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AP Physics ST Electric Potential and Potential Energy Due to a Point Charge, “E from V” www.ccp1.ac.uk.

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Presentation on theme: "AP Physics ST Electric Potential and Potential Energy Due to a Point Charge, “E from V” www.ccp1.ac.uk."— Presentation transcript:

1 AP Physics ST Electric Potential and Potential Energy Due to a Point Charge, “E from V” www.ccp1.ac.uk

2 Electric Potential Due to a Point Charge Recall that every location on an equipotential surface has the same electric potential. – Meaning NO work is needed to move along that specific surface. www.pstcc.edu

3 Electric Potential Due to a Point Charge We’ve defined the electric potential due to a uniform electric field as… But what is creating this field?... (a charge) So now we endeavor to define the electric potential (and thus energy) associated with the charge itself.

4 Electric Potential Due to a Point Charge Consider a point charge with equipotential surfaces identified… – Electric field lines would necessarily be perpendicular to these surfaces at all points. Consider the movement from point A to point B along any path. +q A B rArA rBrB r ds

5 Electric Potential Due to a Point Charge Because you are traveling between two different equipotential surfaces the electric potential changes. To determine what this change depends on focus on a differential element (ds) of the motion along the path between points A and B highlighted in orange. +q A B rArA rBrB r ds

6 Electric Potential Due to a Point Charge Note that theta is the angle between vectors r hat and ds. What then is the electric potential V a distance r from the source charge? ds r dr θ

7 Electric Potential Due to a Point Charge Begin with the general electric potential expression… – Recall the negative sign means that B is at a lower potential than A. Recall from Gauss’s Law:

8 Electric Potential Due to a Point Charge Recall that is a unit vector…magnitude of 1 thus showing direction only. represents the angle between and ds. represents the component of r hat in the direction of ds projection of ds onto r (both vectors)

9 Electric Potential Due to a Point Charge We only care about the change in radial displacement because we already know that movement along the equipotential surface does not require work … meaning no change in energy… meaning no change in electric potential. radial displacement

10 Electric Potential Due to a Point Charge The guts of the integral thus simplifies to … Further simplification…

11 Electric Potential Due to a Point Charge Following integration… – Notice the negative sign cancels out resulting from integration. Potential difference between 2 pts is independent of the path taken! – This is a proof that the electric field is a conservative field!

12 Electric Potential Due to a Point Charge Potential difference depends ONLY on the radial components of A and B. It is quite typical for point A to be located at infinity thus defining the zero level.

13 Electric Potential Due to a Point Charge The Electric Potential due to a Point Charge is therefore… The awesome thing is that electric potential is a scalar quantity! – Speaks only to the magnitude of energy per charge at any location (not direction).

14 Electric Potential Due to a Point Charge Sooooo… if multiple charges exist you can just add ‘em!! (superposition principle)

15 Electric Potential ENERGY Due to a Point Charge Consider the potential energy involved (work) to bring q 2 from infinity to location r 12 through electric potential V 1 To bring q 2 to this location WITHOUT accelerating requires work by an external force. q1q1 q2q2 r 12 from ∞ to this location P V1V1

16 Electric Potential ENERGY Due to a Point Charge The magnitude of work done (thus energy transferred) is equal to the magnitude of charge q 2 moved to the location where the electric potential is V 1 Thus the energy at point r 12 resulting from two point charges is described by….

17 Electric Potential ENERGY Due to a Point Charge If the charges are the same: – +U  external force must do positive work to bring two charges together (without accelerating) If charges are opposite: – -U  external force must do negative work to bring two charges together (without accelerating).

18 Electric Potential ENERGY Due to a Point Charge This is SOOOOO cool… – It says that when brought from infinity THIS is the magnitude of work that was done! – This expression acknowledges the fact that the electric potential varies with distance but depends ONLY on the beginning and ending radial location points. – Further simplified by setting the zero level at infinity.

19 Electric Potential ENERGY Due to a Point Charge Multiple charges present???... Total energy of the system of charges… q1q1 q3q3 q2q2 r 12 r 13 r 23

20 Obtaining E from V To max out the level of awesimity (yes, it is a word and yes this really is that cool!) we can even determine the magnitude of the electric field if we know JUST the potential… … I knooowwww, too cool! Seeeeee… there’s the electric field!

21 Obtaining E from V The crux is too know that V is a scalar quantity and E is a vector quantity so one must note that there is a directional component for the E. To isolate E begin by differentiating both sides…

22 Obtaining E from V Recognize that E has an x-, y- and z-component, thus allow the “ds” to reflect the appropriate direction by changing variables. – Dot-product simplifies because E is specifically along the identified axis

23 Obtaining E from V x-component y-component: z-component:

24 Obtaining E from V “Full circle”… – Recall that the electric potential due to a point charge… – To determine the E… – This should be a familiar result for the electric field of a point charge!

25 Lesson Summary (THINK! What are the BIG, MAIN, GLOBAL lesson ideas?)

26

27 Example #1: 87-1cd, (a,b optional)

28 Example #2: 25-37 Serway 5 th ed Over a certain region of space, the electric potential is V = 5x – 3x 2 y + 2yz 2. a.Find the expressions for the x, y, and z components of the electric field over this region. b.What is the magnitude of the field at the point P, which has coordinates (1,0,-2)m?

29 Example #3 Two point charges, q 1 = +5µC and q 2 = -2µC, are separated by 50 cm. Where along a line through both charges, is V = 0?


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