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EXAMPLE 3 Use a geometric mean

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Presentation on theme: "EXAMPLE 3 Use a geometric mean"— Presentation transcript:

1 EXAMPLE 3 Use a geometric mean Find the value of y. Write your answer in simplest radical form. SOLUTION STEP 1 Draw the three similar triangles.

2 length of shorter leg of RQS length of shorter leg of RPQ
EXAMPLE 3 Use a geometric mean STEP 2 Write a proportion. length of hyp. of RQS length of hyp. of RPQ = length of shorter leg of RQS length of shorter leg of RPQ y 9 = 3 Substitute. 27 = y2 Cross Products Property Take the positive square root of each side. 27 = y = y Simplify.

3 EXAMPLE 4 Find a height using indirect measurement Rock Climbing Wall To find the cost of installing a rock wall in your school gymnasium, you need to find the height of the gym wall. You use a cardboard square to line up the top and bottom of the gym wall. Your friend measures the vertical distance from the ground to your eye and the distance from you to the gym wall. Approximate the height of the gym wall.

4 Find a height using indirect measurement
EXAMPLE 4 Find a height using indirect measurement SOLUTION By Theorem 7.6, you know that 8.5 is the geometric mean of w and 5. 8.5 w = 5 Write a proportion. w Solve for w. So, the height of the wall is 5 + w = 19.5 feet.

5 GUIDED PRACTICE for Examples 3 and 4 In Example 3, which theorem did you use to solve for y? Explain. SOLUTION In example 3, the theorem used was the geometric mean (leg) theorem This was used to set the ratios of the hypotenuse of the Lange triangle to the shorter leg and the hypotenuse of the small triangle to the shorter leg equal to each other

6 GUIDED PRACTICE for Examples 3 and 4 4. Mary is 5.5 feet tall. How far from the wall in Example 4 would she have to stand in order to measure its height? SOLUTION As per example 4, the height of wall is 19.5 feet Height of a Mary is 5.5 feet tall Let her stand x ft away from the wall because your new wall height w is 14.0 ft. 14.0 x 5.5 = x2 = 77 x = 8.77 ft


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