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Please put your name at the top of the whiteboard and sketch these axes v t.

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Presentation on theme: "Please put your name at the top of the whiteboard and sketch these axes v t."— Presentation transcript:

1 Please put your name at the top of the whiteboard and sketch these axes
v t

2 A student enters college at the main entrance, walks to the physics room, then returns a book to the library, then goes to see a friend at the refectory. She then leaves college by the main entrance. Just considering the vertical movement… on the top set of axes, sketch the corresponding displacement-time graph on the bottom set of axes, sketch a velocity-time graph for her time in college, taking upwards as the positive direction. (Remember the gradient of the s/t graph is the value of the v/t graph)

3 Sketch these axes on your whiteboard
v t

4 Summary from last week s
The gradient of the s/t graph gives you the velocity The area under the v/t graph gives you the displacement v t The gradient of the v/t graph gives you the acceleration The area under the a/t graph gives you the velocity a t

5 I will collect in those that have only just completed them
Have a look at your homework sheets, we’re going to check the mark scheme I will collect in those that have only just completed them

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9 aims Build on our knowledge of graphs of motion
Know the meaning of the symbols Use equations for uniform acceleration Link these two areas of knowledge

10 Motion along a straight line with constant (uniform) acceleration
Initial velocity, u Final velocity, v Acceleration, a = constant displacement, s time, t

11 Motion along a straight line with constant (uniform) acceleration
Velocity v v-u u On your whiteboard, rearrange this equation to make v the subject: v = t Equation 1 Time

12 Motion along a straight line with constant (uniform) acceleration
Velocity Area under graph = displacement Displacement = area of trapezium = average height x base = average velocity x time = (u + v) t v 2 u Equation 2 t Time

13 Motion along a straight line with constant (uniform) acceleration
Area under graph = displacement Velocity v v-u u Equation 3 t

14 Motion along a straight line with constant (uniform) acceleration
For those who like a mathematical challenge: Rearrange equation 1 to make t the subject Use this to eliminate t from equation 2 Simplify and rearrange to make v2 the subject Equation 4

15 Summary – write this bit down
The equations of motion for: Motion along a straight line with constant (uniform) acceleration s = displacement (m) u = initial velocity (ms-1) v = final velocity (ms-1) a = acceleration (ms-2) t = time (s)

16 Which equation? Use this method: Write down the 5 symbols
1) An object travelling at 15ms-1 accelerates at 3 ms-2 for 5 seconds. Calculate its final velocity its displacement Which equation? Use this method: Write down the 5 symbols Fill in the 3 values given Put ‘?’ by the one you are asked for Select the equation that doesn’t have the blank symbol You may need to rearrange the equation s = u v a t 15 ms-1 3 ms-2 5 s ?

17 1) An object travelling at 15ms-1 accelerates at 3 ms-2 for 5 seconds.
Calculate its final velocity its displacement a) s = m u ms-1 v a ms-2 t 112.5 15 30 ? b) 3 5

18 (a) distance travelled in first 7 seconds
Equations of Motion Questions Remember that you can only apply suvat when the acceleration is constant. You may need to split problems in to parts. 2) A car travels in a straight line at 25ms-1 for 7 seconds then slows to a stop at a constant rate in 5 seconds. Calculate (a) distance travelled in first 7 seconds (b) its acceleration during the last 5 seconds (c) the total distance travelled. 3) An arrow accelerates from rest at 300ms-2 through a distance of 0.5m. It then flies at steady speed 20m to a target. Calculate the total time from rest until hitting the target.

19 (a) distance travelled in first 7 seconds
2) A car travels at 25ms-1 for 7 seconds then slows to a halt in 5 seconds. Calculate (a) distance travelled in first 7 seconds (b) its acceleration during the last 5 seconds (c) the total distance travelled. Part b s = m u = ms-1 v = a = ? ms-2 t = Motion is in two parts: velocity/ms-1 time/s 25 7 12 a) b)

20 (a) distance travelled in first 7 seconds
2) A car travels at 25ms-1 for 7 seconds then slows to a halt in 5 seconds. Calculate (a) distance travelled in first 7 seconds (b) its acceleration during the last 5 seconds (c) the total distance travelled. a) s = 175m Part c Add distances from a) and c) : total distance = 237.5m

21 3) An arrow accelerates from rest at 300ms-2 through a distance of 0
3) An arrow accelerates from rest at 300ms-2 through a distance of 0.5m. It then flies at steady speed 20m to a target. Calculate the total time from rest until hitting the target. Motion is in two parts, the first part the arrow is accelerating and the second part the arrow is at a constant speed. Find the time for the first part s = m u = ms-1 v = a = ms-2 t = ?

22 3) An arrow accelerates from rest at 300ms-2 through a distance of 0
3) An arrow accelerates from rest at 300ms-2 through a distance of 0.5m. It then flies at steady speed 20m to a target. Calculate the total time from rest until hitting the target. Motion is in two parts, the first part the arrow is accelerating and the second part the arrow is at a constant speed. Find the final velocity to find the value for constant speed for the second part s = m u = ms-1 v = ? a = ms-2 t = Final velocity at end of acceleration = constant velocity in the second stage. In second (constant velocity) stage: v = s / t so t = s / v = 20/17.3 =1.156s Add the times from the 1st and 2nd part: = 1.21s (3sf)

23 Lets see how we’re all doing by trying an exam question
You have 7 minutes Please work on your own for this BUT Don’t panic, its not a test!

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25 aims Build on our knowledge of graphs of motion
Know the meaning of the symbols Use equations for uniform acceleration Link these two areas of knowledge

26 June 2002

27 This is called “freefall”, more on this next week!
Last question An object falls from rest through a distance of 3m with a constant acceleration of 9.81ms-2 downwards. Calculate its final velocity (b) the time taken We don’t really need this bit as all objects released near the earth will accelerate towards it at 9.81ms-2. This is called “freefall”, more on this next week! 7.7ms-1 0.78s

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29 Homework Will be e-mailed out once a week
Will be split into two sets of tasks, one for each teacher Will make clear when the tasks will be checked next week Support available Thursday and Friday at lunchtimes Next time – freefall and projectiles


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