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Asymmetry of M + (H 2 O)RG Complexes, (M=V, Nb) Revealed with Infrared Spectroscopy Timothy B Ward, Evangelos Miliordos, Sotiris Xantheas, Michael A Duncan.

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Presentation on theme: "Asymmetry of M + (H 2 O)RG Complexes, (M=V, Nb) Revealed with Infrared Spectroscopy Timothy B Ward, Evangelos Miliordos, Sotiris Xantheas, Michael A Duncan."— Presentation transcript:

1 Asymmetry of M + (H 2 O)RG Complexes, (M=V, Nb) Revealed with Infrared Spectroscopy Timothy B Ward, Evangelos Miliordos, Sotiris Xantheas, Michael A Duncan + Na +

2 Selectivity Sensitivity Metal-cation water complexes

3 + h (IR)  Mass gate on V + (H 2 O)Ar 2 -Ar Fragmentation at 3683 cm -1 Mass-Selected Ion Photodissociation Spectroscopy

4 JPCA 113, 4849 (2009) Cation-water interactions Cu + (H 2 O)Ar 2 asymmetric stretch, perpendicular type band symmetric stretch, parallel type band asymmetric stretch-bend combination Red shift in the OH stretches Changes due to polarization removes density along O-H bonds Free water has ratio of I sym /I asym 1:18 Symmetric stretch gains intensity from charge oscillation along symmetry axis

5 V + (H 2 O)Ar 2 Co + (H 2 O)Ar 3 Cu + (H 2 O)Ar 2 Many metal ion water complexes have been studied In most case Ar-M binding energy strong, requiring tagging with multiple Ar atoms

6 A special situation happen if: Tagging with one Ar Ar is on C 2 axis with metal-water Treat as prolate symmetric trop Sym Asym JCP 134, 014302 (2011)

7 Using A” we can calculate the HOH bond angle, if we assume that the OH bond length is constant This has been done for several cation-water complexes Cation Binding Increase H-O-H Angle JPCA 112, 6237 (2008) PCCP 8, 3078 (2006) JPCA 109, 7057 (2005) JCP 104, 4591 (1996)

8 Still seem to have two OH stretch bands, that are red shifted Asymmetric stretch still looks to have rotational structure, but different pattern Nb + (H 2 O)Ar Duncan and co-workers, J. Chem. Phys., 2011, 134, Nb + (H 2 O)Ar is different!

9 Ne tagging shows that we only have two OH stretches Same rotational intensity issue arises in V + (H 2 O)Ar Nb + (H 2 O)Ar Nb + (H 2 O)Ne V + (H 2 O)Ar Vanadium-water also has unusual pattern

10 Theory by E. Miliordos and S.S. Xantheas at Pacific Northwest National Lab icMRCI and CCSD(T) methods aug-cc-pVQZ for H, O, and Ar cc-pVQZ for V cc-pVQZ-PP for Nb Calculations show C 2v for the metal-water Argon however is off axis v = 0 v = 1 v = 2 Nb + (H 2 O)

11 V also has out of plane Ar This explains smaller spacing but not intensities v = 0 v = 1 v = 2 PGOPHER Simulation V + (H 2 O)

12 Need an effect to change line intensities

13 ConstantM = Sc ( 3 Α 1 ) (MHz) M = V ( 5 B 1 ) (MHz) M = Nb ( 5 B 1 ) (MHz) AKAK 0.422.173.46 akak -4.28-13.01-11.76 bkbk -3.88-12.98-10.12 ckck 8.1625.9921.87 How to probe ortho-para mixing? Isotropic Fermi Contact from Xantheas and Miliordos Normal 3:1 ortho-para ratio

14 Nb + (H 2 O)Ar A” = 11.5 cm -1 B”/C”= 0.0476 cm -1 A’ = 10.5 cm -1 B’/C’= 0.0476 cm -1 T = 40 K B.O. sym = 3589 cm -1 B.O. asym = 3662 cm -1 Ortho-Para mixed Ortho-Para 3:1

15 V + (H 2 O)Ar A” = 5.5 cm -1 B”/C”= 0.0542 cm -1 A’ = 10.5 cm -1 B’/C’= 0.0542cm -1 T = 40 K B.O. sym = 3604 cm -1 B.O. asym = 3690 cm -1 Ortho-Para mixed Ortho-Para 3:1

16 Conclusions Ar seems to be out of C 2v plane, lowering the value of A” and A’ for both Nb and V Nb and V are examples where nuclear spin is catalyzing ortho-para interconversion Rate is approximately 10 6 s -1 This compares well reasonably with Tanaka and co-workers 1.2*10 5 s -1 torr -1 for open-shelled vinyl radical

17 Acknowledgements Michael Duncan The Duncan lab Sotiris Xantheas Evangelos Miliordos Gary Douberly Department of Energy University of Georgia


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