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Chapter 4 Aqueous Reactions and Solution Stoichiometry

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1 Chapter 4 Aqueous Reactions and Solution Stoichiometry
CHEMISTRY The Central Science 9th Edition Chapter 4 Aqueous Reactions and Solution Stoichiometry David P. White Prentice Hall © 2003 Chapter 4

2 General Properties of Aqueous Solutions
Electrolytic Properties Aqueous solutions, solutions in water, have the potential to conduct electricity. The ability of the solution to conduct depends on the number of ions in solution. There are three types of solution: Strong electrolytes, Weak electrolytes, and Nonelectrolytes. Prentice Hall © 2003 Chapter 4

3 General Properties of Aqueous Solutions
Electrolytic Properties Prentice Hall © 2003 Chapter 4

4 General Properties of Aqueous Solutions
Ionic Compounds in Water Ions dissociate in water. In solution, each ion is surrounded by water molecules. Transport of ions through solution causes flow of current. Prentice Hall © 2003 Chapter 4

5 General Properties of Aqueous Solutions
Molecular Compounds in Water Molecular compounds in water (e.g., CH3OH): no ions are formed. If there are no ions in solution, there is nothing to transport electric charge. Prentice Hall © 2003 Chapter 4

6 General Properties of Aqueous Solutions
Strong and Weak Electrolytes Strong electrolytes: completely dissociate in solution. For example: Weak electrolytes: produce a small concentration of ions when they dissolve. These ions exist in equilibrium with the unionized substance. Prentice Hall © 2003 Chapter 4

7 Precipitation Reactions
When two solutions are mixed and a solid is formed, the solid is called a precipitate. Prentice Hall © 2003 Chapter 4

8 Precipitation Reactions

9 Precipitation Reactions
Exchange (Metathesis) Reactions Metathesis reactions involve swapping ions in solution: AX + BY  AY + BX. Metathesis reactions will lead to a change in solution if one of three things occurs: an insoluble solid is formed (precipitate), weak or nonelectrolytes are formed, or an insoluble gas is formed. Prentice Hall © 2003 Chapter 4

10 Precipitation Reactions
Ionic Equations Ionic equation: used to highlight reaction between ions. Molecular equation: all species listed as molecules: HCl(aq) + NaOH(aq)  H2O(l) + NaCl(aq) Complete ionic equation: lists all ions: H+(aq) + Cl-(aq) + Na+(aq) + OH-(aq)  H2O(l) + Na+(aq) + Cl-(aq) Net ionic equation: lists only unique ions: H+(aq) + OH-(aq)  H2O(l) Prentice Hall © 2003 Chapter 4

11 Acid-Base Reactions Acids
Dissociation = pre-formed ions in solid move apart in solution. Ionization = neutral substance forms ions in solution. Acid = substances that ionize to form H+ in solution (e.g. HCl, HNO3, CH3CO2H, lemon, lime, vitamin C). Acids with one acidic proton are called monoprotic (e.g., HCl). Acids with two acidic protons are called diprotic (e.g., H2SO4). Acids with many acidic protons are called polyprotic. Prentice Hall © 2003 Chapter 4

12 Acid-Base Reactions Bases
Bases = substances that react with the H+ ions formed by acids (e.g. NH3, Drano™, Milk of Magnesia™). Prentice Hall © 2003 Chapter 4

13 Acid-Base Reactions Strong and Weak Acids and Bases
Strong acids and bases are strong electrolytes. They are completely ionized in solution. Weak acids and bases are weak electrolytes. They are partially ionized in solution. Prentice Hall © 2003 Chapter 4

14 Acid-Base Reactions Identifying Strong and Weak Electrolytes
Water soluble and ionic = strong electrolyte (probably). Water soluble and not ionic, but is a strong acid (or base) = strong electrolyte. Water soluble and not ionic, and is a weak acid or base = weak electrolyte. Otherwise, the compound is probably a nonelectrolyte. Prentice Hall © 2003 Chapter 4

15 Acid-Base Reactions Identifying Strong and Weak Electrolytes
Prentice Hall © 2003 Chapter 4

16 HCl(aq) + NaOH(aq)  H2O(l) + NaCl(aq)
Acid-Base Reactions Neutralization Reactions and Salts Neutralization occurs when a solution of an acid and a base are mixed: HCl(aq) + NaOH(aq)  H2O(l) + NaCl(aq) Notice we form a salt (NaCl) and water. Salt = ionic compound whose cation comes from a base and anion from an acid. Neutralization between acid and metal hydroxide produces water and a salt. Prentice Hall © 2003 Chapter 4

17 Acid-Base Reactions Acid-Base Reactions with Gas Formation
Sulfide and carbonate ions can react with H+ in a similar way to OH-. 2HCl(aq) + Na2S(aq)  H2S(g) + 2NaCl(aq) 2H+(aq) + S2-(aq)  H2S(g) HCl(aq) + NaHCO3(aq)  NaCl(aq) + H2O(l) + CO2(g) Prentice Hall © 2003 Chapter 4

18 Oxidation-Reduction Reactions
Oxidation and Reduction When a metal undergoes corrosion it loses electrons to form cations: Ca(s) +2H+(aq)  Ca2+(aq) + H2(g) Oxidized: atom, molecule, or ion becomes more positively charged. Oxidation is the loss of electrons. Reduced: atom, molecule, or ion becomes less positively charged. Reduction is the gain of electrons. Prentice Hall © 2003 Chapter 4

19 Oxidation-Reduction Reactions
Oxidation and Reduction Prentice Hall © 2003 Chapter 4

20 Oxidation-Reduction Reactions
Oxidation and Reduction

21 Oxidation-Reduction Reactions
Oxidation Numbers Oxidation number for an ion: the charge on the ion. Oxidation number for an atom: the hypothetical charge that atom would have if it was an ion. Oxidation numbers are assigned by a series of rules: If the atom is in its elemental form, the oxidation number is zero. E.g., Cl2, H2, P4. For a monoatomic ion, the charge on the ion is the oxidation state. Prentice Hall © 2003 Chapter 4

22 Oxidation-Reduction Reactions
Oxidation Numbers Nonmetal usually have negative oxidation numbers: Oxidation number of O is usually –2. The peroxide ion, O22-, has oxygen with an oxidation number of –1. Oxidation number of H is +1 when bonded to nonmetals and –1 when bonded to metals. The oxidation number of F is –1. The sum of the oxidation numbers for the atom is the charge on the molecule (zero for a neutral molecule). Prentice Hall © 2003 Chapter 4

23 Oxidation-Reduction Reactions
Oxidation of Metals by Acids and Salts Metals are oxidized by acids to form salts: Mg(s) +2HCl(aq)  MgCl2(aq) + H2(g) During the reaction, 2H+(aq) is reduced to H2(g). Metals can also be oxidized by other salts: Fe(s) +Ni2+(aq)  Fe2+(aq) + Ni(s) Notice that the Fe is oxidized to Fe2+ and the Ni2+ is reduced to Ni. Prentice Hall © 2003 Chapter 4

24 Oxidation-Reduction Reactions
Activity Series Some metals are easily oxidized whereas others are not. Activity series: a list of metals arranged in decreasing ease of oxidation. The higher the metal on the activity series, the more active that metal. Any metal can be oxidized by the ions of elements below it. Prentice Hall © 2003 Chapter 4

25

26 Concentrations of Solutions
Molarity Solution = solute dissolved in solvent. Solute: present in smallest amount. Water as solvent = aqueous solutions. Change concentration by using different amounts of solute and solvent. Molarity: Moles of solute per liter of solution. If we know: molarity and liters of solution, we can calculate moles (and mass) of solute. Prentice Hall © 2003 Chapter 4

27 Concentrations of Solutions
Molarity Prentice Hall © 2003 Chapter 4

28 Concentrations of Solutions
Dilution We recognize that the number of moles are the same in dilute and concentrated solutions. So: MdiluteVdilute = moles = MconcentratedVconcentrated Prentice Hall © 2003 Chapter 4

29 Solution Stoichiometry and Chemical Analysis
There are two different types of units: laboratory units (macroscopic units: measure in lab); chemical units (microscopic units: relate to moles). Always convert the laboratory units into chemical units first. Grams are converted to moles using molar mass. Volume or molarity are converted into moles using M = mol/L. Use the stoichiometric coefficients to move between reactants and product. Prentice Hall © 2003 Chapter 4

30 Solution Stoichiometry and Chemical Analysis
Prentice Hall © 2003 Chapter 4

31 Solution Stoichiometry and Chemical Analysis
Titrations

32 Solution Stoichiometry and Chemical Analysis
Titrations Suppose we know the molarity of a NaOH solution and we want to find the molarity of an HCl solution. We know: molarity of NaOH, volume of HCl. What do we want? Molarity of HCl. What do we do? Take a known volume of the HCl solution, measure the mL of NaOH required to react completely with the HCl. Prentice Hall © 2003 Chapter 4

33 Solution Stoichiometry and Chemical Analysis
Titrations What do we get? Volume of NaOH. We know molarity of the NaOH, we can calculate moles of NaOH. Next step? We also know HCl + NaOH  NaCl + H2O. Therefore, we know moles of HCl. Can we finish? Knowing mol(HCl) and volume of HCl (20.0 mL above), we can calculate the molarity. Prentice Hall © 2003 Chapter 4

34 End of Chapter 4: Aqueous Reactions and Solution Stoichiometry
Prentice Hall © 2003 Chapter 4


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