH? NaOH – is a base so = [OH-] Concentration of [OH-][H+]=1x10-14 [H+] = 1 x 10-11 pH = 11 NaOH = 1x10-3

9 TITRATION Use of a known solution to calculate the concentration of an unknown solution Buret USE TITRATION FORMULA MAVA = MBVB VB Solution Of base. We find MB How much base used will Equal how many moles Acid is there. If 50 mL of 0.5M HCl is used to completely neutralize 25 mL of KOH, what is the molarity of the base? MAVA = MBVB (0.5M)(50mL) = MB(25mL) 1.0 M = MB Solution of known concentration With a known volume, VA known MA Moles H+ = moles OH- Phenol (indicator) Place the indicator in the unknown solution When it changes color you’ve reached the equivalence pnt - you have neutralized it!

10 OTHER Indicators – TABLE M
Below the 1st # - 1st color listed Above the 2nd # - 2nd color listed Between the #’s on the chart – will be a blend of the colors Ex. A solutions pH = 5.8 then In methyl orange – color would be yellow In bromthymol blue – color would be yellow In litmus – color would be a reddish-purple (in middle)


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