Download presentation
Presentation is loading. Please wait.
Published byOliver Strickland Modified over 8 years ago
1
Nattee Niparnan
2
Graph A pair G = (V,E) V = set of vertices (node) E = set of edges (pairs of vertices) V = (1,2,3,4,5,6,7) E = ((1,2),(2,3),(3,5),(1,4),(4, 5),(6,7)) 1 2 3 4 5 6 7
3
Term you should already know directed, undirected graph Weighted graph Bipartite graph Tree Spanning tree Path, simple path Circuit, simple circuit Degree
4
Representing a Graph Adjacency Matrix A = |V|x|V| matrix a xy = 1when there is an edge connecting node x and node y a xy = 0otherwise 1 2 3 4 5 01010 10110 01001 11001 00110 12345 1 2 3 4 5
5
Representing a Graph Adjacency List Use a list instead of a matrix For each vertex, we have a linked list of their neighbor 1 2 3 4 5 124 2134...
6
Representing a Graph Incidences Matrix Row represent edge Column represent node 1 2 3 4 5 11000 10010 01010 01100 00101 00011 12345
7
Depth First Search
8
Exploring a Maze
9
Exploring Problem
10
Depth-First-Search void explore(G, v) // Input: G = (V,E) is a graph; v V // Output: visited[u] is set to true for all nodes u reachable from v { visited[v] = true previsit(v) for each edge (v,u) E if not visited[u] explore(u) postvisit(v) }
11
Example Explore(A)
12
Extend to Graph Traversal Traversal is walking in the graph We might need to visit each component in the graph Can be done using explore Do “explore” on all non-visited node The result is that we will visit every node What is the difference between just looking into V (the set of vertices?)
13
Graph Traversal using DFS void dfs(G) { for all v V visited[v] = false for all v V if not visited[v] explore(v) }
14
Complexity Analysis Each node is visited once Each edge is visited twice Why? O( |V| + |E|)
15
Another Example
17
Connected Component
18
Connectivity in Undirected Graph
19
Connected Component Problem Input: A graph Output: Marking in every vertices identify the connected component Let it be an array ccnum, indexed by vertices
20
Solution Define global variable cc In previsit(v) ccnum[v] = cc Before calling each explore cc++
21
DFS visiting time
22
Ordering in Visit void previsit(v) pre[v] = clock++ void postvisit(v) post[v] = clock++
23
Ordering in Visit The interval for node u is [pre(u),post(u)] The inverval for u,v is either Contained disjointed Never intersect
24
DFS in Directed Graph
25
Type of Edge in Directed Graph
26
Directed Acyclic Graph (DAG) A directed Graph without a cycle Has “source” A node having only “out” edge Has “sink” A node having only “in” edge How can we detect that a graph is a DAG What should be the property of “source” and “sink” ?
27
Solution A directed graph is acyclic if and only if it has no back edge Sink Having lowest post number Source Having highest post number
28
Topological Sorting
29
Linearization of Graph
30
Linearization One possible linearization B,A,D,C,E,F Order of work that can be done w/o violating the causality constraints
31
Topological Sorting Problem
32
Topological Sorting Do DFS List node by post number (descending) 1,12 2,9 3,84,5 6,7 10,11
33
Breadth First Search
34
Distance of nodes The distance between two nodes is the length of the shortest path between them S A 1 S C 1 S B 2
35
DFS and Length DFS finds all nodes reachable from the starting node But it might not be “visited” according to the distance
36
Ball and Strings We can compute distance by proceeding from “layer” to “layer”
37
Shortest Path Problem (Undi, Unit) Input: A graph, undirected A starting node S Output: A label on every node, giving the distance from S to that node
38
Breadth-First-Search Visit node according to its layer procedure bfs(G, s) //Input: Graph G = (V,E), directed or undirected; vertex s V //Output: visit[u] is set to true for all nodes u reachable from v for each v V visited[v] = false visited[s] = true Queue Q = [s] //queue containing just s while Q is not empty v = Q.dequeue() previsit(v) visited[v] = true for each edge (v,u) E if not visited[u] visited[u] = true Q.enqueue(u) postvisit(v)
39
Distance using BFS procedure shortest_bfs(G, s) //Input: Graph G = (V,E), directed or undirected; vertex s V //Output: For all vertices u reachable from s, dist(u) is set to the distance from s to u. for all v V dist[v] = -1 dist[s] = 0 Queue Q = [s] //queue containing just s while Q is not empty v = Q.dequeue() for all edges (v,u) E if dist[u] = -1 dist[u] = dist[v] + 1 Q.enqueue(u) Use dist as visited
40
DFS by Stack procedure dfs(G, s) //Input: Graph G = (V,E), directed or undirected; vertex s V //Output: visited[u] is true for any node u reachable from v for each v V visited[v] = false visited[s] = true Stack S = [s] //queue containing just s while S is not empty v = S.pop() previsit(v) visited[v] = true for each edge (v,u) E if not visited[u] visited[u] = true S.push(u) postvisit(v)
41
DFS vs BFS DFS goes depth first Trying to go further if possible Backtrack only when no other possible way to go Using Stack BFS goes breadth first Trying to visit node by the distance from the starting node Using Queue
Similar presentations
© 2024 SlidePlayer.com Inc.
All rights reserved.