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Chapter 4 Stacks
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This is stacks A data structure in which the elements are added and removed from the top only; a Last In First Out (LIFO) data structure.
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Why People use stacks? Say you are writing a notepad application. A good use for a stack would be the undo/redo feature. Every time the user enters something, save the state (in this case, the text) on a stack and if you need to reverse something, just pop it off the top of the undo stack and push it onto the redo stack. Stacks are also used for reversing things. If you push something, say a String onto a Stack one character at a time, and then construct a String from the members popped off the Stack, then the String is reversed.
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Last In First Out B A C B A D C B A E D C B A top D C B A top top top
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Stacks Advantages Disadvantages Advantages Disadvantages Simplest one
Easy to implement Fast operation Insertion/deletion from one place Disadvantages Only can be inserted/removed from the top Problem when accessing “the one that on the top” Recursive Function
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Basic operation
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BASIC OPERATION InitializeStacks – initializes the stack to an empty state DestroyStack – removes all the elements from the state IsEmptyStack – Check the stack whether is empty or not IsFullStack – Check whether the stack is full or not
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Push and Pop PUSH – You add something at the top
POP – You remove something at the top
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Push Operation of Stacks
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Pop Operation
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Simple Example
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Let us Implement Stacks
First, as usual we need to define some maximum stack content to put our data
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Let us Implement Stacks
Then, we use Class system called “stack”
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Let us Implement Stacks
We declare a private inside “stack” class arr[MAX] : this is where we put all the data top : we assign our “leader” here.
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Let us Implement Stacks
Then, we declare public First we put some constructor. Inside this constructor I’ve put a value top = -1 to indicate that stack is empty for the first time.
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Let us Implement Stacks
Now, push operation. - We go through one by one here
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Let us Implement Stacks
1st – This is where this operation get a value which is integer type So, inside main function, we will call using “push(40)” for example So, 40 is an integer
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Let us Implement Stacks
Top++, we increment first because this is top operation, so we updates the current position from -1 to 0. (the computer always starts with “0” and not “1”. So, top is 0 right now
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Let us Implement Stacks
Then, we check whether top is still lower than MAX. If the top still lower than MAX, we continue to insert data at the position according to the top position arr[0] = 40 (recall that top = 0).
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Let us Implement Stacks
If it is not, we create a message to display “Stack Full”. Remember to set the top back to top– since we already add top++ at first line of this function.
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Example push(40) top++ top = 6 4 2 12 32 54 5 top = 6
(before this top is equal to 5, top = 5)
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Example push(40) if(top<MAX) { arr[top]=a; }
2 12 32 54 5 if(top<MAX) { arr[top]=a; } Yes, top is still lower than MAX which is 10. So, arr[6] = 40 (since we receive a = 40) top = 6
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Example push(40) else { cout<<"STACK FULL!!"<<endl; top--;
212 21 23 40 4 2 12 32 54 5 top = 9 else { cout<<"STACK FULL!!"<<endl; top--; } - But if top is equal to 10 (already full after top++), then we put message STACK FULL, and set it back to top--
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Let us Implement Stacks
Now, pop operation. We use function type integer (not void) - We go through one by one here
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Let us Implement Stacks
We check whether top is still -1(empty) - We return NULL is we still do some pop() at the main function
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Let us Implement Stacks
If it is not We give any topmost data inside arr[top] to local variable int data Then, we set the arr[top] = NULL since we actually remove the data We set back the top to top--. Example if top = 5, then top now is 4. We will return the int data
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Example (pop) int data = arr[top] - int data = arr[7]=5 5 64 4 2 12 32
54 top = 7 int data = arr[top] - int data = arr[7]=5
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Example (pop) arr[top]= NULL - arr[7] = NOTHING INSIDE 64 4 2 12 32 54
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Example (pop) 64 4 2 12 32 54 5 top = 7 top-- - Top = 6
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Example (pop) return data
64 4 2 12 32 54 5 top = 7 return data - We return data = 5 to any function that call or want to know what value that the push has throw away.
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Full source code
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#include <iostream> using namespace std; #define MAX 10 // MAXIMUM STACK CONTENT class stack { private: int arr[MAX]; // Contains all the Data int top; //Contains location of Topmost Data pushed onto Stack public: stack() //Constructor top=-1; //Sets the Top Location to -1 indicating an empty stack }
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void push(int a) // Push ie
void push(int a) // Push ie. Add Value Function { top++; // increment to by 1 if(top<MAX) arr[top]=a; //If Stack is Vacant store Value in Array } else cout<<"STACK FULL!!"<<endl; top--;
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int pop() // Delete Item. Returns the deleted item
{ if(top==-1) cout<<"STACK IS EMPTY!!!"<<endl; return NULL; } else int data=arr[top]; //Set Topmost Value in data arr[top]=NULL; //Set Original Location to NULL top--; // Decrement top by 1 return data; // Return deleted item };
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int main() { stack a; a.push(3); cout<<"3 is Pushed\n"; a.push(10); cout<<"10 is Pushed\n"; a.push(1); cout<<"1 is Pushed\n\n"; cout<<a.pop()<<" is Popped\n"; return 0; }
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APPLICATION
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ALGORITHM CONVERTING DECIMAL TO BINARY
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How it works Let say you have a number: 148
Is 148 >= 128? Yes, so the 128 bit must be – 128 = 20, which means we need to find bits worth 20 more. Is 20 >= 64? No, so the 64 bit must be 0. Is 20 >= 32? No, so the 32 bit must be 0. Is 20 >= 16? Yes, so the 16 bit must be – 16 = 4, which means we need to find bits worth 4 more.
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How it works Let say you have a number: 148
Is 4 >= 8? No, so the 8 bit must be 0. Is 4 >= 4? Yes, so the 4 bit must be 1. 4 – 4 = 0, which means all the rest of the bits must be 0.
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How it works Let say you have a number: 148
148 = (1 * 128) + (0 * 64) + (0 * 32) + (1 * 16) + (0 * 8) + (1 * 4) + (0 * 2) + (0 * 1) =
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Coding Enter the decimal number
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Coding While getnumber is still bigger than “0”, we will running this loop
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Coding This is to get the remaining balance after division
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Coding Push the balance (which is the balance of division) into stack
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Coding Save in public array too
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Coding Update the counter
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Coding Get the result of division using integer (not double/floating number)
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Coding Display purpose
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Source
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converting infix to postfix and prefix notation
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What is… Infix is A*B Postfix is AB* Prefix is *AB
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Infix to Postfix Let use an example
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Infix to postfix Process
a Postfix String At first, “a” is found and inserted into Postfix String Our Stack
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Infix to postfix Process
+ a Postfix String Then, we found “+” So put it into Our Stack Our Stack
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Infix to postfix Process
+ ab Postfix String Next, we scanned another one “b”. Put it into Postfix String Our Stack
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Infix to postfix Process
* + ab Postfix String Then, we found “ * ”. We put into Our Stack Our Stack
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Infix to postfix Process
* + abc Postfix String We found “C”. So put into Postfix String Our Stack
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Infix to postfix Process
- + abc* Postfix String Next character scanned is '-'. The topmost character in the stack is '*' which has a higher precedence than '-'. Thus '*' will be popped out from the stack and added to the Postfix string. Our Stack
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Infix to postfix Process
- abc*+ Postfix String Even now the stack is not empty. Now the topmost element of the stack is '+' which has equal priority to '-'. So pop the '+' from the stack and add it to the Postfix string. The '-' will be pushed to the stack. Our Stack
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Infix to postfix Process
- abc*+e Postfix String We found “e”. So put into Postfix String Our Stack
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Infix to postfix Process
abc*+e- Postfix String Nothing to scan. So, empty Our Stack and put “ – ” into Postfix String Our Stack
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But How to program??? Let’s code
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Our main components We must have a function to get a input
Then, we need to have a function to read it in character form And, we need a function to convert it into postfix Of course last one is we want to display the output
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Our main components
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Our Class items
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Our Class items We must have two array of stack
(i) One for the *, / , +, and – (ii) Another one for alphabetic
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Our Class items We need to also have two pointer based data type (char)
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Our Class items Set our initial value
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Our Class items Set our expression
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Our Class items Stack function (push and pop)
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Our Class items Convert function
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Our Class items Priority function (we will call this inside convert function)
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CONCLUSION OF IN/PRE/POST-FIX
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Source
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A Legend The Towers of Hanoi
In the great temple of Brahma in Benares, on a brass plate under the dome that marks the center of the world, there are 64 disks of pure gold that the priests carry one at a time between these diamond needles according to Brahma's immutable law: No disk may be placed on a smaller disk. In the begging of the world all 64 disks formed the Tower of Brahma on one needle. Now, however, the process of transfer of the tower from one needle to another is in mid course. When the last disk is finally in place, once again forming the Tower of Brahma but on a different needle, then will come the end of the world and all will turn to dust.
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The Towers of Hanoi A Stack-based Application
GIVEN: three poles a set of discs on the first pole, discs of different sizes, the smallest discs at the top GOAL: move all the discs from the left pole to the right one. CONDITIONS: only one disc may be moved at a time. A disc can be placed either on an empty pole or on top of a larger disc.
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Towers of Hanoi
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Towers of Hanoi
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Towers of Hanoi
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Towers of Hanoi
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Towers of Hanoi
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Towers of Hanoi
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Towers of Hanoi
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Towers of Hanoi
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addition two integer numbers
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