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Universal Gravitation

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Presentation on theme: "Universal Gravitation"— Presentation transcript:

1 Universal Gravitation

2 What do we know about gravity so far?
Turn to your neighbor and share your knowledge of gravity from this class and other experiences.

3 Inverse Square Law The force of gravity between the earth and any object is inversely proportional to the square of the distance that separates the object’s center from the earth’s center. Fgrav~1/d2 Fgrav represents the force of gravity between the two objects. How are force and distance related? What happens if distance is doubled? What happens if distance is halved?

4 Practice Question Suppose that two objects attract each other with a gravitational force of 16 units. If the distance between the two objects is doubled, what is the new force of attraction between the two object? 4

5 Plicker Question Suppose that two objects attract each other with a gravitational force of 16 units. If the distance between the two objects is tripled, what is the new force of attraction between the two object? A Units B Units C Units D. 4 Units 1.77 (/9)

6 Plicker Question Suppose that two objects attract each other with a gravitational force of 16 units. If the distance between the two objects is halved, what is the new force of attraction between the two object? A. 8 Units B. 64 Units C Units D. 4 Units 64

7 Plicker Question Suppose that two objects attract each other with a gravitational force of 16 units. If the distance between the two objects is reduced by a factor of 5, what is the new force of attraction between the two object? A. 3.2 Units B Units C. 25 Units D Units 400

8 Newton’s Law of Universal Gravitation
All objects attract each other with a force of gravitational attraction. Gravity is universal. This force of gravitational attraction is directly dependent upon the masses of both objects and is inversely proportional to the square of the distance that separates their centers. Fgrav = m1m2/d2 Fgrav represents the force of gravity between objects mx represents the mass of each object d represents the distance separating the objects Talk with you neighbor how does mass impact gravitational force between objects?

9 Universal Gravitation Constant (G)
G= x Nm2/kg2 When G is multiplied by Newton’s Universal Gravitation Equation units = N Therefore Fgrav = G×m1×m2/d2 Plicker Question: The more massive that an object is, the ______ that the object will be attracted to Earth. More B. Less C. Nonsense! Plicker Question: The more the Earth is, the ______ that the object will be attracted to Earth. Plicker Question: The the greater the earth’s radius, the ______ that the object will be attracted to Earth. more

10 Practice Problem Determine the force of gravitational attraction between the earth (m=5.98 x 1024 kg) and a 70 kg physics student standing at sea level 6.38 x 106m from the earth’s center. 686N

11 Plicker Problem Determine the force of gravitational attraction between the earth (m=5.98 x 1024 kg) and a 70 kg physics student in a plane 4000 m from the earth’s surface (which is 6.38 x 106 m from the earth’s center). A. 864N B. 6.6 x 1012 C. 2.6 x 1016 D. 9.3 x 1017 684N

12 Short Cut Determine the force of gravitational attraction between the earth (m=5.98 x 1024 kg) and a 70 kg physics student in a plane m from the earth’s surface (which is 6.38 x 106 m from the earth’s center). Based on our answers a change of only 10000m from the center of the earth is negligible. Therefore Fgrav = m x g = 70 x 9.8 = 686N

13 Practice Calculations

14 Cavendish Experiment Experimentally determined the Universal Gravitation Constant (G= 6.673x10-11) The small value reflects that it is only substantial for objects with large mass. Cavendish was able to use the torsion balance to determine G with measured values of m1, m2, d, and Fgrav

15 Calculating g g represents the acceleration of gravity
g varies inversely with the distance from the center of the earth. It follows the inverse square law. To find the acceleration of gravity on the surface of other planets g= G x mplanet/Rplanet2 We can prove g on earth’s surface is 9.8 9.8=(6.673 x 10-11) x (5.98 x 1024) / (6.38 x 106)2

16 Practice Problems YAY!


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