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SMJE 2103 Synchronous Generator. Scope of discussion 1)Construction 2)Rotation speed 3)Generated voltage 4)Equivalent circuit 5)Power and Torque 6)Testing.

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Presentation on theme: "SMJE 2103 Synchronous Generator. Scope of discussion 1)Construction 2)Rotation speed 3)Generated voltage 4)Equivalent circuit 5)Power and Torque 6)Testing."— Presentation transcript:

1 SMJE 2103 Synchronous Generator

2 Scope of discussion 1)Construction 2)Rotation speed 3)Generated voltage 4)Equivalent circuit 5)Power and Torque 6)Testing 7)Parallel operation 8)Rating

3 Synchronous Generator -construction-

4 The electrical frequency is synchronized with the mechanical rate of rotation Relationship between magnetic field speed and electrical frequency, Synchronous Generator -speed of rotation-

5 Induced voltage, Synchronous Generator -generated voltage-

6 Example 1 At a location in Europe, it is necessary to supply 300 kW of 60-Hz power. The only power sources available operate at 50 Hz. It is decided to generate the power by means of a motor- generator set consisting of a synchronous motor driving a synchronous generator. How many poles should each of the two machines have in order to convert 50-Hz power to 60-Hz power?

7 Synchronous Generator -equivalent circuit- There are some factors that affected in forming of an equivalent circuit: 1.Armature reaction 2.Self inductance of the armature coil 3.Resistance of the armature coil 4.The effect of salient pole rotor shapes

8 Armature Reaction

9 Synchronous Generator -equivalent circuit-

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11 Full equivalent circuit

12 Example 2 Assume that the field current of the generator in Example 5 is adjusted to achieve rated voltage (2300 V) at full load conditions in each of the questions below. (a) What is the efficiency of the generator at rated load? (b) What is the voltage regulation of the generator if it is loaded to rated kilovoltamperes with 0.8-Pflagging loads? (c) What is the voltage regulation of the generator if it is loaded to rated kilovoltamperes with 0.8-Pfleading loads? (d) What is the voltage regulation of the generator if it is loaded to rated kilovoltamperes with unity-powerfactor loads?

13 Synchronous Generator -power and torque-

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15 - R A assumed to be zero -  Torque angle -Maximum torque due to max power when sin  is 1 Synchronous Generator -power and torque-

16 Basic torque equation: From power expression P out = P conv =  ind  m Synchronous Generator -power and torque-

17 Example 3 Assume that the field current of the generator in Example 5 has been adjusted to a value of 4.5 A. (a) What will the terminal voltage of this generator be if it is connected to a Δ-connected load with an,impedance of 20 ∠ 30° Ω? (b) Sketch the phasor diagram of this generator. (c) What is the efficiency of the generator at these conditions? (d) Now assume that another identical Δ-connected load is to be paralleled with the first one. What happens to the phasor diagram for the generator? (e) What is the new terminal voltage after the load has been added? (f) What must be done to restore the terminal voltage to its original value?

18 Example 4 Assume that the field current of the generator in Example 5 has been adjusted so that it supplies rated voltage when loaded with rated current at unity power factor. (You may ignore the effects of R A when answering these questions.) (a) What is the torque angle δ of the generator when supplying rated current at unity power factor? (b) When this generator is running at full load with unity power factor, how close is it to the static stability limit of the machine?

19 Purpose of test is to determine these parameters: a)Field current and flux relationship b)Synchronous reactance c)Armature resistance Open circuit and short circuit tests should be performed in order to get the purpose. Synchronous Generator -testing-

20 Procedures: 1)Generators is rotated at the rated speed 2)No load is connected at the terminals 3)Field current is increased from 0 to maximum 4)Record values of the terminal voltage and field current value Synchronous Generator -testing (open circuit)-

21 I A = 0, so E A = V , possible to plot E A or V T vs I F graph. It is possible to find internal generated voltage for any given field current The iron saturated, mmf getting slow down due to increasing reluctance of the iron Synchronous Generator -testing (open circuit)-

22 Procedures of short circuit test: 1)Generator is rotated at rated speed 2)Adjust field current to 0 3)Short circuit the terminals 4)Measure armature current or line current as the field current is increased. Synchronous Generator -testing (short circuit)-

23 The net magnetic field is very small, the iron is not saturated, so the relationship is linear Synchronous Generator -testing (short circuit)-

24 From the both tests. E A from OCC while I A from SCC Synchronous Generator -testing (short circuit)-

25 Capability Curve

26 Problem statement; Notice that for some possible current angles the required E A ­ exceeds E ­A,max ­. If the generator were operated at the rated armature current and these power factors, the field winding would burn up. Based upon these limits, there is a need to plot the capability of the synchronous generator. This is so that it can be shown graphically the limits of the generator. A capability diagram is a plot of complex power S=P+jQ. The capability curve can be derived back from the voltage phasor of the synchronous generator.

27 On the voltage axes, the origin of the phasor diagram is at -Vf ­ ­ on the horizontal axis, so the origin on the power diagram is at: The field current is proportional to the machine’s flux, and the flux is proportional to E ­A ­ = Kfw. The length corresponding to E ­A ­ on the power diagram is: The armature current I ­A ­ is proportional to X ­S ­I ­A ­, and the length corresponding to X ­S ­I ­A ­ on the power diagram is 3VfI ­A ­.

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29 Example 5 A 2300-V 1000-kVA 0.8-PF-lagging 60-Hz two-pole Y- connected synchronous generator has a synchronous reactance of 1.1 Ω and an armature resistance of 0.15 Ω. At 60 Hz, its friction and windage losses are 24 kW, and its core losses are 18 kW. The field circuit has a dc voltage of 200 V, and the maximum I F is 10 A. The resistance of the field circuit is adjustable over the range from 20 to 200 Ω. The OCC of this generator is shown in Figure. (a) How much field current is required to make V T equal to 2300 V when the generator is running at no load? (b) What is the internal generated voltage of this machine at rated conditions? (c) How much field current is required to make V T equal to 2300 V when the generator is running at rated conditions? (d) How much power and torque must the generator’s prime mover be capable of supplying? (e) Construct a capability curve for this generator.

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31 Reasons for operating in parallel: a)Handling larger loads. b)Maintenance can be done w/t power disruption. c)Increasing system reliability. d)Increased efficiency. Synchronous Generator -parallel operation-

32 Condition required: 1)RMS line voltage must be equal. 2)Both have same phase sequence. 3)Output phase angles are same. 4)Must have a slightly higher frequency for new generator. It will change slowly. Synchronous Generator -parallel operation-

33 Frequency rating: the frequency at the system. Voltage rating: voltage generated that depend on flux and speed. Apparent power rating: maximum power with maximum armature current. Power factor rating: Synchronous Generator -ratings-

34 Example 6 A 480-V 400-kVA 0.85-PF-lagging 50-Hz four-pole Δ-connected generator is driven by a 500-hp diesel engine and is used as a standby or emergency generator. This machine can also be paralleled with the normal power supply (a very large power system) if desired. (a) What are the conditions required for paralleling the emergency generator with the existing power system? What is the generator’s rate of shaft rotation after paralleling occurs? (b) If the generator is connected to the power system and is initially floating on the line, sketch the resulting magnetic fields and phasor diagram. (c) The governor setting on the diesel is now increased. Show both by means of house diagrams and by means of phasor diagrams what happens to the generator. How much reactive power does the generator supply now? (d) With the diesel generator now supplying real power to the power system, what happens to the generator as its field current is increased and decreased? Show this behavior both with phasor diagrams and with house diagrams.

35 Example 7 A 13.8-kV 10-MVA 0.8-PF-lagging 60-Hz two-pole Y- connected steam-turbine generator has a synchronous reactance of 12 Ω per phase and an armature resistance of 1.5 Ω per phase. This generator is operating in parallel with a large power system (infinite bus). (a) What is the magnitude of E A at rated conditions? (b) What is the torque angle of the generator at rated conditions? (c) If the field current is constant, what is the maximum power possible out of this generator? How much reserve power or torque does this generator have at full load? (d) At the absolute maximum power possible, how much reactive power will this generator be supplying or consuming? Sketch the corresponding phasor diagram. (Assume I F is still unchanged.)


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