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M N O P R Q 1. How do you know that N R? ANSWER Third s Thm. 2. Write a triangle congruence statement. ANSWER ∆MNO ∆PRQ
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3. Find x. (7x – 50)º (2x + 10)º (3x)º ANSWER 30
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Proving triangles congruent.
Target Proving triangles congruent. GOAL: 4.4 Use side lengths to prove triangles congruent.
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Vocabulary SSS (Side-Side-Side) Congruence Postulate If three sides of one triangle are congruent to three sides of a second triangle, then the two triangles are congruent.
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EXAMPLE 1 Use the SSS Congruence Postulate Write a paragraph proof. GIVEN KL NL, KM NM PROVE KLM NLM Proof It is given that KL NL and KM NM By the Reflexive Property, LM LM. So, by the SSS Congruence Postulate, KLM NLM
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GUIDED PRACTICE for Example 1 Decide whether the congruence statement is true. Explain your reasoning. DFG HJK SOLUTION If three sides of one triangle are congruent to three sides of second triangle then the two triangle are congruent. Side DG HK, Side DF JH, and Side FG JK. So by the SSS Congruence postulate, DFG HJK. Yes. The statement is true.
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GUIDED PRACTICE for Example 1 Decide whether the congruence statement is true. Explain your reasoning. 2. ACB CAD SOLUTION BC AD GIVEN : PROVE : ACB CAD PROOF: It is given that BC AD . By Reflexive property AC AC, but AB is not congruent CD. Therefore conditions of the hypothesis for SSS have not been met and ABC cannot be congruent to CAD because corresponding sides are not congruent.
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GUIDED PRACTICE for Example 1 Decide whether the congruence statement is true. Explain your reasoning. QPT RST 3. SOLUTION QT TR , PQ SR, PT TS GIVEN : PROVE : QPT RST PROOF: It is given that QT TR, PQ SR, PT TS. So by SSS congruence postulate, QPT RST. Yes the statement is true.
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Standardized Test Practice
EXAMPLE 2 Standardized Test Practice SOLUTION By Ruler Postulate, PQ = 4 and QR = 3. Use the Distance Formula to find PR. d = y 2 – 1 ( ) x +
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Standardized Test Practice
EXAMPLE 2 Standardized Test Practice = + 1 – 4 ( ) 2 – 1 (– 5 ) ) PR = 4 2 + (– 3 ) = 25 5 = By the SSS Congruence Postulate, any triangle with side lengths 3, 4, and 5 will be congruent to PQR. Answer A (–1, 1), (–1, 5), (–4, 5) The distance from (–1, 1) to (–1, 5) is 4. The distance from (–1, 5) to (–4, 5) is 3. The distance from (– 1, 1) to (–4, 5) is = 4 2 + (– 3 5 (–4) – (–1) ( ) 5 – 1) 25 The correct answer is A. ANSWER
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EXAMPLE 3 Solve a real-world problem Structural Support Explain why the bench with the diagonal support is stable, while the one without the support can collapse.
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EXAMPLE 3 Solve a real-world problem The bench with a diagonal support forms triangles with fixed side lengths. By the SSS Congruence Postulate, these triangles cannot change shape, so the bench is stable. The bench without a diagonal support is not stable because there are many possible quadrilaterals with the given side lengths. SOLUTION
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GUIDED PRACTICE for Example 3 Determine whether the figure is stable. Explain your reasoning. SOLUTION The figure is without a diagonal support is not stable Because there are many possible quadrilaterals with the given side lengths.
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GUIDED PRACTICE for Example 3 Determine whether the figure is stable. Explain your reasoning. SOLUTION The diagonal support forms triangle with fixed side length by SSS congruence postulate, these triangles can not change shape. The figure is stable.
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GUIDED PRACTICE for Example 3 Determine whether the figure is stable. Explain your reasoning. 7. SOLUTION The figure is not stable because the lower half of figure dies not have diagonal support.
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