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Gregor Mendel - A monk who studied peas in his garden and developed our basic understanding of heredity.

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Presentation on theme: "Gregor Mendel - A monk who studied peas in his garden and developed our basic understanding of heredity."— Presentation transcript:

1 Gregor Mendel - A monk who studied peas in his garden and developed our basic understanding of heredity.

2 Allele Alternate forms of a gene Most traits have 2 alleles
Ex. Mendel’s peas

3 Blue eye or brown eye allele

4 Heredity The transmission of characteristics from parents to offspring

5 Trait The visible character that shows Ex. Yellow pea or green pea

6 Genes A discrete unit of hereditary information located on a chromosome

7 Generations P1 Generation – The original parents
F1 Generation – The first offspring (Children) F2 Generation – The offspring from the F1 gen. (grandchildren)

8 Law of segregation When gametes (sperm and egg) form, only one of the 2 possible genes for each trait will be in each gamete

9 Dominant vs. Recessive Dominant – The trait that is stronger or masks the other trait Recessive – The trait that is weaker or hidden

10                                                    Dominant gene Black fur is dominant to white

11 If there are both a dominant and recessive traits together, only the dominant one appears

12 G g Genotype The genes an organism carries
Ex: Gg = green (G) and yellow (g) genes G g

13 Phenotype How the genes are expressed (what it looks like)
Ex: Gg has both green and yellow genes but the phenotype is green because green is dominant

14 G Homozygous Dominant Both Dominant Genes Present Genotype = GG
Phenotype = Green GG G G

15 g Gg G Heterozygous 1 Dominant gene, 1 recessive gene present
Genotype = Gg Phenotype = Green g Gg G

16 gg g g Homozygous Recessive Both recessive Genes Present Genotype = gg
Phenotype = Yellow gg g g

17 Monohybrid cross Look at one single character

18 If we know the alleles of the parents, we can make predictions about the genetic traits of the offspring using A PUNNETT SQUARE! Draw a Punnett square Label 1 side with the genotype of one parent. Label the other side with the genotype of the other parent. Do the cross Describe genotypes including the possible percentages for the offspring Describe the phenotypes including the possible percentages for the offspring

19 Punnett Square Practice
1. Curly hair (H) is dominant to straight hair (h). Draw a punnett square crossing a heterozygous male (Hh) with a heterozygous female (Hh). Name all possible gentoypes and phenotypes and the percentages. H H H h h h Genotypes: HH: Hh: hh: Phenotypes: Curly: Straight: H h H H h h

20 Punnett Square Practice
2. Dimples (D) are dominant to not having dimples (d). Draw a punnett square crossing a homozygous dominant female (DD) with a homozygous recessive male (dd). Name all possible genotypes and phenotypes and the percentages. d d d d d d Genotypes: DD: Dd: dd: Phenotypes: Dimples: No Dimples: D D D D D D

21 Punnett Square Practice
3. Unattached earlobes (E) are dominant to attached earlobes (e). Draw a punnett square crossing a homozygous recessive female with a heterozygous male. Name all possible genotypes and phenotypes and percentages. e e Genotypes: EE: Ee: ee: Phenotypes: Attached: Unattached: E e Ee Ee ee ee

22 Punnett Square Practice
4. Having freckles (F) is dominant to not having freckles (f). Draw a Punnett square crossing a heterozygous female with a homozygous dominant male. Name all possible genotypes and phenotypes and percentages. F f Genotypes: FF: 50% Ff: 50% PhenotypesFreckles: 100% F F FF Ff

23 Punnett Square Practice
i i 5. Immunity to poison ivy is dominant to being susceptible to getting poison ivy. Draw a punnett square crossing a homozygous recessive female with a homozygous dominant male. Name all possible genotypes and phenotypes and percentages. Genotypes: Ii: 100% PhenotypesImmunity: 100% I I Ii Ii

24 Punnett Square Practice
6. A widow’s peak is dominant to a normal hairline. Draw a punnett square crossing a heterozygous female with a heterozygous male. Name all possible genotypes and phenotypes and percentages. W w Genotypes: WW: 25% Ww: 50% ww: 25% PhenotypesImmunity: Widows peak: 75% Normal: 25% W w WW Ww Ww ww

25 Cases in Genetics with Filbert the Frog and Friends

26 Dihybrid Punnett Squares
S: smooth s: rough Y: yellow y: green Dihybrid Punnett Squares Genotypes: Phenotypes: SSYY: 1/16 SSYy: 2/16 SSyy: 1/16 SsYY: 2/16 SsYy: 4/16 Ssyy: 2/16 ssYY: 1/ 16 ssYy: 2/16 ssyy: 1/16 Smooth Yellow: 9/16 Rough Yellow: 3/16 Smooth green: 3/16 Rough green: 1/16

27 Now try to make one… Genotypes: Phenotypes: BBSS: 1/16 BBSs: 2/16
B = black fur b = brown fur S = short fur s = long fur Now try to make one… Genotypes: Phenotypes: BBSS: 1/16 BBSs: 2/16 BBss: 1/16 BbSS: 2/16 BbSs: 4/16 Bbss: 2/16 bbSS: 1/16 bbSs: 2/16 bbss: 1/16 BBSS BBSs BbSS BbSs BBSs BBss BbSs Bbss BbSS BbSs bbSS bbSs BbSs Bbss bbSs bbss Black, Short: 9/16 Brown, Short: 3/16 Black, Long: 3/16 Brown, Long: : 1/16

28 Try this one: BBSs vs. bbSs
B = black fur b = brown fur S = short fur s = long fur Try this one: BBSs vs. bbSs Genotypes: Phenotypes:

29 BBSs vs. bbSs BS Bs bS bs

30 Try this one: BBSs vs. bbSs
B = black fur b = brown fur S = short fur s = long fur Try this one: BBSs vs. bbSs Genotypes: Phenotypes: bS bs bS bs BbSS: 4/16 BbSs: 8/16 Bbss: 4/16 BS Bs BbSS BbSs BbSS BbSs BbSs Bbss BbSs Bbss BbSS BbSs BbSS BbSs Black, Short: 12/16 Black, long: 4/16

31 Homework: Complete a dihybrid punnett square using this cross: TtRR x TTrr. Tall (T) is dominant to short (t) and Red (R) is dominant to pink (r). Find the genotype and phenotype percentages.


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