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Published byTheodora Anthony Modified over 7 years ago
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EXAMPLE 5 Use Theorem 10.10 Find the value of each variable. a. SOLUTION PQRS is inscribed in a circle, so opposite angles are supplementary. a. m P + m R = 180o m Q + m S = 180o 75o + yo = 180o 80o + xo = 180o y = 105 x = 100
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EXAMPLE 5 Use Theorem 10.10 Find the value of each variable. b. SOLUTION b. JKLM is inscribed in a circle, so opposite angles are supplementary. m J + m L = 180o m K + m M = 180o 2ao + 2ao = 180o 4bo + 2bo = 180o 4a = 180 6b = 180 b = 30 a = 45
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GUIDED PRACTICE for Example 5 Find the value of each variable. 5. SOLUTION ABCD is inscribed in a circle, so opposite angles are supplementary. m A + m C = 180o m D+ m B = 180o 82o + xo = 180o y°+ 68o = 180o y = 112 x = 98
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GUIDED PRACTICE for Example 5 Find the value of each variable. 6. SOLUTION STUV is inscribed in a circle, so opposite angles are supplementary. m S + m U = 180o m V+ m T = 180o c°+ (2c – 6 )o = 180o 8xo + 10xo = 180o (3c)o = 186o 18xo = 180o c = 62 x = 10
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