1. Diffraction Chapter 36
Protein crystallography at SLAC, Stanford, CA
Apologies for the issues with the last two clicker problems !! Not your fault !

4. Response from the company

5. Let’s try again Today’s plan Quiz
Diffraction with some clicker examples.
Let’s try again
Please notify me if there are any glitches or problems.
In cases of doubt, I will just award everyone full credit.

6. Find the wavelength of light used in this 2- slits interference.
Q4.1
Find the wavelength of light used in this 2- slits interference.
Note: Not drawn to scale.
3.16mm
0.666mm mm
0.200mm
Hint:
Ans: λ=633nm (typical of He-Ne laser) 6

7. Find the wavelength of light used in this 2- slits interference.
Q4.1
Find the wavelength of light used in this 2- slits interference.
Note: Not drawn to scale.
3.16mm
0.666mm mm
0.200mm
Ans: λ=633nm (typical of He-Ne laser) 7

8. Q4.2 A 8

9. Q4.2 A 9

10. Q4.2 A 1 1 10

11. What do these pictures try to illustrate?
Q4.3
What do these pictures try to illustrate?
The phase shift during reflection.
Interference can occur when the film thickness is less than the coherence length of the light.
Interference can occur when the film thickness is greater than the coherence length of the light. B 11

12. What do these pictures try to illustrate?
Q4.3
What do these pictures try to illustrate?
The phase shift during reflection.
Interference can occur when the film thickness is less than the coherent length of the light.
Interference can occur when the film thickness is greater than the coherent length of the light. B 12

13. Will need phasors to understand diffraction gratings.
Phasor review
Will need phasors to understand diffraction gratings. 13

14. Diffraction grating and the sun (first gateway to QM)
Joseph von Fraunhofer ( )
QM means quantum mechanics
Unexpected dark lines due to the absorption of elements in the sun’s atmosphere. In the 20th century it was realized that atomic energies are quantized.
The spectrum is not continuous ! 14

15. Crystallography by X-ray diffraction
Protein x-ray crystallography setup at the SLAC LCLS
(Linear Coherent Light Source) in Stanford, CA.
First x-ray diffraction image of DNA by Rosalind Franklin
(Fig of the text)
Other similar facilities in Hamburg Germany and Harima Science City, Japan 15

16. Goals for Chapter 36 (Diffraction)
To see how a sharp edge or an aperture affects light
To analyze single-slit diffraction and calculate the intensity of the light
To investigate the effect on light of many closely spaced slits
To learn how scientists use diffraction gratings (e.g. in astrophysics)
To see what x-ray diffraction tells us about crystals, proteins…
To learn how diffraction places limits on the resolution of a telescope
Holograms ! 16

17. Diffraction, Chapter 36
What is Diffraction: the process by which a beam of light or other system of waves is spread out as a result of passing through a narrow aperture or across an edge, typically accompanied by interference between the wave forms produced.
A picture helps
Diffraction of water waves 17

18. Diffraction from a single slit (Physical Optics)
In the Figure below, the prediction of geometric optics in (a) does not occur. Instead, a diffraction pattern is produced, as in (b).
The narrower the slit, the broader the diffraction pattern.
Light is a wave (EM waves) and hence diffracts.
Diffraction phenomena also occur for EM waves, sound, electrons (QM)
Geometric optics
Physical Optics 18

19. Diffraction Not a clicker problem !! λ (wavelength) Slit spacing Both
Neither
Life/death of Schroedinger’s cat
What physical parameters control whether single slit diffraction occurs ?
Ans: λ (wavelength), a (slit spacing). But this is not the full story.
Ans: 2nd part, distance to the screen (near field, Fresnel diffraction) and (far field, Fraunhofer diffraction) 19

20. Diffraction
According to geometric optics, a light source shining on an object in front of a screen should cast a sharp shadow. Surprisingly, this does not occur because of diffraction. 20

21. Diffraction and Huygen’s Principle
Huygens’s principle can be used to analyze diffraction.
Fresnel diffraction: Source, screen, and obstacle are close together.
Fraunhofer diffraction: Source, screen, and obstacle are far apart.
The figure below shows the diffraction pattern of a razor blade. 21

22. Diffraction and Huygen’s Principle
What is Huygens’s principle ?
The Huygens-Fresnel principle states that every point on a wavefront is a source of wavelets. These wavelets spread out in the forward direction, at the same speed as the source wave. The new wavefront is a line tangent to all of the wavelets.
So what is interfering in single slit diffraction ? 22

23. Fresnel and Fraunhofer diffraction by a single slit
The figure below shows Fresnel (near-field) and Frauenhofer (far-field) diffraction for a single slit. 23

24. Locating the dark fringes
Review the single-slit diffraction discussion in the text.
The figure below shows the geometry for single slit Fraunhofer diffraction. (Imagine the aperture is made of many tiny slits).
a.sin(θ)
a/2 sin(θ)
a/4 sin(θ)
What is the path difference between the two strips ?
Ans: path difference =a/2 sin(θ)
bright
dark
In between
Dark fringe
If path difference to P is λ/2, what do we see at Point P ? 24

25. Locating the dark fringes in single slit diffraction
In general, at what angles do we find the dark fringes ?
Ans: If path difference to P is mλ/2, we will find dark fringes
Dark fringes
Different from double slit interference 25

26. Locating the dark fringes in the single slit diffraction pattern26

27. Examples of single-slit diffraction
The figure on the left is a photograph of a Fraunhofer pattern of a single horizontal slit. What features are especially notable ?
Example 36.1: You pass 633-nm light through a narrow slit and observe the diffraction pattern on a screen 6.0 m away. The distance at the screen between the center and the first minima on either side is 32 mm long. How wide is the slit?
(look at the intensity pattern) 27

28. Intensity in the single-slit pattern
Follow the text’s discussion of the intensity in the single-slit pattern using the phasor diagrams below.
Why ? 28

29. Quantitative Intensity in the single-slit pattern
E field phasors
The angle β is the phase angle of the ray from the top of the slit, while the phase angle from the bottom of the slit is 0. The vectors lie along a circle whose center is at C, so Ep is a chord of the circle. The arc length E0 is subtended by this same angle β, so the radius of the circle is E0/β.
From the diagram,
Since
We have
(sinc function) 29

30. Quantitative Intensity in the single-slit diffraction pattern
Intensity of a single slit diffraction pattern or 30

31. Intensity maxima in a single-slit pattern
The figure on the right shows the intensity versus angle in a single-slit diffraction pattern.
The minima occur when β is a multiple of 2π, i.e. at
The location of the maxima are found by taking the derivative of
and setting it to zero. Surprisingly, these are not precisely where
In fact, there are no maxima for m = 0 in this expression. The central maximum is wider than the others, and occurs at θ = 0.
Using these approximate values of β in the intensity, we find 31

32. Width of the single-slit pattern
The width of the single-slit diffraction pattern depends on the ratio of the slit width a to the wavelength λ.
This characterizes the width
Angular position of first minimum 32

33. For next time
Expected to read the book (Chapter 36) in advance. For Wednesday sections