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Section 7.3: Probability Distributions for Continuous Random Variables

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1 Section 7.3: Probability Distributions for Continuous Random Variables

2 A probability distribution for a continuous random variable x – is specified by a mathematical function denoted by f(x) and called the density function. The graph of a density function is a smooth curve (the density curve). The following requirements must be met:

3 f(x) ≥ 0 (so that the curve cannot dip below the horizontal axis).
The total area under the density curve is equal to 1. The probability that x falls in any particular interval is the area under the density curve and above the interval.

4 Many probability calculations involve the following three events:
a < x < b, the event that the random variable x assumes a value between two given numbers a and b. x < a, the event that the random variable x assumes a value less than a given number a b < x, the event that the random variable x assumes a value greater than a given number b (this can also be x > b)

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6 Example Define a continuous random variable x by
x = amount of time (in minutes) taken by a clerk to process a certain type of application form. Suppose that x has a probability distribution with density function

7 The graph of f(x), the density curve, is shown on the next slide
The graph of f(x), the density curve, is shown on the next slide. It is especially easy to use this density curve to calculate probabilities, because it just requires finding the area of rectangles using the formula Area = (base)(height)

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9 The curve has positive height, 0. 5, only between x = 4 and x = 6
The curve has positive height, 0.5, only between x = 4 and x = 6. The total area under the curve is just the area of the rectangle with base extending from 4 to 6 and with height 0.5. This gives Area = (6 – 4)(0.5) = 1

10 When the density is constant over an interval (resulting in a horizontal density curve), the probability distribution is called a uniform distribution.

11 The probability that x is between 4.5 and 5.5 is
Area = (5.5 – 4.5)(0.5) = .5 The probability that x > 5.5 Area = (6 – 5.5)(0.5) = .25

12 For any two numbers a and b with a < b,
P(a ≤ x ≤ b)=P(a < x ≤ b)=P(a ≤ x < b)=P(a < x < b) when x is a continuous random variable. The probability that a continuous random variable x lies between a lower limit a and an upper limit b is P(a < x < b) = (cumulative area to the left of b) – (cumulative area to the left of a) = P(x < b) – P(x < a)

13 Section 7.4: Mean and Standard Deviation of a Random Variable

14 The mean value of a random variable x; denoted by μx, describes where the probability distribution of x is centered. The standard deviation of a random variable x, denoted by σx, describes variability in the probability distribution. When σx is small, observed values of x tend to be close to the mean value (little variability). When the value of σx is large, there is more variability in observed x values.

15 Mean value of a discrete random variable x – denoted by μx, is computed by first multiplying each possible x value by the probability of observing that value and then adding the resulting quantities. Symbolically, μx = ∑ (x)p(x) The term expected value is sometimes used in place of mean value, and E(x) is alternative notation for μx.

16 Example Individuals applying for a certain license are allowed up to four attempts to pass the licensing exam. Let x denote the number of attempts made by a randomly selected applicant. The probability distribution of x is as follows:

17 x p(x) Thus x has mean value μx = ∑ (x)p(x) = 1(.10) + 2(.20) + 3(.30) + 4(.40) = = 3.00

18 Example A television manufacturer receives certain components in lots of four from two different suppliers. Let x and y denote the number of defective components in randomly selected lots from the first and second suppliers, respectively. The probability distributions for x and y are as follows:

19 x y p(x) p(y) Probability histograms for x and y are given below:

20 Variance of a discrete random variable x – denoted by σ2x, is computed by first subtracting the mean from each possible x value to obtain the deviations, then squaring each deviation and multiplying the result by the probability of the corresponding x value, and finally adding these quantities. Symbolically, σ2x = ∑ (x – μ)2p(x) The standard deviation of x, denoted by σx, is the square root of the variance

21 Example From the previous example we know that μ = 1
For x = number of defective components in a lot from the first supplier

22 For y = the number of defective components in a lot from the second supplier.

23 Mean, Variance, and Standard Deviation of a Linear Function

24 If x1, x2,  , xn are random variables and a1, a2,  , an are numerical constants, the random variable y defined as y = a1x1 + a2x2 +  + anxn is a linear combination of the xi’s.

25 Mean, Variance, and Standard Deviation for Linear Combinations
If x1, x2, …, xn are random variables with means μ1, μ2,…,μn and variances σ21, σ22,…,σ2n, respectively, and if y = a1x1 + a2x2 +…+ anxn,, then


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