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Conjugated Pi Systems and Pericyclic Reactions

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Presentation on theme: "Conjugated Pi Systems and Pericyclic Reactions"— Presentation transcript:

1 Conjugated Pi Systems and Pericyclic Reactions
Chapter 17 Conjugated Pi Systems and Pericyclic Reactions Suggested Problems –

2 Classes of Dienes There are three categories for dienes
Cumulated – pi bonds are adjacent Conjugated – pi bonds are separated by exactly ONE single bond Isolated – pi bonds are separated by any distance greater than ONE single bond

3 Classes of Dienes There are three categories for dienes
Cumulated – pi bonds are perpendicular Conjugated – pi bond overlap extends over the entire system Isolated – pi bonds are separated by too great a distance to experience extra overlap

4 Classes of Dienes Heteroatoms may be involved in a conjugated system
Draw a picture of the molecule shown to the right indicating where the pi bonds are and how they overlap Practice with conceptual checkpoint 17.1

5 Conjugated Dienes A sterically hindered base can be used to form dienes while avoiding the competing substitution reaction Practice with conceptual checkpoint 17.2

6 Conjugated Dienes Single bonds that are part of a conjugated pi system are shorter than typical single bonds The hybridization of a carbon affects its bond length

7 Conjugated Dienes The more s-character a carbon has, the shorter its bonds will be. WHY? Practice with conceptual checkpoint 17.3

8 Conjugated Dienes HOW do heats of hydrogenation provide information about stability? WHY is energy released upon hydrogenation?

9 Conjugated Dienes HOW does conjugation affect stability?
Practice conceptual checkpoints 17.4 and 17.5

10 Conjugated Dienes Rank the following compounds in order of increasing stability Based on degree of unsaturation, conjugation, and degree to which the alkenes are substituted with carbons, the order should be from least to most stable A < C < B < D

11 Conjugated Dienes In general, single bonds will freely rotate
The two most stable rotational conformations for butadiene are the s-cis and s-trans What does the “s” of s-cis and s-trans stand for? Are there any other rotational conformations that you think might be possible? S stands for single

12 Conjugated Dienes The s-cis and s-trans both allow for full pi system overlap Other possible conformations will be higher in energy

13 Conjugated Dienes Why is s-trans lower in energy?
About 98% of the molecules are in the s-trans form

14 Conjugated Dienes The highest energy conformer will not be conjugated

15 Molecular Orbital Theory
Let’s review Molecular Orbital (MO) theory A MO forms when atomic orbitals overlap A MO extends over the entire molecule Recall the pi bonding and antibonding MOs for ethylene Which is more stable? WHY? What is a node?

16 Molecular Orbital Theory
The number of MOs must be equal to the number of AOs combined Note how the shorthand drawing matches the actual MOs

17 Molecular Orbital Theory
The 4 pi electrons in butadiene will occupy the lowest energy MOs. HOW will that affect stability?

18 Molecular Orbital Theory
MO theory also explains why the central C-C single bond is shorter and stronger than a typical C-C single bond

19 Molecular Orbital Theory
1,3,5-Hexatriene should have 6 pi MOs What are HOMO and LUMO? The HOMO and LUMO are the frontier MOs

20 Molecular Orbital Theory
Reactions that molecules undergo can often be explained by studying their frontier orbitals Light can be used to excite an electron from the HOMO to the LUMO

21 Electrophilic Addition
Recall the Markovnikov addition of H-X to a C=C double bond from section 9.3 With a conjugated diene as the substrate, two products are observed

22 Electrophilic Addition
The pi electrons attack the acid to give the most stable carbocation What intermediate would result if the H were added to any of the other carbons in the molecule?

23 Electrophilic Addition
The resonance stabilized carbocation can be attacked by the halide at either site that is sharing the (+) charge Practice with SkillBuilder 17.1 How is 1,2-addition different from 1,4-addition?

24 Electrophilic Addition
The addition of bromine to a diene also gives both 1,2 and 1,4 addition Predict the MAJOR products for the reaction below. Pay close attention to stereochemistry

25 Thermodynamic Control vs. Kinetic Control
The ratio of 1,2 vs. 1,4 addition is often temperature dependant The energy diagram must be examined to see WHY temperature affects the product distribution

26 Thermodynamic Control vs. Kinetic Control
Why are the products unequal in free energy?

27 Thermodynamic Control vs. Kinetic Control
Draw a structure for each of the Nuc: attack transition states

28 Thermodynamic Control vs. Kinetic Control
δ+ δ- Draw a structure for each of the Nuc: attack transition states δ+ δ-

29 Thermodynamic Control vs. Kinetic Control
The 1,2 addition should occur more often regardless of temperature. WHY? The H and Br are closer in the 1,2 adduct

30 Thermodynamic Control vs. Kinetic Control
Explain how high temps yield one product while low temps yield the other

31 Thermodynamic Control vs. Kinetic Control
Predict the MAJOR product for the following reactions

32 Thermodynamic Control vs. Kinetic Control
Predict the MAJOR product for the following reactions

33 Thermodynamic Control vs. Kinetic Control
Many polymerization reactions rely on 1,4 addition Give a reasonable mechanism for the cationic polymerization Practice with conceptual checkpoint 17.13

34 Thermodynamic Control vs. Kinetic Control
Many polymerization reactions rely on 1,4 addition Give a reasonable mechanism for the cationic polymerization

35 Intro to Pericyclic Reactions
Pericyclic reactions occur without ionic or free radical intermediates There are three main types of pericyclic reactions Cycloaddition reactions How is it an addition reaction?

36 Intro to Pericyclic Reactions
There are three main types of pericyclic reactions Electrocyclic reactions Sigmatropic rearrangements What is the difference between an addition and a rearrangement?

37 Intro to Pericyclic Reactions
Pericyclic reactions have 4 general features The reaction mechanism is concerted. It proceeds without any intermediates The mechanism involves a ring of electrons moving around a closed loop The transition state is cyclic The polarity of the solvent generally has no effect on the reaction rate.

38 Intro to Pericyclic Reactions
Changes in the number of pi and sigma bonds distinguish the pericyclic reactions from one another

39 Diels-Alder Reactions
Diels-Alder reactions can be very useful They allow a synthetic chemist to quickly build molecular complexity What is meant by [4+2] cycloaddition? Like all pericyclic reactions, the mechanism is concerted

40 Diels-Alder Reactions
Why do the products generally have lower free energy? Two pi bonds are broken and two sigma bonds are formed. Sigma bonds are lower in energy.

41 Diels-Alder Reactions
Most Diels-Alder reactions are thermodynamically favored at low and moderate temperatures At temperatures above 200 C, the retroDiels-Alder can predominate Will the reaction be favored or disfavored by entropy? Reaction is disfavored by entropy.

42 Diels-Alder Reactions
The pi  sigma conversion provides a (-)ΔH

43 Diels-Alder Reactions
ΔS should be (-) Two molecules combine to form ONE A ring (with limited rotational freedom) forms What will the sign (+/-) be for the –TΔS term?

44 Diels-Alder Reactions
Given the signs for ΔH and –TΔS, how should temperature affect reaction spontaneity (reactant vs. product favorability)? Are there any disadvantages if the temperature is too low? Think kinetics

45 Diels-Alder Reactions
In the Diels-Alder reaction, the reactants are generally classified as either the diene or dienophile If a dienophile is not substituted with an electron withdrawing group, it will not be kinetically favored (a lot of activation energy or high temperature will be required) However, high temps do not favor the products thermodynamically

46 Diels-Alder Reactions
When an electron withdrawing group is attached to the dienophile, the reaction is generally spontaneous Show how the groups highlighted in red are electron withdrawing using resonance and induction where appropriate

47 Diels-Alder Reactions
Diels-Alder reactions are stereospecific depending on whether the (E) or (Z) dienophile is used We will investigate the stereochemical outcome later in this chapter

48 Diels-Alder Reactions
A CΞC triple bond can also act as a dienophile Practice with SkillBuilder 17.3

49 Diels-Alder Reactions
Predict products for the following reactions

50 Diels-Alder Reactions
Predict products for the following reactions The regiochemistry results from the less crowded transition state.

51 Diels-Alder Reactions
Diels-Alder reactions can also be affected by diene structure Recall that many dienes can exist in an s-cis or an s-trans rotational conformation Which conformation is generally more stable, and WHY? Diels-Alder reactions can ONLY proceed when the diene adopts the s-cis conformation

52 Diels-Alder Reactions
Dienes that can only exist in an s-trans conformation can not undergo Diels-Alder reactions, because carbons 1 and 4 are too far apart Dienes that are locked into the s-cis conformation undergo Diels-Alder reactions readily Cyclopentadiene is so reactive, that at room temperature, two molecule will react together. 4 1

53 Diels-Alder Reactions
Draw four potential bicyclic Diels-Alder products for the reaction below Two of the potential stereoisomers are impossible. WHICH ones and WHY?

54 Diels-Alder Reactions
Draw four potential bicyclic Diels-Alder products for the reaction below The geometry of the concerted mechanism precludes the structures labeled impossible.

55 Diels-Alder Reactions
When bicyclic systems form, the terms ENDO and EXO are used to describe functional group positioning

56 Diels-Alder Reactions
The electron withdrawing groups attached to dieneophiles tend to occupy the ENDO position Major Product Minor Product

57 Diels-Alder Reactions
The Diels-Alder transition state that produces the ENDO product benefits from favorable pi system interactions Practice with conceptual checkpoint 17.19

58 MO Description of Cycloadditions
Note the molecular orbital descriptions below

59 MO Description of Cycloadditions
In the Diels-Alder, the HOMO of one compound must interact with the LUMO of the other

60 MO Description of Cycloadditions
With an electron withdrawing group, the dieneophile’s LUMO will accept electrons from the diene’s HOMO

61 MO Description of Cycloadditions
The phases of the MOs align to allow for orbital overlap If there is conservation of orbital symmetry, the process is symmetry-allowed Note the carbons that change their hybridization from sp2 to sp3

62 MO Description of Cycloadditions
Similar to a Diels-Alder ([4+2] cycloaddition),the reaction below is a [2+2] cycloaddition Draw a reasonable concerted mechanism Unless the reaction is symmetry-allowed, the process will not occur, so let’s analyze the MOs

63 MO Description of Cycloadditions
The LUMO of one reactant must overlap with the HOMO of the other WHY can’t both of the HOMOs interact together?

64 MO Description of Cycloadditions
The phases of the HOMO and LUMO can not line up to give effective overlap, so the reaction is symmetry-forbidden

65 MO Description of Cycloadditions
[2+2] cycloadditions are only possible when light is used to excite an electron Draw a picture that shows how the reaction is now symmetry allowed Practice with conceptual checkpoint 17.20

66 MO Description of Cycloadditions
[2+2] cycloadditions are only possible when light is used Draw a picture that shows how the reaction is now symmetry allowed

67 Electrocyclic reactions
Determine how the number of σ and π bonds change for the representative electrocyclic reactions below Explain why the equilibrium favor either products or reactants in the examples above

68 Electrocyclic reactions
When substituents are present on the terminal carbons, stereoisomers are possible Note that the use of light versus heat gives different products. See next few slides for explanation

69 Electrocyclic reactions
Often the energy present at room temperature is sufficient to promote thermal electrocyclic reactions Note that with the use of heat, the configuration of the reactant determines the product formed

70 Electrocyclic reactions
The symmetry of the HOMO determines the outcome The terminal carbons rotate as they become sp3 hybridized and overlap lobes that are in phase 6C

71 Electrocyclic reactions
The terminal carbons rotate as they become sp3 hybridized and overlap lobes that are in phase Disrotatory rotation (one rotates clockwise and the other counterclockwise) gives the cis product 6C

72 Electrocyclic reactions
The symmetry of the HOMO determines the outcome The terminal carbons rotate as they become sp3 hybridized and overlap lobes that are in phase 4C

73 Electrocyclic reactions
The symmetry of the HOMO determines the outcome Conrotatory rotation (one rotates clockwise and the other counterclockwise) gives the trans product 4C

74 Electrocyclic reactions
Use MO theory to explain the products for the reactions below Will disrotatory or conrotatory rotation be necessary? Practice with conceptual checkpoint 17.21 conrotatory

75 Electrocyclic reactions
Predict the major product for the reaction below. Pay close attention to stereochemistry

76 Electrocyclic reactions
Predict the major product for the reaction below. Pay close attention to stereochemistry disrotatory

77 Electrocyclic reactions
Under photochemical conditions, light energy excites an electron from the HOMO to the LUMO What was the LUMO becomes the new HOMO This was the old LUMO

78 Electrocyclic reactions
Will the new excited HOMO react disrotatory or conrotatory? Draw the expected product conrotatory

79 Electrocyclic reactions
Make the same MO analysis to predict the symmetry-allowed product for the reaction below. Pay close attention to stereochemistry

80 Electrocyclic reactions
Make the same MO analysis to predict the symmetry-allowed product for the reaction below. Pay close attention to stereochemistry The HOMO undergoes disrotatory motion pushing both ethyl groups up or both down

81 Electrocyclic reactions
The ring-opening reaction gives products that result from disrotatory rotation. Predict products below

82 Electrocyclic reactions
The Woodward-Hoffmann rules for thermal and photochemical electrocyclic reactions are found in table 17.2 Practice with SkillBuilder 17.4 4n Thermal Conrotatory

83 Sigmatropic Rearrangements
Sigmatropic Rearrangements – a pericyclic reaction in which one sigma bond is replaced with another Note that the pi bonds move their location

84 Sigmatropic Rearrangements
The notation for sigmatropic rearrangements is different from reactions we have seen so far Count the number of atoms on each side of the sigma bonds that are breaking and forming This is a [3,3] sigmatropic rearrangement

85 Sigmatropic Rearrangements
The reaction below is a [1,5] sigmatropic rearrangement Practice with conceptual checkpoint 17.25

86 Sigmatropic Rearrangements
The Cope rearrangement is a [3,3] sigmatropic reaction in which all 6 atoms in the cyclic transition state are CARBONS In general, what factors affect the spontaneity of the reaction (product favored vs. reactant favored)? Practice with conceptual checkpoint 17.26 Formation of a trisubstituted alkene

87 Sigmatropic Rearrangements
The Claisen rearrangement is a [3,3] sigmatropic reaction in which one of the 6 atoms in the cyclic transition state is an OXYGEN In general, what factors affect the spontaneity of the reaction? Practice with conceptual checkpoints and 17.28

88 Sigmatropic Rearrangements
Two pericyclic reactions occur in the biosynthesis of Vitamin D

89 UV-Vis Spectroscopy If light with the necessary energy strikes a compound with pi bonds, an electron will be excited from the HOMO to the LUMO Light energy is converted into potential energy

90 UV-Vis Spectroscopy In general, the necessary energy to excite an electron from π  π* (HOMO to LUMO) is either in the UV or visible region of the spectrum What might happen after the electrons is excited?

91 UV-Vis Spectroscopy UV-Vis spectroscopy gives structural information about molecules A beam of light ( nm) is split in two Half of the beam travels through a cuvette with the analyte in solution The other half of the beam travels through a cuvette with just the solvent (used as a negative control) The intensities of the light that pass through the cuvettes are compared to determine how much light is absorbed by the analyte

92 UV-Vis Spectroscopy UV-Vis spectroscopy gives structural information about molecules The resulting data is plotted to give a UV-Vis absorption spectrum Compounds require specific wavelengths of energy to excite

93 UV-Vis Spectroscopy More conjugation gives a smaller π  π* energy gap
The smaller the energy gap, the greater the lambda max 217 258 290

94 UV-Vis Spectroscopy The group of atoms responsible for absorbing UV-Vis light is known as the chromophore What you need to know – The greater the conjugation, the smaller the gap between energy levels The less energy needed to promote an electron The longer the wavelength of light absorbed More light emitted in the visible region

95 UV-Vis Spectroscopy The group of atoms responsible for absorbing UV-Vis light is known as the chromophore Woodward and Fieser developed rules to predict λmax for chromophore starting with butadiene as the base

96 UV-Vis Spectroscopy Woodward and Fieser developed rules to predict λmax for chromaphore starting with butadiene as the base The Woodward-Fieser rules are a guide to estimate λmax

97 UV-Vis Spectroscopy Practice with SkillBuilder 17.4

98 Color The visible region of the spectrum ( nm) is lower energy than UV radiation Lycopene is responsible for the red color of tomatoes Β-carotene is responsible for the orange color of carrots

99 Color The color observed by your eyes will be the opposite of what is required to cause the π  π* excitation. WHY? Practice with conceptual checkpoint 17.31

100 Color Bleaching agents generally work by breaking up conjugation through an addition reaction Destroying long range conjugation destroys the ability to absorb colored light. WHY? Does bleach actually remove stains? No, it breaks the extended conjugation so the stain is no longer colored

101 Chemistry of Vision Rods and Cones are photosensitive cells
Rods are the dominant receptor in dim lighting. Owls have only rods allowing them to see well at night Cones are responsible for detection of color. Pigeons have only cones providing sensitive daytime vision Rhodopsin is the light-sensitive compound in rods

102 Chemistry of Vision Sources of 11-cis-retinal include Vitamin A and β-carotene

103 Chemistry of Vision When rhodopsin is excited photochemically, a change in shape occurs that causes a release of Ca2+ ions The Ca2+ ions block channels through which billions of Na+ ions generally travel each second The decrease of Na+ ion flow culminates in a nerve impulse to the brain Our eyes are extremely sensitive Just a few photons can cause a nerve impulse

104 Additional Practice Problems
Explain the relationship between heat of hydrogenation and stability of a pi system. When a pi system is hydrogenated (with some rare exceptions), energy is released as pi bonds are converted to sigma bonds. Because electrons in a sigma bonds are more likely to be close to the nuclei sharing them, they are more stable and lower in energy. Producing products that are lower in energy is a negative enthalpy change or exothermic. Heat of hydrogenation is greater or more negative when more energy is released by the process. If a pi system has an extra degree of instability, it will be at an even higher energy level to begin with releasing more energy upon hydrogenation having a higher heat of hydrogenation.

105 Additional Practice Problems
Explain why the instability of electrons in a pi MO directly relates to the number of nodes the orbital posses. Each node is an area directly between two nuclei where the electron may not reside. That means the chance of an electron being in a stable position attracting to both nuclei at once is less. With fewer nodes, the electron can attract all of the nuclei at once as it has more freedom and more attractions means more stability.

106 Additional Practice Problems
Give a complete mechanism and predict the major product for the addition reaction below.

107 Additional Practice Problems
Predict the products and give necessary conditions for the compound below to undergo a retro Diels-Alder

108 Additional Practice Problems
Predict the products for the electrocyclic ring-opening below with proper stereochemical configuration.


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