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BELLWORK – DAY #1 Solve. 1. x + 5 = 9 2. r – 34 = 72 3. 124 = e – 39 x = 4 x = 106 x = 163.

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Presentation on theme: "BELLWORK – DAY #1 Solve. 1. x + 5 = 9 2. r – 34 = 72 3. 124 = e – 39 x = 4 x = 106 x = 163."— Presentation transcript:

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2 BELLWORK – DAY #1 Solve. 1. x + 5 = 9 2. r – 34 = 72 3. 124 = e – 39 x = 4 x = 106 x = 163

3 BELLWORK – DAY #2 What 4-digit number am I? I am greater than 4,000 and less than 5,000. I am greater than 4,000 and less than 5,000. The sum of my hundreds digit and my ones digit is 9. The sum of my hundreds digit and my ones digit is 9. Twice my tens number is 2 more than my thousands digit. Twice my tens number is 2 more than my thousands digit. The product of my hundreds digit and my ones digit is 0. The product of my hundreds digit and my ones digit is 0. I am not an even number. I am not an even number. 4,039

4 BELLWORK – DAY #3 Solve. 1. p – 13 = 9 2. m – 44 = 18 3. 94 = k – 39 p = 22 m = 62 k = 133

5 MA.7.A.3.4 We will solve one step equations involving addition, subtraction, multiplication and division. MA.7.A.3.3 Sunshine State Standards

6 Vocabulary Multiplication Property of Equality Division Property of Equality

7 Like addition and subtraction, multiplication and division are inverse operations. They “undo” each other. ÷

8 If a variable is divided by a number, you can often use multiplication to isolate the variable. Multiply both sides of the equation by the number.

9 Solve the equation = 13. Check your answer. Additional Example 1: Using the Division Property of Equality h2h2 h2h2 = 13 h2h2 = 13(2) (2) h = 26 Check h2h2 = 13 13 = 13 ? Think: h is divided by 2, so multiply both sides by 2 to isolate h. Substitute 26 for h. 26 is a solution. 26 2 ? = 13

10 Check It Out: Example 1A Solve the equation. Check your answer. x = 30(5) x = 150 Check: x5x5 = 30 30 = 30 150 5 ? = 30 X5X5

11 Check It Out: Example 1B Solve the equation. Check your answer. j = 9(8) j = 72 Check: 9 = 9 j ÷ 8 = 9 72 ÷ 8 = 9 ? j ÷ 8 = 9

12 RUBRIC ON ONE STEP EQUATIONS 12345 No understanding Little understanding Some understanding Good understanding Complete understanding No comprenderPoca comprension Una Cierta comprension Buena comprension Comprension Completa Pa gen okenn konpreyansyon Ti konpreyansyon Kek konpreyansyon Bon konprannRanpli konpreyansyon

13 If a variable is multiplied by a number, you can often use division to isolate the variable. Divide both sides of the equation by the number.

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15 Solve the equation 51 = 17x. Check your answer. Additional Example 2: Solving an Equation by Division 51 = 17x 17 3 = x Check 51 = 17x Think: x is multiplied by 17, so divide both sides by 17 to isolate x. Substitute 3 for x. 3 is a solution. 51 = 17(3) ? 51 = 51 ?

16 Check It Out: Example 2A Solve each equation. Check your answer. y = 76 y = 4 Check 76 = 19y 76 = 19(4) ? 76 = 76 19 76 = 19y

17 Check It Out: Example 2B Solve each equation. Check your answer. t = 180 t = 15 Check t · 12 = 180 15 · 12 = 180 ? 180 = 180 12 t · 12 = 180

18 RUBRIC ON ONE STEP EQUATIONS 12345 No understanding Little understanding Some understanding Good understanding Complete understanding No comprenderPoca comprension Una Cierta comprension Buena comprension Comprension Completa Pa gen okenn konpreyansyon Ti konpreyansyon Kek konpreyansyon Bon konprannRanpli konpreyansyon

19 Trevor’s heart rate is 78 beats per minute. How many times does his heart beat in 10 seconds? Additional Example 3: Health Application Use the given information to write an equation, where b is the number of heart beats in 10 seconds. If you count your heart beats for 10 seconds and then multiply that by 6, you can find your heart rate in beats per minute.

20 Beats in 10s times 6 = beats per minutes Additional Example 3 Continued b · 6 = 78 6b = 78 6 b = 13 Trevor’s heart beats 13 times 10 seconds. Think: b is multiplied by 6, so divide both sides by 6 to isolate b.

21 Check It Out: Example 3A A museum charges $7 per person for admission. If a group paid a total of $105 for admission, how many people were in the group? There were 15 people in the group. 7 · p = 105 7p = 105 7 7 p = 15

22 Check It Out: Example 3B During a stock car race, one driver is able to complete 68 laps in 1 hour. How many laps would he finish in 15 minutes? The number of laps in 15 min times 4 will give you the total number of laps in 1 hour.

23 x 4 = 68 4x = 68 4 4 x = 17 He will finish 17 laps in 15 minutes. Check It Out: Example 3B Continued

24 RUBRIC ON ONE STEP EQUATIONS 12345 No understanding Little understanding Some understanding Good understanding Complete understanding No comprenderPoca comprension Una Cierta comprension Buena comprension Comprension Completa Pa gen okenn konpreyansyon Ti konpreyansyon Kek konpreyansyon Bon konprannRanpli konpreyansyon

25 Lesson Quiz: Part I Solve the equation. Check your answer. 1. 12 = 4x 2. 18z = 90 3. 12 = 4. 840 = 12y 5. z = 5; 18  5 = 90 x = 3; 12 = 4  3 y = 70; 840 = 12  70 x4x4 h 22 = 9 x = 48; 12 = x4x4 h = 198; = 9 198 22

26 Lesson Quiz: Part II 6. The cost of each ticket at the carnival was $0.25. Li bought $7.50 worth of tickets. How many tickets did she buy? 30

27 1. Solve the equation. Check your answer. 15 = A.x = ; = 3C. x = 18; 15 + 3 = 18 B.x = 5; = 5D. x = 45; 15 = Lesson Quiz for Student Response Systems 1515 15 3 15 5 45 3 x3x3

28 2. Solve the equation. Check your answer. = 7 A.f = ; 21 = 7 3C. f = 28; 28 = 7 4 B.f = 3; = 7D. f = 147; = 7 Lesson Quiz for Student Response Systems 1313 21 3 147 21 f 21

29 3. Solve the equation. Check your answer. 45 = 9x A. x = 3; 45 = 3 15 B. x = 5; 45 = 9 5 C. x = 9; 45 = 5 9 D. x = 15; 45 = 15 3 Lesson Quiz for Student Response Systems

30 4. Solve the equation. Check your answer. 12z = 72 A. z = 2; 2 36 = 72 B. z = 3; 3 24 = 72 C. z = 4; 4 18 = 72 D. z = 6; 12 6 = 72 Lesson Quiz for Student Response Systems

31 5. The cost of one pen is $0.75. Joe bought $9.75 worth of pens. How many pens did he buy? A. 12 pens B. 13 pens C. 14 pens D. 15 pens Lesson Quiz for Student Response Systems


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