1. Questions on Practice Assignment? Page 254 21, 23, 33, 41 Page 263, 15 -19, 21 - 27

2. A.y-intercept = 3, axis of symmetry: x = –3, x-coordinate = –3 B.y-intercept = –3, axis of symmetry: x = 3, x-coordinate = 3 C.y-intercept = 3, axis of symmetry: x = 3, x-coordinate = 3 D.y-intercept = –3, axis of symmetry: x = –3, x-coordinate = –3 1. Given the quadratic function f(x) = 3 – 6x + x 2. Find the y- intercept, the equation of the axis of symmetry, and the x-coordinate of the vertex. A.–5 B.–1 C.5 D.none 2. Given the function f(x) = x 2 + 4x – 1. What is the maximum or minimum value? A.D = {all real numbers}; R = {f(x) | f(x) ≥ –5} B.D = {all real numbers}; R = {f(x) | f(x) ≤ –5} C.D = {x ≥ –5}; R = {all real numbers} D.D = {x ≤ –5}; R = {all real numbers} 3. Given f(x) = x 2 + 4x – 1. What are the domain and range? A.4, –4 B.3, –2 C.2, 0 D.2, –2 4. Find the solution to y = x 2 – 4

3. A.y-intercept = 3, axis of symmetry: x = –3, x-coordinate = –3 B.y-intercept = –3, axis of symmetry: x = 3, x-coordinate = 3 C.y-intercept = 3, axis of symmetry: x = 3, x-coordinate = 3 D.y-intercept = –3, axis of symmetry: x = –3, x-coordinate = –3 1. Given the quadratic function f(x) = 3 – 6x + x 2. Find the y- intercept, the equation of the axis of symmetry, and the x-coordinate of the vertex. A.–5 B.–1 C.5 D.none 2. Given the function f(x) = x 2 + 4x – 1. What is the maximum or minimum value? A.D = {all real numbers}; R = {f(x) | f(x) ≥ –5} B.D = {all real numbers}; R = {f(x) | f(x) ≤ –5} C.D = {x ≥ –5}; R = {all real numbers} D.D = {x ≤ –5}; R = {all real numbers} 3. Given f(x) = x 2 + 4x – 1. What are the domain and range? A.4, –4 B.3, –2 C.2, 0 D.2, –2 4. Find the solution to y = x 2 – 4

4. Factor GCF and by Grouping Factor 9y 3 – 6y 2 + 3y. 9y 3 – 6y 2 + 3y =3y(3y 2 ) – 3y(2y) + 3y(1)Factor the GCF. =3y(3y 2 – 2y + 1) Distributive Property Answer: 3y(3y 2 – 2y + 1)

5. Factor GCF and by Grouping Factor 8a 2 + 10ab 2 + 4ab + 5b 3. 8a 2 + 10ab 2 + 4ab + 5b 3 =(8a 2 + 4ab) + (10ab 2 + 5b 3 )Group terms with common factors. =4a(2a + b) + 5b 2 (2a + b)Factor the GCF from each group. =(4a + 5b 2 )(2a + b)Distributive Property Answer: (4a + 5b 2 )(2a + b)

6. A.6b(6b 2 + 3b + 3) B.4b(6b 2 – 4b + 4) C.6b(4b 2 – 3b + 3) D.12b(2b 2 – b + 1) A. Factor 24b 3 – 18b 2 + 18b.

7. A.(3p – 4r)(2p – r 2 ) B.(4p + 3r)(2p – r 2 ) C.(4p + 3r)(2p + 3r 2 ) D.(3p + 4r)(2p – r 2 ) B. Factor 6p 2 – 3pr 2 + 8pr – 4r 3.

8. Factoring Binomials Difference of Squares a 2 – b 2 = (a + b)(a – b) a = the square root of a 2, b = the square root of b 2 Once you find a and b, just put it into the format these will both be perfect squares!!! EX: 5mp 2 – 45m x 2 – 25 9x 8 – 16x 4 16x 2 + 81 3y 2 – 48 5m 4 - 5

9. Factoring ax 2 +bx + c x 2 + 7x + 10 Don’t forget to check your solution! (x + )(x + ) Factors of AC Sum of Factors 1, 10 11 2, 5 7 Use factors of AC that when added together equal B (x + 2 )(x + 5 ) Check your answers by using Foil F O I L (x + 2)(x + 5) = x 2 + 5x + 2x + 10 = x 2 + 7x + 10 

10. y = x 2 + 7x + 10 x = -2, and x = -5 x + 2 = 0 x + 5 = 0 y = (x + 2 )(x + 5 ) Zero Product Property

11. Factoring ax 2 -bx - c x 2 - x - 2 Don’t forget to check your solution! (x + )(x - ) Factors of AC Difference of Factors 1, 2 1 Use factors of AC that when subtract together equal B (x + 1 )(x - 2 ) Check your answers by using Foil F O I L (x + 1)(x - 2) = x 2 - 2x -+1x -2 = x 2 -x -2 

12. y = x 2 - x - 2 y = x 2 - x – 2 x = -1, and x = +2 x + 1 = 0 x - 2 = 0 y = (x + 1 )(x - 2 ) Zero Product Property

13. Factoring ax 2 -bx - c x 2 - 36 Don’t forget to check your solution! (x + )(x - ) Factors of AC Difference of Factors 6, 6 0 Use factors of AC that when subtract together equal B (x + 6 )(x - 6 ) Check your answers by using Foil F O I L (x + 1)(x - 2) = x 2 - 6x +6x -36 = x 2 - 36  AC = 360

14. A.(x + 3)(x + 5) B.(x – 4)(x + 2) C.(x + 7)(x + 8) D.(x – 3)(x – 5) A. Factor x 2 – 8x + 15.

17. A.(3s + 1)(s – 4) B.(s + 1)(3s – 4) C.(3s + 4)(s – 1) D.(s – 1)(3s + 4) B. Factor 3s 2 – 11s – 4.

18. A.7 feet B.11 feet C.14 feet D.25 feet TENNIS During a match, Andre hit a lob right off the court with the ball traveling in the shape of a parabola whose vertex was the height of the shot. The height of the shot is given by h = 49 – x 2, where x is the horizontal distance from the center of the shot. Both h and x are measured in feet. How far was the lob hit?

19. Practice Assignment Page 272 - 7, 11, 13, 21, 25, 27, 39, 41, 53 Additional practice 5, 9, 15, 23, 29