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E = m Lf E = m c θ E = m Lv.

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Presentation on theme: "E = m Lf E = m c θ E = m Lv."— Presentation transcript:

1 E = m Lf E = m c θ E = m Lv

2 E = m c θ E = m c θ E = m Lf E = m c θ

3 Energy = m x Lf Energy = 10 x 340 Energy = 3,400 J Energy = m x Lf
1.a Energy = x Energy = 3,400 J Energy = m x Lf 1.b Energy = x Energy = 6,800 J

4 Energy = m x Lf Energy = 10 x 340 Energy = 3,400 J Energy = m x Lf
1.a Energy = x Energy = 3,400 J Energy = m x Lf 1.b Energy = x Energy = 6,800 J

5 Energy to melt ice = m x Lf
2.a = x = J Energy to warm up water = m x c x θ = x x = J Total energy required = J J = J

6 Energy to melt ice = m x Lf
2.a = x = J Energy to warm up water = m x c x θ = x x = J Total energy required = J J = J

7 Energy to cool water = m x c x θ
2.b = x x = ,800 J Energy change each minute = ,800 J / 10 min = ,680 J / Min

8 Energy to cool water = m x c x θ
2.b = x x = ,800 J Energy change each minute = ,800 J / 10 min = ,680 J / Min

9 Energy to melt ice = m x Lf
3. = x = ,000 J Energy transferred = power x time = W x t 34,000 J = seconds 34,000 J 50 W

10 Energy to melt ice = m x Lf
3. = x = ,000 J Energy transferred = power x time = W x t 34,000 J = seconds 34,000 J 50 W

11 Energy from cooling rivets = m x c x θ
4a. O C because the block of ice is large and will not all melt! Energy from cooling rivets = m x c x θ 4.b = x x = ,300 J Energy given to melt ice = m x Lf 4.b = m x 15,300 J = m = 45 g 15,300 J 340

12 Energy from cooling rivets = m x c x θ
4a. O C because the block of ice is large and will not all melt! Energy from cooling rivets = m x c x θ 4.b = x x = ,300 J Energy given to melt ice = m x Lf 4.b = m x 15,300 J = m = 45 g 15,300 J 340

13 Energy to change 4g water to steam = m x Lv = 4 x 2,300 = 9,200 J
5.b Energy to change 10 g steam to water = m x Lv Energy to change 10 g steam to water = x Energy to change 10 g steam to water = ,000 J Energy given out as water cools to 50 C = m x c x θ = x x Total heat given out = 23,000 J + 2,100 J = 25,100 J = 2,100 J

14 Energy to change 4g water to steam = m x Lv = 4 x 2,300 = 9,200 J
5.b Energy to change 10 g steam to water = m x Lv Energy to change 10 g steam to water = x Energy to change 10 g steam to water = ,000 J Energy given out as water cools to 50 C = m x c x θ = x x Total heat given out = 23,000 J + 2,100 J = 25,100 J = 2,100 J

15 Energy transferred = power x time
6. = ,000 W x s = ,000 J Energy to change water to steam = m x Lv 360,000 J = m x ,300 360,000 J = m = g 2,300

16 Energy transferred = power x time
6. = ,000 W x s = ,000 J Energy to change water to steam = m x Lv 360,000 J = m x ,300 360,000 J = m = g 2,300

17 Energy from cooling metal = m x c x θ
Energy from cooling metal = x x Energy from cooling metal = ,000 J Energy given to vaporize liquid = m x Lf 50, = x Lf 50, = Lf = 2,500 J/g 20

18 Energy from cooling metal = m x c x θ
Energy from cooling metal = x x Energy from cooling metal = ,000 J Energy given to vaporize liquid = m x Lf 50, = x Lf 50, = Lf = 2,500 J/g 20

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