1. 2 pt 3 pt 4 pt 5pt 1 pt 2 pt 3 pt 4 pt 5 pt 1 pt 2pt 3 pt 4pt 5 pt 1pt 2pt 3 pt 4 pt 5 pt 1 pt 2 pt 3 pt 4pt 5 pt 1pt Chapter 9

2. 1pt Find the probability of selecting a vowel from the letters F, G, H, and I. Express the probability as a fraction, decimal, and a percent. The event vowel has one outcome, I, out of four possible outcomes.

3. 1pt Find the probability of selecting a vowel from the letters F, G, H, and I. Express the probability as a fraction, decimal, and a percent. The event vowel has one outcome, I, out of four possible outcomes. P(vowel) = number of favorable outcomes 1414 total number of possible outcomes P(vowel) = = 0.25 = 25%Write as a fraction, decimal, and percent. 1414

4. 2pt Jacques has 1 blue shirt, 5 white shirts, 3 green shirts, and 2 brown shirts. He selects a shirt from his closet with his eyes shut. Find each probability. P(white shirt)

5. 2pt Jacques has 1 blue shirt, 5 white shirts, 3 green shirts, and 2 brown shirts. He selects a shirt from his closet with his eyes shut. Find each probability. P(white shirt) There are 11 possible outcomes. The event white shirt has 5 favorable outcomes. P(white shirt) = number of favorable outcomes 5 11 total number of possible outcomes

6. 3pt A player makes 7 free throws out of 12 attempts. Based on this, what is the experimental probability of this player making a free throw?

7. 3pt A player makes 7 free throws out of 12 attempts. Based on this, what is the experimental probability of this player making a free throw? P(free throw) = number of throws made total number of attempted free throws 7 12 The experimental probability of making a free throw is. 7 12

8. 4pt A manufacturer of computer parts checks 100 parts each day. On Monday, two of the checked parts are defective. a. What is the experimental probability that a part is defective? number of defective parts total number of parts checked P(defective part) =

9. 4pt a. What is the experimental probability that a part is defective? number of defective parts total number of parts checked P(defective part) = 2 100 The experimental probability is. 1 50 1 50 Simplify.= A manufacturer of computer parts checks 100 parts each day. On Monday, two of the checked parts are defective.

10. 5pt b. Predict the probable number of defective parts in Monday’s total production of 1,250 parts. Let x represent the predicted number of defective parts. Write a proportion. 1 50 defective total = x 1,250 defective total 1(1,250) = 50x Write the cross products. 1,250 = 50x Simplify. A manufacturer of computer parts checks 100 parts each day. On Monday, two of the checked parts are defective. The experimental probability is. 1 50

11. 5pt You can predict 25 parts out of 1,250 to be defective. 25 = x Simplify. Divide each side by 50.= 50x 50 1,250 50 Write a proportion. 1 50 defective total = x 1,250 defective total 1(1,250) = 50x Write the cross products. 1,250 = 50x Simplify.

12. 1pt Use the table below to determine the experimental probability of landing on heads for this experiment.

13. 1pt Use the table below to determine the experimental probability of landing on heads for this experiment. Answer:The experimental probability of landing on heads in this case is

14. 2pt Suppose you can go west or northwest by train, bus, or car. a. Draw a tree diagram to show the sample space. Vehicle Train Bus Car

15. 2pt Suppose you can go west or northwest by train, bus, or car. a. Draw a tree diagram to show the sample space. There are 6 possible outcomes. Direction West Northwest West Northwest West Northwest Outcomes Train, West Train, Northwest Bus, West Bus, Northwest Car, West Car, Northwest Vehicle Train Bus Car

16. 3pt There are 6 possible outcomes. Direction West Northwest West Northwest West Northwest Outcomes Train, West Train, Northwest Bus, West Bus, Northwest Car, West Car, Northwest Vehicle Train Bus Car b. What is the probability of a random selection that results in a bus trip west?

17. 3pt There is one favorable outcome (bus, west) out of six possible outcomes. The probability is. 1616 There are 6 possible outcomes. Direction West Northwest West Northwest West Northwest Outcomes Train, West Train, Northwest Bus, West Bus, Northwest Car, West Car, Northwest Vehicle Train Bus Car b. What is the probability of a random selection that results in a bus trip west?

18. 4pt How many kinds of coin purses are available if the purses come in small or large sizes and colors red, blue, yellow, and black? Use the counting principle. SizesColors smallred largeblue yellow black

19. 4pt How many kinds of coin purses are available if the purses come in small or large sizes and colors red, blue, yellow, and black? Use the counting principle. SizeColor number of choices  number of choices 2  4= 8 There are 8 different kinds of coin purses available. SizesColors smallred largeblue yellow black

20. 5pt A box contains the same number of green marbles, orange marbles, and blue marbles. You draw one marble, replace it, and draw a second marble. What is the probability that both marbles you draw are blue?

21. 5pt A box contains the same number of green marbles, orange marbles, and blue marbles. You draw one marble, replace it, and draw a second marble. What is the probability that both marbles you draw are blue? Since of the marbles are blue, the probability of drawing a blue marble is. 1313 1313 P(blue, then blue)= P(blue)  P(blue) Selecting blue is the first and second event. Substitute. =  1313 1313 Multiply. = 1919 The probability that both marbles will be blue is. 1919

22. 1pt You select a card at random from those having A, E, I, O, U, P, C. The card has the letter E. Without replacing the E card, you select a second card. Find the probability of selecting a card that does not have a vowel. There are 6 cards remaining after selecting an E card.

23. 1pt You select a card at random from those having A, E, I, O, U, P, C. The card has the letter E. Without replacing the E card, you select a second card. Find the probability of selecting a card that does not have a vowel. There are 6 cards remaining after selecting an E card. P(not vowel) = 2626 number of cards not a vowel number of cards remaining Simplify. 1313 P(not vowel) = The probability of selecting a non-vowel for the second card is. 1313

24. 2pt A bag contains 3 red marbles, 4 white marbles, and 1 blue marble. You draw one marble. Without replacing it, you draw a second marble. What is the probability that the two marbles you draw are red and white?

25. 2pt A bag contains 3 red marbles, 4 white marbles, and 1 blue marble. You draw one marble. Without replacing it, you draw a second marble. What is the probability that the two marbles you draw are red and white? The two events are dependent. After the first selection, there are 7 marbles to choose from. P(red, then white)= P(red)  P(white after red) Use the formula for dependent events. Substitute. =  3838 4747 Simplify. = 3 14 The probability that the two marbles are red and white is. 3 14 Multiply.= 12 56

26. 3pt An experiment consists of spinning this spinner once. Find the probability of each event. Calculating Theoretical Probability P(4)

27. 3pt An experiment consists of spinning this spinner once. Find the probability of each event. Calculating Theoretical Probability P(4) The spinner is fair, so all 5 outcomes are equally likely: 1, 2, 3, 4, and 5. 1 5 P(4) = = number of outcomes for 4 5

28. 4pt P(both tails) An experiment consists of flipping two coins. Find the probability of each event.

29. 4pt P(both tails) There is 1 outcome in the event “both tails”: (T, T). P(both tails) = 1 4 An experiment consists of flipping two coins. Find the probability of each event.

30. 5pt Give the probability for each outcome.

31. 5pt Give the probability for each outcome. Three of the eight sections of the spinner are labeled 1, so is a reasonable estimate. P(1) = 3 8 3838

32. 1pt A marble is randomly drawn out of a bag and then replaced. The table shows the results after fifty draws. Estimate the probability of drawing a green marble. OutcomeGreenRedYellow Draw121523

33. 1pt A marble is randomly drawn out of a bag and then replaced. The table shows the results after fifty draws. The probability of drawing a green marble is about 0.24, or 24%. probability  number of green marbles drawn total number of marbles drawn 12 50 = OutcomeGreenRedYellow Draw121523

34. 2pt A ticket is randomly drawn out of a bag and then replaced. The table shows the results after 100 draws. Estimate the probability of drawing a purple ticket. OutcomePurpleOrangeBrown Draw552223

35. 2pt A ticket is randomly drawn out of a bag and then replaced. The table shows the results after 100 draws. The probability of drawing a purple ticket is about 0.55, or 55%. probability  number of purple tickets drawn total number of tickets drawn Estimate the probability of drawing a purple ticket. OutcomePurpleOrangeBrown Draw552223

36. 3pt Three separate boxes each have one blue marble and one green marble. One marble is chosen from each box. What is the probability of choosing a blue marble from each box? Finding the Probability of Independent Events

37. 3pt Three separate boxes each have one blue marble and one green marble. One marble is chosen from each box. What is the probability of choosing a blue marble from each box? The outcome of each choice does not affect the outcome of the other choices, so the choices are independent. P(blue, blue, blue) = In each box, P(blue) =. 1212 1212 · 1212 · 1212 = 1818 = 0.125 Multiply. Finding the Probability of Independent Events

38. 4pt Two boxes each contain 4 marbles: red, blue, green, and black. One marble is chosen from each box. What is the probability of choosing a blue marble from each box? The outcome of each choice does not affect the outcome of the other choices, so the choices are independent.

39. 4pt Two boxes each contain 4 marbles: red, blue, green, and black. One marble is chosen from each box. What is the probability of choosing a blue marble from each box? The outcome of each choice does not affect the outcome of the other choices, so the choices are independent. In each box, P(blue) =. 1414 P(blue, blue) = 1414 · 1414 = 1 16 = 0.0625 Multiply.

40. 5pt 2525 3535 

41. 6 25 2525 3535 

42. 1pt 3434 1616 

43. 1818 3434 1616 

44. 2pt 2525 Write each fraction as a decimal.

45. 2pt 0.4 2525 Write each fraction as a decimal.

46. 3pt Write each fraction as a decimal. 32 125

47. 3pt Write each fraction as a decimal. 32 125 0.256

48. 4pt 1 12 1 6 + ADD.

49. 4pt 1 12 1 6 1 4 +

50. 5pt 1 2 2 36 + ADD.

51. 5pt 1 2 2 36 5 9 + ADD.