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SURVIVAL ANALYSIS PRESENTED BY: DR SANJAYA KUMAR SAHOO PGT,AIIH&PH,KOLKATA.

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Presentation on theme: "SURVIVAL ANALYSIS PRESENTED BY: DR SANJAYA KUMAR SAHOO PGT,AIIH&PH,KOLKATA."— Presentation transcript:

1 SURVIVAL ANALYSIS PRESENTED BY: DR SANJAYA KUMAR SAHOO PGT,AIIH&PH,KOLKATA

2 SURVIVAL SURVIVAL: It is the probability of remaining alive for a specific length of time. If our point of interest : prognosis of disease i.e 5 year survival e.g. 5 year survival for AML is 0.19, indicate 19% of patients with AML will survive for 5 years after diagnosis

3 e.g For 2 year survival: S= A-D/A= 6-1/6 =5/6 =.83=83%

4 CENSORING: Subjects are said to be censored if they are lost to follow up drop out of the study, if the study ends before they die or have an outcome of interest. They are counted as alive or disease-free for the time they were enrolled in the study. In simple words, some important information required to make a calculation is not available to us. i.e. censored.

5 Types of censoring: Three Types of Censoring Right censoring Left censoringInterval censoring

6 Right Censoring: Right censoring is the most common of concern. It means that we are not certain what happened to people after some point in time. This happens when some people cannot be followed the entire time because they died or were lost to follow-up or withdrew from the study.

7 Left censoring is when we are not certain what happened to people before some point in time. Commonest example is when people already have the disease of interest when the study starts. Left Censoring:

8 Interval/random censoring is when we know that something happened in an interval (i.e. not before starting time and not after ending time of the study ), but do not know exactly when in the interval it happened. For example, we know that the patient was well at time of start of the study and was diagnosed with disease at time of end of the study, so when did the disease actually begin? All we know is the interval. Interval/Random Censoring

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10 10 What is survival analysis? Statistical methods for analyzing longitudinal data on the occurrence of events. Events may include death,onset of illness, recovery from illness (binary variables) or failure etc. Accommodates data from randomized clinical trial or cohort study design.

11 Need for survival analysis: Investigators frequently must analyze data before all patients have died; otherwise, it may be many years before they know which treatment is better. Survival analysis gives patients credit for how long they have been in the study, even if the outcome has not yet occurred. The Kaplan–Meier procedure is the most commonly used method to illustrate survival curves.

12 12  Estimate time-to-event for a group of individuals: -such as time until death for heart transplant patients(mortality studies) -Time of remission for leukemic patients(in therapy trials)  To compare time-to-event between two or more groups: -such as treated vs. placebo MI patients in a randomized controlled trial.  To assess the prognostic co-variables:(Survival models) -such as: weight, insulin resistance, or cholesterol influence survival time of MI patients? Objectives of survival analysis:

13 13 Why use survival analysis? 1. Why not compare mean time-to-event between your groups using a t-test or linear regression? -- ignores censoring 2. Why not compare proportion of events in your groups using risk/odds ratios or logistic regression? --ignores time

14 14 Survival Analysis: Terms Time-to-event: The time from entry into a study until a subject has a particular outcome. Censoring: Subjects are said to be censored if they are lost to follow up or drop out of the study, or if the study ends before they die or have an outcome of interest. They are counted as alive or disease-free for the time they were enrolled in the study.

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16 Importance of censoring in survival analysis? Example: we want to know the survival rates of a disease in two groups and our outcome interest is death due the disease? group-1 group-2 Time in months event 5death 6 8 9 10death 12death 16death Time in months event 9death 8 12death 20death 6 7 4 This data can’t be analysed by survival analysis method.As there is no censored data.In this case as all pts. died so we can take mean time of death and know which group has more survival time Also data shouldn’t have >50% censored data

17 SURVIVAL FUNCTION: Let T= Time of death(disease) Survival function S(t)=F(t) =prob.(alive at time t) =prob.(T>t) In simple terms it can be defined as No. of pts. Surviving longer than ‘t’ S(t)= ---------------------------------------------- Total no. of pts.

18 18 Kaplan-Meier estimate of survival function: Kaplan-Meier estimate of survival function: Calculate the survival of study population. Easy to calculate. Non-parametric estimate of the survival function. Commonly used to compare two study populations. Applicable to small,moderate and large samples.

19 Kaplan-Meier Estimate: The survival probability can be calculated in the following way: P 1 =Probability of surviving for atleast 1 day after transplant P 2 =Probability of surviving the second day after having survived the first day. P 3 = Probability of surviving the third day after having survived the second day

20 To calculate S(t) we need to estimate each of P 1, P 2, P 3 ……. P t probability of survival at time ‘t’ calculated as: No. of pts. Followed for atleast (t-1)days and who also survived day t P t = -------------------------------------------------------------------------- No. of patients alive at the end of day (t-1) S(t) = P 1 x P 2 x P 3 …….x P t

21 Example: 10 Tumor patients(remission time) Event Time (T) Number at Risk ni Number of Events di (ni – di)/ni 31019/10 4+ 5.7+ 6.5725/79/10*5/7 8.4+ 10413/49/10*5/7*3/4 10+ 12211/29/10*5/7*3/4*1/2 151000 One patient's disease progressed at 3 month and another at 6.5, 10, 12 & 15months, and they are listed under the column “Number of Events” (di) and ni denotes No. of patients at risk at that point of time. Then, each time an event or outcome occurs, probability of survival at that point of time and survival times(t) calculated. In this method first step is to list the times when a death or drop out occurs, as in the column “Event Time”. Denotes censored data

22 Beginning of study End of study  Time in months  Subject B Subject A Subject C Subject D Subject E Survival Data (right-censored) 1. subject E dies at 4 months X 0

23 100%  Time in months  Corresponding Kaplan-Meier Curve Probability of surviving to 4 months is 100% = 5/5 Fraction surviving this death = 4/5 Subject E dies at 4 months 4

24 Beginning of studyEnd of study  Time in months  Subject B Subject A Subject C Subject D Subject E Survival Data 2. subject A drops out after 6 months 1. subject E dies at 4 months X 3. subject C dies at 7 months X

25 100%  Time in months  Corresponding Kaplan-Meier Curve subject C dies at 7 months Fraction surviving this death = 2/3 7 4

26 Beginning of studyEnd of study  Time in months  Subject B Subject A Subject C Subject D Subject E Survival Data 2. subject A drops out after 6 months 4. Subjects B and D survive for the whole year-long study period 1. subject E dies at 4 months X 3. subject C dies at 7 months X

27 12 100%  Time in months  Corresponding Kaplan-Meier Curve Rule from probability theory: P(A&B)=P(A)*P(B) if A and B independent In kaplan meier : intervals are defined by failures(2 intervals leading to failures here). P(surviving intervals 1 and 2)=P(surviving interval 1)*P(surviving interval 2)  Product limit estimate of survival = P(surviving interval 1/at-risk up to failure 1) * P(surviving interval 2/at-risk up to failure 2) = 4/5 * 2/3=.5333 0 The probability of surviving in the entire year, taking into account censoring = (4/5) (2/3) = 53%

28 Properties of survival function: 1.Step function 2.Median survival time estimate(i.e 50% of pts. survival time)

29 Median survival? 12 &22 Which has better survival? (2 nd one) What proportion survives 20days?(in 1 st graph=around 35% and in 2 nd onearound 62%)

30 Limitations of Kaplan-Meier: 1.Must have >50% uncensored observations. 2.Median survival time. 3. Doesn’t control for covariates. 4.Assumes that censoring occurs independent of survival times.(what if the person who develops adverse effect due to some treatment and forced to leave or died?)

31 t2 t2 t1t1 Median survival time=( t 1 + t 2 )/2

32 Comparison between 2 survival curve Don’t make judgments simply on the basis of the amount of separation between two lines

33 Comparison between 2 survival curve: methods may be used to compare survival curves. Logrank statistic. Breslow Statistics Tarone-Ware Statistics

34 LOGRANK TEST: The log rank statistic is one of the most commonly used methods to learn if two curves are significantly different. This method also known as Mantel-logrank statistics or Cox-Mantel- logrank statistics. The logrank statistic is distributed as χ 2 with a H 0 that survival functions of the two groups are the same

35 LOG-RANK TEST Emphasizes failures in the tail of the survival curve,where The no. at risk decreases over time,yet equal weight is given to each failure time. USUALLY GIVE STATISTICALLY SIGNIFICANT RESULTS BRESLOW STATISTICS Gives greater weight to early observations. It is less sensitive than the Log-Rank test to late events when few subjects remain in the study. TARONE-WARE STATISTICS Provide a compromise between the Log-Rank test and Breslow Statistics with an intermediate weighting scheme.This test maintains power across a wider range of alternatives than do the other two tests. USUALLY APPLIED.

36 Hazard function: Opposite to survival function Hazard function is the derivative of the survival function over time h(t)=dS(t)/dt instantaneous risk of event at time t (conditional failure rate) It is the probability that a person will die in the next interval of time, given that he survived until the beginning of the interval.

37 Hazard function Hazard function given by h(t,x1,x2…x5)=ƛ 0 (t) eb1x1+b2x2+….b5x5 ƛ 0 is the baseline hazard at time t i.e. ƛ0(t) For any individual subject the hazard at time t is hi(t). hi(t) is linked to the baseline hazard h0(t) by log e {hi(t)} = log e {ƛ0(t)} + β 1 X1 + β 2 X2 +……..+ βpXp where X1, X2 and Xp are variables associated with the subject

38 38 Cox-Proportional hazards: Hazard functions should be strictly parallel! Produces covariate-adjusted hazard ratios! Hazard for person j (eg a non-smoker) Hazard for person i (eg a smoker) Hazard ratio

39 39 The model: binary predictor This is the hazard ratio for smoking adjusted for age.

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41 Importance Provides the only valid method of predicting a time dependent outcome, and many health related outcomes related to time. Can be interpreted in relative risk or odds ratio Gives survival curves with control of confounding variables. Can be used with multiple events for a subject.

42 Take Home Message survival analysis Estimate time-to-event for a group of individuals and To compare time-to-event between two or more groups. In survival data is transformed into censored and uncensored data all those who achieve the outcome of interest are uncensored” data those who do not achieve the outcome are “censored” data

43 Take Home Message The Kaplan-Meier method uses the next death, whenever it occurs, to define the end of the last class interval and the start of the new class interval. Log-Rank test used to compare 2 survival curves but does not control for confounding. For control for confounding use another test called as ‘Cox Proportional Hazards Regression.’


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