= 0) { int result = number * number; } else { result = number * 10; } System.out.printf("result = %d\n", result); }"> = 0) { int result = number * number; } else { result = number * 10; } System.out.printf("result = %d\n", result); }">

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Variable scope. Variable Scope Variables do not live forever. Failing to take that into account leads to problems. Let's look at an example. Let's write.

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Presentation on theme: "Variable scope. Variable Scope Variables do not live forever. Failing to take that into account leads to problems. Let's look at an example. Let's write."— Presentation transcript:

1 Variable scope

2 Variable Scope Variables do not live forever. Failing to take that into account leads to problems. Let's look at an example. Let's write a program that: – Asks the user to enter an integer. – If the integer is >= 0, it creates a variable result and sets it equal to the square of the integer. – If the integer is < 0, it creates a variable result and sets it equal to 10 * the integer. – It prints out the value of variable result. 2

3 Variable Scope This version will not run. Why? 3 import java.util.Scanner; // incorrect code public class example1 { public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.printf("Please enter an integer: "); int number = in.nextInt(); if (number >= 0) { int result = number * number; } else { result = number * 10; } System.out.printf("result = %d\n", result); }

4 Variable Scope This version will not run. Why? Java will complain that "it cannot find symbol" result, on the line shown in red. How do we fix this? 4 import java.util.Scanner; // incorrect code public class example1 { public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.printf("Please enter an integer: "); int number = in.nextInt(); if (number >= 0) { int result = number * number; } else { result = number * 10; } System.out.printf("result = %d\n", result); }

5 Variable Scope This version will also not run. Why? 5 import java.util.Scanner; // incorrect code public class example1 { public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.printf("Please enter an integer: "); int number = in.nextInt(); if (number >= 0) { int result = number * number; } else { int result = number * 10; } System.out.printf("result = %d\n", result); }

6 Variable Scope This version will also not run. Why? Java will complain that "it cannot find symbol" result, on the line shown in red. 6 import java.util.Scanner; // incorrect code public class example1 { public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.printf("Please enter an integer: "); int number = in.nextInt(); if (number >= 0) { int result = number * number; } else { int result = number * 10; } System.out.printf("result = %d\n", result); }

7 Lifetime of a Variable What is the reason for these errors? Each variable has a lifetime. – It is born in a line of code. – It dies at some point. To understand the lifetime of variable, we must understand the concept of a block of code. 7 import java.util.Scanner; // incorrect code public class example1 { public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.printf("Please enter an integer: "); int number = in.nextInt(); if (number >= 0) { int result = number * number; } else { int result = number * 10; } System.out.printf("result = %d\n", result); }

8 Blocks of Code and Braces A block of code is a chunk of code that: – Starts with an opening brace {. – Ends with the corresponding closing brace }. Example: – What block of code does the highlighted line belong to? 8 import java.util.Scanner; // incorrect code public class example1 { public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.printf("Please enter an integer: "); int number = in.nextInt(); if (number >= 0) { int result = number * number; } else { int result = number * 10; } System.out.printf("result = %d\n", result); }

9 Blocks of Code and Braces A block of code is a chunk of code that: – Starts with an opening brace {. – Ends with the corresponding closing brace }. Example: – What block of code does the highlighted line belong to? – The answer is shown in red. 9 import java.util.Scanner; // incorrect code public class example1 { public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.printf("Please enter an integer: "); int number = in.nextInt(); if (number >= 0) { int result = number * number; } else { int result = number * 10; } System.out.printf("result = %d\n", result); }

10 Blocks of Code and Braces A block of code is a chunk of code that: – Starts with an opening brace {. – Ends with the corresponding closing brace }. Example: – What block of code does the highlighted line belong to? 10 import java.util.Scanner; // incorrect code public class example1 { public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.printf("Please enter an integer: "); int number = in.nextInt(); if (number >= 0) { int result = number * number; } else { int result = number * 10; } System.out.printf("result = %d\n", result); }

11 Blocks of Code and Braces A block of code is a chunk of code that: – Starts with an opening brace {. – Ends with the corresponding closing brace }. Example: – What block of code does the highlighted line belong to? – The answer is shown in red. 11 import java.util.Scanner; // incorrect code public class example1 { public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.printf("Please enter an integer: "); int number = in.nextInt(); if (number >= 0) { int result = number * number; } else { int result = number * 10; } System.out.printf("result = %d\n", result); }

12 Birth of a Variable Each variable has a lifetime. – It is born in a line of code. – It dies at some point. Where is a variable born? – At the line where it is declared. 12 import java.util.Scanner; // incorrect code public class example1 { public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.printf("Please enter an integer: "); int number = in.nextInt(); if (number >= 0) { int result = number * number; } else { int result = number * 10; } System.out.printf("result = %d\n", result); }

13 Death of a Variable Where is a variable born? – At the line where it is declared. Where does a variable die? – Find the innermost block containing the variable declaration. – The variable dies at the end of that block. 13 import java.util.Scanner; // incorrect code public class example1 { public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.printf("Please enter an integer: "); int number = in.nextInt(); if (number >= 0) { int result = number * number; } else { int result = number * 10; } System.out.printf("result = %d\n", result); }

14 Scope of a Variable Where is a variable born? – At the line where it is declared. Where does a variable die? – Find the innermost block containing the variable declaration. – The variable dies at the end of that block. The lines of code where a variable is alive are called the scope of that variable. 14 import java.util.Scanner; // incorrect code public class example1 { public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.printf("Please enter an integer: "); int number = in.nextInt(); if (number >= 0) { int result = number * number; } else { int result = number * 10; } System.out.printf("result = %d\n", result); }

15 Variable Scope Where is variable number born? 15 import java.util.Scanner; // incorrect code public class example1 { public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.printf("Please enter an integer: "); int number = in.nextInt(); if (number >= 0) { int result = number * number; } else { int result = number * 10; } System.out.printf("result = %d\n", result); }

16 Variable Scope Where is variable number born? – At the line where it is declared. 16 import java.util.Scanner; // incorrect code public class example1 { public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.printf("Please enter an integer: "); int number = in.nextInt(); if (number >= 0) { int result = number * number; } else { int result = number * 10; } System.out.printf("result = %d\n", result); }

17 Variable Scope Where is variable number born? – At the line where it is declared. Where does variable number die? 17 import java.util.Scanner; // incorrect code public class example1 { public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.printf("Please enter an integer: "); int number = in.nextInt(); if (number >= 0) { int result = number * number; } else { int result = number * 10; } System.out.printf("result = %d\n", result); }

18 Variable Scope Where is variable number born? – At the line where it is declared. Where does variable number die? – The innermost block where containing the declaration of number is shown in red. 18 import java.util.Scanner; // incorrect code public class example1 { public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.printf("Please enter an integer: "); int number = in.nextInt(); if (number >= 0) { int result = number * number; } else { int result = number * 10; } System.out.printf("result = %d\n", result); }

19 Variable Scope Where is variable number born? – At the line where it is declared. Where does variable number die? – The innermost block where containing the declaration of number is shown in red. – So, number dies when we get outside that block. – In short, number dies at the end of the program. 19 import java.util.Scanner; // incorrect code public class example1 { public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.printf("Please enter an integer: "); int number = in.nextInt(); if (number >= 0) { int result = number * number; } else { int result = number * 10; } System.out.printf("result = %d\n", result); }

20 Variable Scope So, what is the scope of variable number? 20 import java.util.Scanner; // incorrect code public class example1 { public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.printf("Please enter an integer: "); int number = in.nextInt(); if (number >= 0) { int result = number * number; } else { int result = number * 10; } System.out.printf("result = %d\n", result); }

21 Variable Scope So, what is the scope of variable number? It is the lines between its declaration and its death. – Shown in red. It cannot be used before or after those lines. This is fine, the scope of number is what it should be. 21 import java.util.Scanner; // incorrect code public class example1 { public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.printf("Please enter an integer: "); int number = in.nextInt(); if (number >= 0) { int result = number * number; } else { int result = number * 10; } System.out.printf("result = %d\n", result); }

22 Variable Scope What is the scope of variable result? 22 import java.util.Scanner; // incorrect code public class example1 { public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.printf("Please enter an integer: "); int number = in.nextInt(); if (number >= 0) { int result = number * number; } else { int result = number * 10; } System.out.printf("result = %d\n", result); }

23 Variable Scope What is the scope of variable result? In this code, there are two independent variables called result. – The first one has its scope shown in red. – The second one has its scope shown in green. Obviously, none of them is alive at the printf line. – That is why Java complaints. 23 import java.util.Scanner; // incorrect code public class example1 { public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.printf("Please enter an integer: "); int number = in.nextInt(); if (number >= 0) { int result = number * number; } else { int result = number * 10; } System.out.printf("result = %d\n", result); }

24 Variable Scope What is the scope of variable result in this example? 24 import java.util.Scanner; // incorrect code public class example1 { public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.printf("Please enter an integer: "); int number = in.nextInt(); if (number >= 0) { int result = number * number; } else { result = number * 10; } System.out.printf("result = %d\n", result); }

25 Variable Scope What is the scope of variable result in this example? It is shown in red on this slide. Obviously, in this example, result is not alive either at the else part or at the printf line at the end. – That is why Java complains. 25 import java.util.Scanner; // incorrect code public class example1 { public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.printf("Please enter an integer: "); int number = in.nextInt(); if (number >= 0) { int result = number * number; } else { result = number * 10; } System.out.printf("result = %d\n", result); }

26 Variable Scope How do we make this code correct? 26 import java.util.Scanner; // incorrect code public class example1 { public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.printf("Please enter an integer: "); int number = in.nextInt(); if (number >= 0) { int result = number * number; } else { result = number * 10; } System.out.printf("result = %d\n", result); }

27 Variable Scope How do we make this code correct? We need to make sure that we have a single variable, called result, that is alive: – at the if part. – at the else part. – at the printf statement at the end. 27 import java.util.Scanner; // incorrect code public class example1 { public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.printf("Please enter an integer: "); int number = in.nextInt(); if (number >= 0) { int result = number * number; } else { result = number * 10; } System.out.printf("result = %d\n", result); }

28 Variable Scope The solution is to declare result before the if part. What is the scope of result now? 28 import java.util.Scanner; // correct code public class example1 { public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.printf("Please enter an integer: "); int number = in.nextInt(); int result; if (number >= 0) { result = number * number; } else { result = number * 10; } System.out.printf("result = %d\n", result); }

29 Variable Scope The solution is to declare result before the if part. What is the scope of result now? It is shown in red on this slide. 29 import java.util.Scanner; // correct code public class example1 { public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.printf("Please enter an integer: "); int number = in.nextInt(); int result; if (number >= 0) { result = number * number; } else { result = number * 10; } System.out.printf("result = %d\n", result); }

30 Variable Scope We do not have to assign a value to result when we declare it. Java is sure that, when it is time to print the value at the end, result has received a value. How can it be sure? 30 import java.util.Scanner; // correct code public class example1 { public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.printf("Please enter an integer: "); int number = in.nextInt(); int result; if (number >= 0) { result = number * number; } else { result = number * 10; } System.out.printf("result = %d\n", result); }

31 Variable Scope We do not have to assign a value to result when we declare it. Java is sure that, when it is time to print the value at the end, result has received a value. How can it be sure? – Because result is assigned a value both by the if part and by the else part. 31 import java.util.Scanner; // correct code public class example1 { public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.printf("Please enter an integer: "); int number = in.nextInt(); int result; if (number >= 0) { result = number * number; } else { result = number * 10; } System.out.printf("result = %d\n", result); }

32 Variable Scope What is going to happen here? – We removed the else part. 32 import java.util.Scanner; // incorrect code public class example1 { public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.printf("Please enter an integer: "); int number = in.nextInt(); int result; if (number >= 0) { result = number * number; } System.out.printf("result = %d\n", result); }

33 Variable Scope What is going to happen here? – We removed the else part. Java will refuse to run this code. Reason: if number < 0, then result never receives a value. Before running a program, Java must prove to itself that all variables receive values before they are used. 33 import java.util.Scanner; // incorrect code public class example1 { public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.printf("Please enter an integer: "); int number = in.nextInt(); int result; if (number >= 0) { result = number * number; } System.out.printf("result = %d\n", result); }

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