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Example 1 Factor ax2 + bx + c

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1 Example 1 Factor ax2 + bx + c
Example 2 Factor When a, b, and c Have a Common Factor Example 3 Determine Whether a Polynomial Is Prime Example 4 Solve Equations by Factoring Lesson 4 Contents

2 Example 1 Factor ax2 + bx + c

3 Step 1: Draw a box with 9 squares
Factor In order to factor a trinomial with an “a” value we will use a technique called the factor box. Step 1: Draw a box with 9 squares Step 2: Place the first term in the top left box. 5x2 10 Step 3: Place the third term in the top middle box. Example 4-1a

4 Step 5: Place the middle term outside the box at the right.
Factor In a factor box, the left box times the middle box will equal the right box. Step 4: 5x2 x 10 = 50x2 Step 5: Place the middle term outside the box at the right. Step 6: Find the factors of 50x2 that add to 27x. 5x2 10 50x2 27x Example 4-1a

5 Factor Step 7: Place the 2 terms that multiply to be 50x2 and add to be 27x in the far right boxes. 5x2 10 50x2 27x 2x 25x Example 4-1a

6 What can I multiply to get 2x?
Factor Before looking at the 4 remaining boxes, remember the rules we have learned thus far: ) you multiply from left to right and the product is in the far right box ) you multiply from bottom to top and the result is in the top box. Ask yourself: What can I multiply to get 2x? What can I multiply to get 25x? As you are figuring that out, you also have to figure out how to multiply those factors going up to obtain 5x2 and 10. Example 4-1a

7 Factor Step 8: Place the 2 terms that multiply to be 2x in the top 2 remaining boxes. Step 9: Place the 2 terms that multiply to be 25x in the bottom 2 remaining boxes. 5x2 10 50x2 27x 2x 25x x 2 5x 5 Example 4-1a

8 Vertical Check: Does x times 5x equal 5x2?
Factor Vertical Check: Does x times 5x equal 5x2? Does 5 x 2 = 10? 5x2 27x x 5x 10 2 5 Example 4-1a

9 Factor Horizontal Check: Does x times 2 equal 2x? Does 5x times 5 = 25x? 27x x 2 2x 5x 5 25x Once everything checks out, you are ready to identify your final answer. Example 4-1a

10 Factor Your factors are in blue. Circle them diagonally. If there is no sign it is understood to be addition. 27x x 2 2x 5x 5 25x 5x2 10 50x2 Answer: (x + 5)(5x + 2) Example 4-1a

11 Factor 26x 3x2 35 105x2 x 5 3x 7 5x 21x Answer: Example 4-1a

12 Factor Look for the factors of 72x2 (24x2 times 3) that add to be -22x. –73 –38 –27 –22 –1, –72 –2, –36 –4, –24 –4, –18 Sum of Factors Factors of 72 The correct factors are –4, –18. Example 4-1b

13 Factor 24x2 - 22x + 3 Now place the 2 terms that multiply to be 72x2 and add to be -22x in the far right boxes. 24x2 3 72x2 -22x -4x -18x Example 4-1b

14 Factor 24x2 - 22x + 3 Next: Place the 2 terms that multiply to be -4x in the top 2 remaining boxes. Then: Place the 2 terms that multiply to be -18x in the bottom 2 remaining boxes. 24x2 3 72x2 -22x -4x -18x 4x -1 6x -3 Example 4-1b

15 Factor 24x2 - 22x + 3 Your factors are in blue. Circle them diagonally. If there is no sign it is understood to be addition. -22x 4x -1 -4x 6x -3 -18x 24x2 3 72x2 Answer: (4x - 3)(6x - 1) Example 4-1b

16 a. Factor -17x 3x2 10 30x2 x -2 3x -5 -2x -15x Answer: Example 4-1b

17 b. Factor -23x 10x2 12 120x2 2x -4 5x -3 -8x -15x Answer: Example 4-1b

18 Example 2 Factor When a, b, and c Have a Common Factor

19 First factor out the common term.
4(x2 + 6x + 8) Now, factor the trinomial x2 + 6x + 8 Answer: Example 4-2a

20 First factor out the common term.
2(x2 + 7x + 10) Now, factor the trinomial x2 + 7x + 10 Answer: Example 4-2b

21 Determine Whether a Polynomial Is Prime
Example 3 Determine Whether a Polynomial Is Prime

22 Factor Look for the factors of -15x2 (3x2 times -5) that add to be 7x. 14 –14 2 –2 –1, 15 1, –15 –3, 5 3, –5 Sum of Factors Factors of –15 Example 4-3a

23 Answer: is a prime polynomial.
There are no factors whose sum is 7. Therefore, cannot be factored using integers. Answer: is a prime polynomial. Example 4-3a

24 Factor First make a table of the terms that multiply to be 9 but add to be -5. –1, -9 1, 9 –3, -3 3, 3 Sum of Factors Factors of 9 There are NO such factors so it canNOT be factored. Answer: prime Example 4-3b

25 Solve Equations by Factoring
Example 4 Solve Equations by Factoring

26 Hint: Key word SOLVE (set equation = 0)
Original equation Hint: Key word SOLVE (set equation = 0) Rewrite so one side equals 0. Hint: Use the factor box to factor! -14b 15b2 -8 -120b2 3b 2 5b -4 6b -20b Example 4-4a

27 Answer: The solution set is
Factor the left side. or Zero Product Property Solve each equation. Answer: The solution set is Example 4-4a

28 Hint: Use the factor box to factor!
Solve: 12x2 - 19x + 5 = 0 Original equation 12x2 - 19x + 5 = 0 Hint: Use the factor box to factor! -19x 12x2 5 60x2 3x -5 4x -1 -15x -4x Example 4-4b

29 Factor the left side. (3x - 1)(4x - 5) = 0 or Zero Product Property
Solve each equation. 3x = 1 4x = 5 x = 1/3 x = 5/4 Answer: Example 4-4b

30 Homework: Page even Use the factor box to assist you with factoring. Example 4-4b


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