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Combinatorial Principles, Permutations, and Combinations

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Presentation on theme: "Combinatorial Principles, Permutations, and Combinations"β€” Presentation transcript:

1 Combinatorial Principles, Permutations, and Combinations
Section 03 Combinatorial Principles, Permutations, and Combinations

2 Permutations vs. Combinations
Permutations are ordered Combinations are not ordered Therefore, there are more permutations than combinations for given 𝑛 and π‘˜ Both apply to combinatorics without replacement Also: remember 0! = 1

3 Permutations ORDER MATTERS
Choosing an ordered subset of size π‘˜ from a collection of 𝑛 objects without replacement: π‘›π‘ƒπ‘˜= 𝑛! π‘›βˆ’π‘˜ ! Given 𝑛 objects, of which 𝑛 1 are Type 1, 𝑛 2 are Type 2, etc, up to 𝑛 𝑑 , the number of ways to order all 𝑛 objects is: 𝑛! 𝑛 1 !βˆ— 𝑛 2 !βˆ—β€¦βˆ— 𝑛 𝑑 !

4 Combinations ORDER DOES NOT MATTER
Choosing a subset of size π‘˜ from a collection of 𝑛 objects without replacement: 𝑛 π‘˜ =π‘›πΆπ‘˜= 𝑛! π‘˜!βˆ— π‘›βˆ’π‘˜ ! 𝑛 π‘˜ is also called a binomial coefficient

5 Binomial Theorem 𝑛 π‘˜ is called the binomial coefficient because it is used in the power series expansion of (1+𝑑) 𝑛 (1+𝑑) 𝑛 = π‘˜=0 ∞ 𝑁 π‘˜ βˆ— 𝑑 π‘˜ = 1+𝑁𝑑+ 𝑁(π‘βˆ’1) 2 𝑑 2 + 𝑁 π‘βˆ’1 (π‘βˆ’2) 6 𝑑 3 +… If N is as integer, summations stops at k=N If N is not an integer, series is only valid if -1<t<1 This expansion is useful for understanding the binomial distribution

6 Multinomial Theorem In the power series expansion of ( 𝑑 1 + 𝑑 2 +…+ 𝑑 𝑠 ) 𝑁 the coefficient of 𝑑 1 𝑛 1 βˆ— 𝑑 2 𝑛 2 βˆ—β€¦βˆ— 𝑑 𝑠 𝑛 is 𝑁 𝑛 1 𝑛 2 … 𝑛 𝑠 = 𝑁! 𝑛 1 !βˆ— 𝑛 2 !βˆ—β€¦βˆ— 𝑛 𝑠 ! Useful for understanding multinomial distributions (much later)

7 In conclusion… Ordered? Not ordered? π‘›π‘ƒπ‘˜= 𝑛! π‘›βˆ’π‘˜ !
π‘›π‘ƒπ‘˜= 𝑛! π‘›βˆ’π‘˜ ! Not ordered? 𝑛 π‘˜ =π‘›πΆπ‘˜= 𝑛! π‘˜!βˆ— π‘›βˆ’π‘˜ !

8 Sample Exam #4 An urn contains 10 balls: 4 red and 6 blue. A second urn contains 16 red balls and an unknown number of blue balls. A single ball is drawn from each urn. The probability that both balls are the same color is Calculate the number of blue balls in the second urn

9 Sample Exam #248 Bowl I contains eight red balls and six blue balls. Bowl II is empty. Four balls are selected at random, without replacement, and transferred from bowl I to bowl II. One ball is then selected at random from bowl II. Calculate the conditional probability that two red balls and two blue balls were transferred from bowl I to bowl II, given that the ball selected from bowl II is blue.

10 Actex, Sec 3 #1, pg 103 A class contains 8 boys and 7 girls. The teacher selects 3 of the children at random and without replacement. Calculate the probability that the number of boys selected exceeds the number of girls selected.

11 Actex, Sec 3, #3, pg 103 A box contains 4 red balls and 6 white balls. A sample of size 3 is drawn without replacement from the box. What is the probability of obtaining 1 red ball and 2 white balls, given that at least 2 of the balls in the sample are white?

12 Actex, Sec 3, #5 A box contains 35 gems, of which 10 are real diamonds and 25 are fake diamonds. Gems are randomly taken out of the box, one at a time without replacement. What is the probability that exactly 2 fakes are selected before the second real diamond is selected?


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