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Chapter 9 - Stoichiometry

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1 Chapter 9 - Stoichiometry
9.1 The Arithmetic of Equations 9.2 Chemical Calculations 9.3 Limiting Reagent and Percent Yield

2 9.1 The Arithmetic of Equations
Using Everyday Equations Building a bicycle (Figure 9.2) Baking brownies! Interpreting Chemical Equations

3 9.2 Chemical Calculations
Mole-Mole Calculations The Mole Ratio: N2 (g) + 3H2 (g) = 2NH3 (g) is the formation of ammonia. Using the coefficients as mole amounts we can set up “ratios” of equivalent substances (conservation of mass) – the mole ratio. 1 mol N2 / 3 mol H2 3 mol H2 / 2 mol NH3 2 mol NH3 / 1 mol N2 These are used to solve problems involving substance amounts and balanced chemical equations.

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6 Chapter 9 Assignments CPQ # 1 pp.262–63 # 33,34,36,37,38,39,41

7 9.3 Limiting Reagent and Percent Yield
What is a Limiting Reagent? Back to some Limiting versus excess “common” examples… Problems…

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9 9.3 Limiting Reagent and Percent Yield (cont.)
100%! Batting averages, grades, etc. % yield = actual yield / theoretical yield x 100 Ex: 50 g NaCl / 75 g NaCl x 100 = 66.6% Need to know the actual and theoretical yields!

10 Chapter 9 Assignments CPQ # 1 pp.262–63 # 33,34,36,37,38,39,41
# 42-47,49


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