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SYSTEMS OF LINEAR INEQUALITIES
Solving Linear Systems of Inequalities by Graphing
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Solving Systems of Linear Inequalities
We show the solution to a system of linear inequalities by graphing them. This process is easier if we put the inequalities into Slope-Intercept Form, y = mx + b.
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Solving Systems of Linear Inequalities
Graph the line using the y-intercept & slope. If the inequality is < or >, make the lines dotted. If the inequality is < or >, make the lines solid.
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Solving Systems of Linear Inequalities
The solution also includes points not on the line, so you need to shade the region of the graph: above the line for ‘y >’ or ‘y ’. below the line for ‘y <’ or ‘y ≤’.
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Solving Systems of Linear Inequalities
Example: a: 3x + 4y > - 4 b: x + 2y < 2 Put in Slope-Intercept Form:
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Solving Systems of Linear Inequalities
Example, continued: Graph each line, make dotted or solid and shade the correct area. a: dotted shade above b: dotted shade below
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Solving Systems of Linear Inequalities
a: 3x + 4y > - 4
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Solving Systems of Linear Inequalities
a: 3x + 4y > - 4 b: x + 2y < 2
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Solving Systems of Linear Inequalities
a: 3x + 4y > - 4 b: x + 2y < 2 The area between the green arrows is the region of overlap and thus the solution.
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PRACTICE #1 on Worksheet We will solve on the whiteboard together! STEP 1: REARRANGE inequalities to look like y = mx + b 4x + 5y ≤ 2 y ≤ x + 3 -4x x (already done for you!) 5y ≤ -4x + 2 y ≤ -4/5x + 2/5
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Practice (cont.) STEP 2: Graph each inequality like a linear equation.
STEP 3: Shade area where point values “work” (plug in, does it make sense?)
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Practice (cont.) STEP 4: FIND THE COMMONLY SHADED AREA.
STEP 5: This is your final answer (only shade this part on final answer) FINAL ANSWER
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PRACTICE (cont) (#2) 3x + 5y > 15 y ≤ x – 2 -3x -3x already done! 5y > -3x y > -3/5 x + 3 Repeat graphing strategy (5 STEPS!)
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PRACTICE Solve # 3-8 on Worksheet by graphing on your whiteboard! (worksheet should be inside communicator!)
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