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Notes 16-1 Acids and Bases. Question 15.76 An equilibrium mixture of H 2, I 2, and HI at 458°C contains 0.112 mol H 2, 0.112 mol I 2 and 0.775 mol HI.

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Presentation on theme: "Notes 16-1 Acids and Bases. Question 15.76 An equilibrium mixture of H 2, I 2, and HI at 458°C contains 0.112 mol H 2, 0.112 mol I 2 and 0.775 mol HI."— Presentation transcript:

1 Notes 16-1 Acids and Bases

2 Question 15.76 An equilibrium mixture of H 2, I 2, and HI at 458°C contains 0.112 mol H 2, 0.112 mol I 2 and 0.775 mol HI in a 5.00L vessel. What are the equilibrium partial pressures when equilibrium is reestablished following the addition of 0.100 mol of HI?

3 16.1 Acids and Bases: a review A.) Arrhenius 1.) An acid is a substance that, when dissolved in water, increases the concentration of hydrogen ions. 2.) A base is a substance that, when dissolved in water, increases the concentration of hydroxide ions.

4 B.) Brønsted-Lowry 1.) An acid is a proton donor. 2.) A base is a proton acceptor. 3.) an H + ion in water a.) an H + ion is simply a proton with no surrounding valence electron. b.) it then forms a coordinate covalent bond with a water to form H 3 O + c.) it can form complexes of hydrogen bonds that have formulas such as H 5 O 2 +, or H 9 O 4 + d.) chemists usually just use the interchangeable H + and H 3 O +

5 C.) A Brønsted-Lowry acid… …must have a removable (acidic) proton. D.) A Brønsted-Lowry base… …must have a pair of nonbonding electrons.

6 E.) If it can be either… …it is amphiprotic. HCO 3 - HSO 4 - H2OH2O

7 © 2009, Prentice-Hall, Inc. F.) What Happens When an Acid Dissolves in Water? 1.) Water acts as a Brønsted-Lowry base and abstracts a proton (H + ) from the acid. 2.) As a result, the conjugate base of the acid and a hydronium ion are formed.

8 © 2009, Prentice-Hall, Inc. G.) Conjugate Acids and Bases 1.) The term conjugate comes from the Latin word “conjugare,” meaning “to join together.” 2.) Reactions between acids and bases always yield their conjugate bases and acids.

9 Sample Exercise 16.1 Identifying Conjugate Acids and Bases (a) What is the conjugate base of each of the following acids: HClO 4, H 2 S, PH 4 +, HCO 3 – ? (b) What is the conjugate acid of each of the following bases: CN –, SO 4 2–, H 2 O, HCO 3 – ? Write the formula for the conjugate acid of each of the following: HSO 3 –, F –, PO 4 3–, CO. Practice Exercise

10 Sample Exercise 16.2 Writing Equations for Proton-Transfer Reactions The hydrogen sulfite ion (HSO 3 – ) is amphiprotic. (a) Write an equation for the reaction of HSO 3 – with water, in which the ion acts as an acid. (b) Write an equation for the reaction of HSO 3 – with water, in which the ion acts as a base. In both cases identify the conjugate acid–base pairs. When lithium oxide (Li 2 O) is dissolved in water, the solution turns basic from the reaction of the oxide ion (O 2– ) with water. Write the reaction that occurs, and identify the conjugate acid–base pairs. Practice Exercise

11 H.) Acid and Base Strength 1.) Strong acids are completely dissociated in water. – Their conjugate bases are quite weak. 2.) Weak acids only dissociate partially in water. – Their conjugate bases are weak bases.

12 3.) Substances with negligible acidity do not dissociate in water. Their conjugate bases are exceedingly strong. Using the categories to the left, specify the strength of HNO 3 and the strength of its conjugate base, NO 3 -

13 4.) In any acid-base reaction, the equilibrium will favor the reaction that moves the proton to the stronger base. HCl (aq) + H 2 O (l)  H 3 O + (aq) + Cl - (aq) H 2 O is a much stronger base than Cl -, so the equilibrium lies so far to the right that K is not measured (K>>1).

14 5.) In any acid-base reaction, the equilibrium will favor the reaction that moves the proton to the stronger base. Acetate is a stronger base than H 2 O, so the equilibrium favors the left side (K<1). CH 3 CO 2 H (aq) + H 2 O (l) H 3 O + (aq) + CH 3 CO 2 - (aq)

15 Sample Exercise 16.3 Predicting the Position of a Proton-Transfer Equilibrium For the following proton-transfer reaction, use Figure 16.4 to predict whether the equilibrium lies predominantly to the left (that is, K c 1): For each of the following reactions, use Figure 16.4 to predict whether the equilibrium lies predominantly to the left or to the right: Practice Exercise


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