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Acid-Base Equilibria and Solubility Equilibria Chapter 16.

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Presentation on theme: "Acid-Base Equilibria and Solubility Equilibria Chapter 16."— Presentation transcript:

1 Acid-Base Equilibria and Solubility Equilibria Chapter 16

2 Objectives Define key terms and concepts Explain how a buffer works and how to prepare a buffer system for a specific pH. Calculate the pH of a buffer solution. Calculate the equivalence point for acid-base titrations. Calculate the solubility product for a compound. Calculate concentration and solubility using the common ion and complex ion effects. Develop and utilize a flow chart for use in qualitative analysis.

3 Conjugate Acids and Bases

4 Buffers Buffer solutions resist changes in pH when small amounts of acids or bases are added Buffers are made of a weak acid or base and it’s salt (acid-base conjugate pair) Buffering Capacity

5 Buffers

6 Instructions for making up a buffer say to mix 60mL of 0.1M NH 3 with 40mL of 0.1M NH 4 Cl. What is the pH of the buffer?

7 Calculate the pH of a buffer solution using ammonia and ammonium to which 3mL of 0.10M HNO 3 is added.

8 Instructions for making up a buffer say to mix 100mL of 0.25M HC 2 H 3 O 2 with 75mL of 0.3M NaC 2 H 3 O 2. What is the pH of the buffer?

9 Calculate the pH of a buffer solution using acetic acid/sodium acetate to which 9.5mL of 0.10M HCl is added.

10 Buffers Henderson-Hasselbalch Equation Relates pH of a buffer for different concentrations of the conjugate acid-base If the molar concentration of the acid ≈ base, then the pH ≈ pK a pH = pK a + log [base] [acid] pK a = -log K a

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12 What must the ratio of the concentration of the HCO 3 - and H 2 CO 3 buffer system found in blood be for the pH to be 7.4?

13 What acid-base conjugate pair could be used to make a buffer with a pH of 3.7? How would you prepare the buffer solution? H 3 PO 4 ↔ H 2 PO 4 - + H 3 O + K a = 7.5x10 -3 H 2 S ↔ HS - + H 3 O + K a = 1x10 -7 HCO 2 H ↔ HCO 2 - + H 3 O + K a = 1.8x10 -4

14 Acid-Base Titrations Titration Addition of a solution of a known concentration (standard solution) to a solution of unknown concentration until the reaction is complete (reaches its equivalence point)

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16 Acid-Base Titrations Strong Acid-Base Titrations Weak Acid-Base Titrations Strong Acid-Weak Base Titration Weak Acid-Strong Base

17 Calculate the pH of a solution in which 10mL of 0.1M NaOH is added to 25.0mL of 0.1M HCl.

18 Calculate the pH of a solution when 25mL of 0.1M nicotinic acid (HC 5 H 4 NO 2 ) is titrated by 20mL of 0.1M NaOH. The K a for nicotinic acid is 1.4x10 -5.

19 What is the pH of a solution when 35mL of 0.2M ammonia is titrated by28mL 0.12M HCl. The K b for ammonia is 1.8x10 -5.

20 What is the pH at the equivalence point when 25mL of 0.1M HF is titrated by 0.15M NaOH?

21 What are your questions?

22 Solubility Equilibria Solubility Product (K sp ) The product of the molar concentrations of the ions that make-up a compound, each raised to the power of it’s stoichiometric coefficient. The smaller the K sp value, the less soluble the compound is in water. BaCO 3 ↔ Ba 2+ + CO 3 2- K sp = [Ba 2+ ] [CO 3 2- ] BaF 2 ↔ Ba 2+ + 2F - K sp = [Ba 2+ ] [F - ] 2

23 Solubility Equilibria The saturation level of a solution can be determined using K sp and Q. If Q < K sp, the solution is unsaturated If Q > K sp, the solution is supersaturated If Q = K sp, the solution is saturated

24 Write the solubility product expression for the following salts: AgCl Hg 2 Cl 2 Pb 3 (AsO 4 ) 2

25 A liter of a solution saturated at 25°C with calcium oxalate, CaC 2 O 4, is evaporated to dryness, giving a 0.0061g residue of CaC 2 O 4. Calculate the solubility product constant for the salt at 25°C.

26 By experiment, it is found that 1.2x10 -3 mole of lead (II) iodide dissolves in 1L of aqueous solution at 25°C. What is the solubility product constant at this temperature?

27 Solubility Equilibria Molar Solubility The number of moles of solute in 1 liter of saturated solution Moles per liter Solubility The number of grams of solute in 1 liter of saturates solution Grams per liter These both refer to solutions at a specific temperature

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29 Solubility Product and Molar Solubility

30 Calculate the solubility in g/L of lead (II) chromate in water. The K sp for PbCrO 4 is 1.8x10 -14.

31 Calculate the solubility in g/L for lead (II) arsenate when dissolved in water. The K sp for Pb 3 AsO 4 ) 2 is 4.0x10 -36.

32 Calculate the solubility product for potassium nitrate if the solubility of the compound in water is 133g/L at 0°C.

33 If 0.17g of calcium fluoride is soluble in 1L of solvent, what is the solubility product of calcium fluoride?

34 Precipitation Reactions If the ion product exceeds the K sp, a precipitate will form. Soluble Compounds Almost all salts of Na +, K +, and NH 4 + Salts of NO 3 -, ClO 3 -, ClO 4 -, C 2 H 3 O 2 - Exceptions Almost all salts of Cl -, Br -, I - Halides of Ag +, Hg 2+, Pb 2+ Compounds containing F - Fluorides of Mg 2+, Ca 2+, Sr 2+, Ba 2+, and Pb 2+ Salts of SO 4 2- Sulfates of Ca 2+, Sr 2+, Ba 2+, Pb 2+ Insoluble CompoundsExceptions Most salts of CO 3 2-, PO 4 3-, C 2 O 4 2-, CrO 4 2- Salts of NH 4 + and alkali metal cations Most metal sulfides, S 2- Most metal hydroxides and oxides

35 Common Ion Effect and Solubility A compound can be precipitated out of solution if another compound containing a common ion is added to the solution. The saturation level of a solution can be determined using K sp and Q (ion product). If Q < K sp, the solution is unsaturated If Q > K sp, the solution is supersaturated If Q = K sp, the solution is saturated

36 Common Ion Effect and Solubility

37 o Which of the following compounds should most affect the solubility of lead (II) sulfate in water to which it has been added? a) NaCl b) Na 2 SO 4 c) PbS o Which of the following compounds should most affect the solubility of silver chloride in water to which it has been added? a) NaCl b) Na 2 SO 4 c) PbS

38 The concentration of calcium ion in blood plasma is 0.0025M. If the concentration of oxalate ion is 1.0x10 -7 M, do you expect calcium oxalate to precipitate? K sp for calcium oxalate is 2.3x10 -9.

39 AgCl will be dissolved into a solution with is ALREADY 0.0100 M in chloride ion. What is the solubility of AgCl? The K sp =1.77 x 10¯ 10

40 What is the solubility of Ca(OH) 2 in 0.0860 M Ba(OH) 2 ? The K sp for Ca(OH) 2 is known to be 4.68 x 10¯ 6.

41 A.If 1.1 x 10 -4 g of Cr(OH) 3 is added to 120 L of water at 25 °C, will all of the solute dissolve? The of chromium (III) hydroxide is K sp = 6.7 x 10 -31. B.If 4.0 x 10 -4 g of NaOH is added to the solution described above, will a precipitate form? C.Calculate the molar solubility of Cr(OH) 3 in a solution buffered at pH = 11.00.

42 Complex Ion Equilibria and Solubility Complex Ion An ion containing a central metal cation bonded to one or more molecules or ion. Commonly formed by transition metals Formation Constant (K f ) The equilibrium constant for complex ion formation The larger the K f, the more stable the complex

43 Complex Ions

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46 Cu 2+ + 4NH 3 2+  Cu(NH 3 ) 4 2+ (solutions turns a deep blue) Ni 2+ + 6NH 3  Ni(NH 3 ) 6 2+ (Solutions is blue)

47 Will silver chloride precipitate from a solution that is 0.01M AgNO 3 and 0.01M NaCl? The K sp for silver chloride is 8.3x10 -17

48 Will silver iodide precipitate from a solution that is 0.0045M AgNO 3 and 0.15M NaI? The K sp for silver iodide is 1.8x10 -10.

49 Sulfate ion in solution is often determined quantitatively by precipitating it as barium sulfate. The sulfite ion may have been formed from a sulfur compound. Analysis for the amount of sulfate ion then indicates the percentage of sulfur in the compound. Is a precipitate expected to form at equilibrium when 50mL of 0.0010M barium chloride is added to 50mL of 0.00010M sodium sulfate? The solubility product constant for barium sulfate is 1.1x10 -10.

50 What are your questions?


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