14.1 Matrix Addition and Scalar Multiplication OBJ: To find the sum, difference, or scalar multiples of matrices
EX: An automobile dealer sells four different models whose fuel economy is shown in the table below: This information can be displayed as a rectangular array of numbers enclosed by brackets, called a matrix (plural, matrices), usually labeled with a capital letter. Spts Car Se- dan Sta- tion Wag Van City Mpg High- way Mpg
sp se sw v M = c h Each number is an element (or entry) of the matrix. The dimensions are the number of rows and columns. Since M has two rows and four columns, M is a 2 x 4 matrix, denoted by M 2x4. It is a “driving-condition by model” matrix.
If the rows and columns are interchanged, you get the transpose of M, denoted by M t c h M t = sp l l se l l sw v M t 4x2 is a “model by driving-condition” matrix, with 4 rows and 2 columns.
If the rows and columns are interchanged, you get the transpose of M, denoted by M t c h M t = sp l l se l l sw v M t 4x2 is a “model by driving-condition” matrix, with 4 rows and 2 columns.
The Environmental Protection Agency mandated in 5 years the fuel performance figures must increase 10%. This means every element in matrix M must be multiplied by 1.10, resulting in the matrix sp se sw v 1.1M = c h This is called scalar multiplication, with 1.1 being called a scalar.
EX: If A = , find At, 2A, and -3A At=At= 3 4 | 1 0 5 -2 2A = -3A =
Two matrices with the same dimensions can be added or subtracted, by finding the sums or differences of the corresponding elements. EX: A = 381 -215 B = 209 0 72 Find A + B and A – B. A + B = A – B =
EX: A = 2 -1 4 0 0 -8 B = Find A t + B and A + B t. A t = B t = -6 0 3 7 5 -4 A t + B = A + B t = 7 7
Two matrices are equal if and only if they have the same dimensions and all corresponding elements (same row, same column) are equal. EX: Find the values of the variables for which the given statement is true. a b – 2 -3 = c d 5 -1 -1 0 a b = + 2 -3 c d -1 0 5 -1 a b = c d 4 -1
Solve the matrix equation for X 2 5 1 + 3X = 1 -4 3 4 3 -7 10 2 + 3X = 1 -4 6 8 3 -7 3X= 1 -4 – 10 2 = 3 -7 6 8 _1_ 3 X =