Presentation is loading. Please wait.

Presentation is loading. Please wait.

Level 1 Fundamental Training Pressure 1.

Similar presentations


Presentation on theme: "Level 1 Fundamental Training Pressure 1."— Presentation transcript:

1 Level 1 Fundamental Training Pressure 1

2 Contents Topics: Slide No: Why measure pressure? 3
What is pressure? Pressure terminology Inferring non-pressure variables Pressure measurement technology Pressure calibrators 45 Exercises

3 Why measure pressure? 4 Common Reasons
Safety prevent pressurized pipes & vessels from bursting Process Efficiency variation of pressure below or above a set-point will result in scrap rather than useable product in some manufacturing process Cost Saving preventing unnecessary expense of creating more pressure or vacuum than is required saves money Inferred Measurement of Other Variables rate of flow through a pipe level of fluid in a tank density of fluid how two or more liquids in a tank interface

4 What is pressure? The Same Weight, Different Pressure
Weight = 100lb 1 sq ins 100 sq ins 100 sq ins 1 sq ins Pressure increases as the force increases, or if the area over which the force is applied decreases. In the above example, although the force applied is the same in both cases, the pressure applied depends on the area over which the force is applied. Pressure = 1lb/in² Pressure = 100 lb/in²

5 What is pressure? Liquid & Gas Pressures
LIQUIDS The pressure exerted by a liquid is influenced by 3 main factors. The height of the liquid. The density of the liquid. The pressure on the surface of the liquid. GASES The pressure exerted by a gas is influenced by 2 main factors. 1. Volume of the gas container. 2. Temperature of the gas Note. Gases are compressible whereas liquids are not Liquids. Provided the density and surface pressure remain the same, then the pressure measured at a depth of 5 feet will be the same in a 5000 gallon tank as in a 50 gallon tank. If the liquid density doubles, then the pressure measured at a depth of 5 feet will also double. If the the pressure on the surface of the liquid increases, then the pressure measured at a depth of 5 feet would increase by the same amount. Gases Boyle’s law states that the pressure of a gas varies proportionally to the volume it occupies provided the temperature is held constant. That is, if you transfer the gas from a 5000ft³ tank at a pressure of 1000psia to a 1000ft³ tank, if you maintain the same temperature (e.g.300°C) the pressure would increase to 5000psia Charles’s law states that the pressure of a gas varies proportionally to the absolute temperature provided the volume is held constant. For instance, if in the above example we reduce the temperature to 14°C then the pressure would drop to 2500psia

6 Pressure terminology Engineering Units
Pressure is defined as FORCE applied over a unit AREA. P = F/A Examples of pressure units: Units of force per unit area Pascals Pa N / m2 (Newtons / square metre) psi lbs/in (Pounds / square inch) Bar Bar = 100,000 Pa Units referenced to columns of liquids ins. water gauge in H2O mm water gauge mm H2O ins. mercury in Hg mm mercury mm Hg Atmosphere atm Pressure applied by a 1 inch column of water at 20°C. 1 Torr = 1 mm Hg 12 inH2O = 1 ft H2O 1 psi = inH2O 1 inHg = 25.4 mm Hg 1 bar = psi 1 kg/cm2 = mbars Atmospheres Atmos. 1 Pascals Pa N / m Pa psi lbs/in psia Bar Bar Bar abs ins. water gauge in H2O in. H2O at 15°C mm water gauge mm H2O mm H2O at 15°C ins. mercury in Hg in Hg at 0°C mm mercury mm Hg 760mm Hg at 0°C Pressure applied by a 1 inch column of mercury with a density of g/cm³. Pressure exerted by the earth’s atmosphere at sea level (approximately psi)

7 Pressure terminology Reference Pressure
Gage Compound Range Absolute Barometric Range Atmospheric Pressure Approx psia Pressure Total Vacuum (Zero Absolute) Gage(psig) - Level of pressure relative to atmospheric Positive or negative in magnitude Absolute(psia) - based from zero absolute pressure - no mass Typical atm reference: psia Compound Range (psig) - Gage reading vacuum as negative value Differential(psid) - difference in pressure between two points

8 Pressure terminology Quiz
? Psia 19.7 5 psig Atm. Pressure 14.7 psia ? Psia ? Psig 5 psi vacuum 9.7 -5 Absolute Zero Total Vacuum Assume: Patm = 14.7psia; 28 inches H2O per psi 1000 in H2O = ___________ psi 35.71

9 Pressure terminology Measurable Pressures
The four most common types of measurable pressures used in the process control industries are: 1. Head Pressure or Hydrostatic Pressure. Pressure exerted by a column of liquid in a tank open to atmosphere, HEAD PRESSURE = HEIGHT x DENSITY 2. Static Pressure, Line Pressure, or Working pressure Pressure exerted in a closed system 3. Vapor Pressure The temperature at which a liquid boils, or turns into a vapor varies depending on the pressure. The higher the pressure, the higher the boiling point. 4. Vacuum Absolute pressure below atmospheric pressure ( a compound range gage transmitter will read a negative pressure) HEAD PRESSURE. If the height is measured in inches, and the Density is replaced by the Specific Gravity, then the Head Pressure will be in inches of water

10 Pressure terminology Measurable Pressure
Vapor pressure increases with temperature. Liquid boils when its vapor pressure equals atmospheric pressure. Lower Altitute (Sea Level) Typical Vapor Pressure Curve liquid Pressure(log) gas Higher Altitute T1 T2 Temperature

11 Inferring non-pressure variables Flow
Line Pressure Orifice Plate Infer Flow - flow is calculated (indirect measurement) You have a line pressure of 1000PSI. As the flow comes to the orificeplate the pressure will increase because of the blockage. As the process makes it through the blockage the pressure will drop and then gradually work its way back to 1000PSI. This pressure drop is inverse to the flow. In other words if the flow increases the pressure on the low side will go lower. The simple equation to convert the pressure drop in on the bottom of the slide. The “K” constant is made of many variables but is represented by one number in non-compensated flow application. These variables do change as flow changes and that is what the 3095 addresses. The square root of of DP is a characteristic of a head producing flow device, the relationship between the flow velocity and DP it creates. There are different places to measure this pressure drop. This diagram is flange taps. (k) - reflects the characteristics of the restrictor and flow conditions. Flow Restriction in Line cause a differential Pressure QV= K DP

12 Inferring non-pressure variables Flow
Theoritical equations come from 3 sources: Continuity Equation Flow into pipe equals flow out of pipe and is the same at all pipe cross sections (Conservation of Mass) Bernoulli’s Equation (Conservation of Energy for fluid in a pipe) Experimentally Determined Correction Factors Discharge Coefficient Gas Expansion Factor Qm= K DP

13 Inferring non-pressure variables Flow
Continuity Equation The volume flowing into a pipe equals the volume flowing out of pipe, assuming constant density A1v1 = A2v2 A = area of pipe cross section v = velocity A1V1 Flow A2V2 Flow v1 = A2/A1 x v2  d2/4 x D2/4 v1 = d2/D2 x v2  d/D =  v1 = 2 x v2

14 Inferring non-pressure variables Flow
Bernoulli’s Equation The total energy before the restriction in the pipe must equal the total energy after the restriction. P1 P2 Flow v1 D v2 d Three energies: Kinetic (1/2v2) Potential (gh) Static Pressure (P)  cancel - off for level pipe

15 Inferring non-pressure variables Flow
Before restriction After restriction common dP = ½  (v22 - v12) 2 /  x dP = v22 - v12 V12 = (2 x V2)2 2 /  x dP = v22 - 4 x v22 common As stated in the continuity equation, if the area is reduced the velocity must increase. If the velocity (kinetic energy) increases, the static pressure must decrease to keep total energy equal. So, with the potential energy equal before and after, (horizontal pipe), the difference in pressure is inversely proportional to the difference in velocity. 2 /  x dP = (1- 4) v22 subject v22 = (2 /  x dP) / (1- 4) Re-arranged

16 Inferring non-pressure variables Flow
v2 = [(2 /  x dP) / (1- 4)] ½ v2 = (2)½ x (1/)½ x 1/ (1- 4)½ x (dP)½ Qv2 = A2 x v2 Qv2 = (d2/4) x (2)½ x (1/)½ x 1/ (1- 4)½ x (dP)½ constant constant assumed constant velocity of approach constant - “E” As stated in the continuity equation, if the area is reduced the velocity must increase. If the velocity (kinetic energy) increases, the static pressure must decrease to keep total energy equal. So, with the potential energy equal before and after, (horizontal pipe), the difference in pressure is inversely proportional to the difference in velocity. Volumetric Flow Qv2 = k (dP/)½ Mass Flow  k (dP/)½ x  Qm2 = k (dP x )½

17 Inferring non-pressure variables Flow
Quiz: If an orifice plate creates a differential of 50 kPa at 30m³/s (i) What would be the differential at 10m³/s? (ii) What would be the flow rate at 30kPa differential? Qv = K DP Qv = K DP Qv1 DP1 --- = ---- Qv2 DP2 Qv1 DP1 --- = ---- Qv2 DP2 (i) Qv = K DP Qv1 DP1 ----- = Qv2 DP2 30/10 = 50/ DP2 DP2 = 5.6kPa (ii) 30/Qv2 = 50/ 30 Qv2 = 23.26m³/s 30/10 = 50/ DP2 30/Qv2 = 50/ 30 DP2 = 5.6kPa Qv2 = m³/s

18 Inferring non-pressure variables Level
Hydrostatic Pressure - The liquid will rise to the same level in each vessel regardless of its diameter & shape. Unit Area (eg. per cm2) Liquid D H P P P P Which shape gives higher pressure at the bottom of the vessel? Similar height of column will have same mass acting on the same unit area SAME PRESSURE

19 Inferring non-pressure variables Level
The hydrostatic pressure exerted by the column of liquid depends on the S.G. (or density) of the liquid and its vertical height. Density of liquid = D Average cross-section area of vessel = A Vertical height of liquid = H Volume of liquid, V = Total weight of liquid, M = = Pressure at the bottom of liquid = weight of liquid cross-section area = = H x A D x V D x A x H (D x A x H) / A D x H S.G x H With reference to inches or mm WATER 

20 Inferring non-pressure variables Level
P= force / area mass x g  g = gravitational acceleration r x volume  Density = mass/volume = r height x area P = r x g x height x area / area Phead = r x g x h Pascal

21 Inferring non-pressure variables Level
Cancelled off since both L & H sides of transmitter experience it. DP Transmitter at the bottom of the tank measures HEAD. HEAD = pressure at the bottom of a column of liquid with known relative density (S.G) S.G Ullage or Vapor XMTR H L 0% 100% Height Phead Phead = S.G x Height Height = Phead / S.G

22 Inferring non-pressure variables Level
Quiz: Open Tank What is the level if Pmax = 120 inH2O, s.g.= 1.2? ? Height = Phead / S.G Height = 120 / 1.2 XMTR Height = 100 inches L H

23 Inferring non-pressure variables Level
Quiz: Closed Tank Dry leg: no fluid in low side impulse piping, or leg Ph = 105 psi Pl = 100 psi What is level if s.g. = 1.0? Ptop= Ullage Phead dP = 5 psi = 5 x 28 inH2O XMTR Height = 140 / 1.0 L H Height = 140 inches

24 Inferring non-pressure variables Density
Ptop Pbottom = Ptop = Pbottom - Ptop = Hence, S.G = S.G X h2 Ptop h1 S.G X h1 Phead(top) H S.G (h2 - h1) h2 Phead(bottom) H Pbottom diff. Pressure / dist. betw. taps To measure Relative Density (Specific Gravity) Can use one differential transmitter with two remote seals at the two points. Liquid level must be above the Top transmitter tap.

25 Inferring non-pressure variables Density
Quiz: Determined the S.G of the process fluid if Ptop = 20 psi Pbottom = 22 psi Distance between taps = 50 inches Assuming 1 psi = 28”H2O Ullage Ptop 50” H DP = (22 -20) = 2 psi = 56”H2O H Pbottom S.Gprocess = DP / dist. betw. Taps = 56 / 50 = 1.12

26 Inferring non-pressure variables Interface
Indirectly measures liquid Interface Pbottom Ptop L H Remote Seal Vapor 0% 100% SG1 SG2 Dist. Betw. Taps (h1 - h2) h2 SGf Total Liquid level must always be above the Top transmitter tap. h1 Interface is the separation boundary between two immersible liquid. SG1 - Lower specific gravity SG2 - higher specific gravity Both the SGs must be predetermined and should remain constant for accurate measurement. Can use one differential transmitter with two remote seals at the two points. At 0% Liquid Interface (4mA) DP = Hside - Lside = (SG1*h1) - [(SGf*(h1-h2)) + (SG1*h2)]

27 Inferring non-pressure variables Interface
Indirectly measures liquid Interface Remote Seal Vapor SG1 Ptop h2 SGf 100% Total Liquid level must always be above the Top transmitter tap. h1 Dist. Betw. Taps (h1 - h2) 0% L H Pbottom SG2 At 100% Liquid Interface (20mA) DP = Hside - Lside = [SG2*(h1-h2) + SG1*h2)] - [(SGf*(h1-h2)) + (SG1*h2)]

28 Inferring non-pressure variables Interface
Application Example: Transmitter calibrated from 120”H2Oto 132”H2O Determine % of interface of Liquid A with respect to Liquid B Vapor 0% 100% SG1= 1.0 SG2= 1.1 Pbottom Ptop L H Remote Seal 10 ft Liquid A Liquid B If transmitter reads 123 inH2O % interface = (3/12) * 100% = 25% 123 inH2O

29 Pressure measurement technology Pressure Gauges
Barometer Used to measure Barometric Pressure Reference is 0 psia, due to low vapor pressure of Hg. General operating principle: Tube completely filled with mercury & Invert into the container filled with mercury. The mercury level in the tube will drop until it reaches an equilibrium. This equilibrium height is a measure of atmospheric pressure. What is the barometric Pressure? Phead Patm Phead = Patm Barometric Pressure = Atmospheric Pressure 29.9 inHg

30 Pressure measurement technology Pressure Gauges
Manometers U-tube with one side reference, one side measured pressure H How to check for dP ? dP = H (SGfill fluid - SGprocess fluid) Reference side can be: Sealed (AP reference) Open to atmosphere(GP reference) Connected to reference pressure(DP reference) Typically used for low pressures, non process control

31 Pressure measurement technology Pressure Gauges
Mechanical The mechanical element techniques convert applied pressure into displacement. The displacement may be converted into electrical signal with help of Linear Variable Displacement Transformer (LVDT).

32 Pressure measurement technology Pneumatic Pressure Cells
Pneumatic Controller Relay’s modulated output is the controller output which is usually a pneumatic signal that adjusts the final control element (Control valve) Output to Actuator (or Relay) Constant flowrate maintained (Compressed air) Nozzle Flapper Bourdon Tube Process Pressure It is a FORCE BALANCE pressure transmitter (Closed loop feedback device). In a force balance unit, pressure displaces the sensing element (diaphragm). The amount of displacement is detected and the element is returned to a null or zero displacement position by a restoring force pneumatically. Thus a pneumatic pressure will be maintained exactly proportional to differential pressure and is used as a standard output signal (3 to 15 psi).

33 Pressure measurement technology Pneumatic Pressure Cells
Pressure Transmitter Produce a linear output proportional to input pressure Zero Scale: Full Scale: 3 psig 15 psig Disadvantages Reconfiguration costly Losses occur over long piping runs Performance levels are not comparable to electronic instrumentation It is a FORCE BALANCE pressure transmitter (Closed loop feedback device). In a force balance unit, pressure displaces the sensing element (diaphragm). The amount of displacement is detected and the element is returned to a null or zero displacement position by a restoring force pneumatically. Thus a pneumatic pressure will be maintained exactly proportional to differential pressure and is used as a standard output signal (3 to 15 psi).

34 Pressure measurement technology Electronic Pressure Transmitters
Made up of 2 main elements: Transducer - Electronic sensor module that registers process variable and outputs a corresponding usable electrical signal eg. resistance, millivolts, capacitance, etc. Electronics - Convert transducer output to a standard output signal eg mA, V dc, digital signal, etc.

35 Pressure measurement technology Electronic Pressure Transmitters
(Standard signals) Example of Application Transmitter configured to operate from: 0 to 50 psi Electronic Output: 4 to 20 mA This mean 0% reading (0 psi) represents 4 mA and 100% reading (50 psi) represents 20 mA. Signal To Controller Transmitter Signal from sensor module (Transducer) Sensing Diaphragm Process Variable (Line / Static Pressure) We normally use a transmitter to measure the process signals. The transmitter changes the output of the primary element into a control signal that can be utilized by the process controller; typically a current, voltage, HART compliant, or digital signal. The primary element senses a change in the value, quantify, or quality of the process variable and provides an output in the form of a change in current, voltage, motion, force, pressure, etc. The sensor output is generally a very low level signal that must be amplified, conditioned, or converted before it is useful in a process control system. Other devices are used to change signals from one type to another. These units are often called transducers or converters; and they are used to match or provide the necessary signal type to be compatible with another device. We will discuss transmitters for the “BIG FOUR”, those being pressure, temperature, level, and flow. Some other common measurements are oxygen, pH, conductivity, position, weight, and composition. What will be the output current at 25 psi reading? 4 + (25/50)*16 = 12 mA

36 Pressure measurement technology Electronic Pressure Sensor Modules
Characterized by the type of sensing element: Variable capacitance Variable Resistance (Wheatstone bridge) Strain gauge Thin -film strain gauge Diffused, strain gauge Variable inductance Variable reluctance Vibrating wire Piezoelectric

37 Pressure measurement technology Electronic Pressure Sensor Modules
Variable Capacitance Process pressure transmitted thru isolating diaphragm Distortion of sensing diaphragm proportional to the differential pressure Position of sensing diaphragm detected by capacitor plates Differential capacitance translated to 4-20mA or 10-50mA output dc signal. In the DP Sensor, process pressure is transmitted through the isolating diaphragm and fill fluid to the sensing diaphragm in the center of the capacitance cell. Capacitor plates on both sides of the sensing diaphragm detect its position. The differential capacitance between the sensing diaphragm and the capacitor plates is proportional to process pressure.

38 Pressure measurement technology Electronic Pressure Sensor Modules
Variable Resistance / Piezo-Resistive Process pressure transmitted thru isolating diaphragm Very small distortion in sensing diaphragm Applies strain to a wheatstone bridge circuit Change in resistance translated to 4-20mA or 1-5V dc signal GP XMTRs - ref. side of sensor exposed to atm. Pressure AP XMTRs - sealed vacuum reference. The AP Sensor is fabricated utilizing a processing method called Chemical Vapor Decomposition (CVD). Resistive sensors have 4 resistors in the diaphragm, connected as a wheatstone bridge.The resistors are formed by vapour deposition in a thin film on top of a silicon substrate.(Thin-film strain gauge) OR diffusion / embedding inside the silicon. (Piezoresistive strain gauges)- solid state device. Hydraulically (sealed fluid) connected to the high pressure side of the transmitter. Process pressure is transmitted through the fill fluid to the sensing element, creating a very small deflection of the silicon substrate. The resulting strain on the substrate changes the bridge resistance in proportion to the the pressure applied. (Bridge unbalanced) GP Sensor is fabricated in the same technique as AP sensor, however the reference side of the silicon substrate is vented to atmosphere instead of concealed in the vacuum. Thin Film Strain Gauge Diffused Strain Gauge

39 Pressure measurement technology Electronic Pressure Sensor Modules
Amplifier & electronics Control Signal Piezoelectric Crystal Diaphragm Process Pressure Piezoelectric Piezoelectric crystal is a natural or a synthetic crystal that produces a voltage when pressure is applied to it. Voltage produce by crystal increases with increases in pressure and vice-versa. The produced small voltage is then amplified to a standard control signal.

40 Pressure measurement technology Electronic Pressure Sensor Modules
Variable Inductance Inductance is the opposition to a change in current flow Alternating current pass through the coil Elastic element connected to core Applied pressure deflects elastic element Position of core changes relative to coil resulting in change in inductance Resistor connected in series with inductor to measure change in voltage.

41 Pressure measurement technology Electronic Pressure Sensor Modules
Variable Reluctance Reluctance is a property of magnetic circuit A moving magnetic element located between two coils Coil turn electromagnet when excited by AC source Position of element with respect to the coils determines differential magnetic reluctance Thus differential inductance within the coils A bridge is used to measure changes in a circuit

42 Pressure measurement technology Electronic Pressure Sensor Modules
Vibrating Wire Wire located in magnetic field vibrate when current pass through it Wire movement within field induces current into it Induced voltage amplified as output signal Vibration frequency depends on wire tension Elastic element connected to wire. Frequency of wire vibration become a function of measured pressure Direct digital output signal

43 Pressure measurement technology Electronic Pressure Sensor Modules
Output Electronics Sensor Module Output Electronics Sensor Module Diaphragm Seal Sensor (transducer) module is part of the transmitter. Sensor will become active only when the transmitter is powered. (Attenuation) Output Electronics in the transmitter translates the userable electrical signal from the sensor into a standard output signal.

44 Pressure calibrators ISO Requirement
ISO Require calibration device to be 4 times more accurate than the accuracy of the instrument being calibrated. If the reference accuracy of a 3051C transmitter is 0.075% of span, What should the accuracy of the C/V pressure source be? the equipment for calibrating the pressure source? If the diameter of the ball on a dead weight tester is 0.75 inches. The weight of a plate is 723g. What is the pressure required to freely float that plate on the dead weight tester (g/cm2)? % % 2.55 g/cm2

45 Exercise 1. If the atmospheric pressure drop by 0.1 % and the line pressure remains unchanged, what changes will occur in the readings? (A) AP reading will change. (B) GP reading will change. (C) Both reading will change. (D) Both reading will not change. [ ] 2. If a customer wants to measure vacuum, what type of transmitter should be used? (A) AP (B) DP (C) GP [ ] Liquid flow Line pressure = 80 psig 94.7psi 80.psi GP Transmitter AP Transmitter 1. B 2 C

46 Exercise Write down the readings in (psi) that are recorded by the transmitters in the above application (Atmosphere = 14.7 psi). 3. Differential Pressure Transmitter (a): [ ] 4. Gage Pressure Transmitter (b): [ ] 5. Absolute Pressure Transmitter (c): [ ] 50 psig 80 psig c a b = 30 psi 4. 50 psi = 94.7 psi

47 Exercise S.G of Process Temp + Pressure = 1.0 P2 P1 S.G. = 13.6 200mm (Note 1 mm H2O = 9.8 Pa) 6. What is the differential pressure (P1 - P2) in kPa being applied to the manometer in the the above application ? DP = 200 ( ) = 2520 mm H2O = 2520 * 9.8/1000 kPa = 24.7 kPa


Download ppt "Level 1 Fundamental Training Pressure 1."

Similar presentations


Ads by Google