ME 440 Intermediate Vibrations Th, April 2, 2009 Chapter 5: Vibration of 2DOF Systems © Dan Negrut, 2009 ME440, UW-Madison Quote of the Day: It is a miracle.

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ME 440 Intermediate Vibrations Th, April 2, 2009 Chapter 5: Vibration of 2DOF Systems © Dan Negrut, 2009 ME440, UW-Madison Quote of the Day: It is a miracle that imagination survives formal education. - Albert Einstein

Before we get started… Last Time: Examples Using the Initial Conditions (ICs) to compute solution parameters Today: HW Assigned (due April 9): For this problem do the following A) Derive the equations of motion B) Indicate the assumptions you have to make to render this equations linear C) After doing B) above, indicate the type of coupling between the equations (dynamics and/or static) Hint: write EOM in the horizontal dir for M, and in the horizontal/vertical/rotational components for the pendulum (you’ll have to consider the reaction forces (one horizontal and one vertical) in the pin joint connecting M and m). Also, point O is the CM of the body of mass M. Material Covered: Coordinate Coupling in the equations of motion Modal analysis Next time: April 7 - Exam 2 Covers chapters 3 and 4 Review session on Monday, April 6 at 7:15 PM. Review session will have same format like last time You can bring one sheet of paper with equations (use both sides) 2

[Last Time] Free Response of 2DOF Systems ~ Summary Slide ~ Steps for finding the solution 1. Compute the two natural frequencies of the system 2. Compute the mode ratios 3. Use ICs to compute the A’s and  ’s : 3

[AO] Example: Two Masses on Weightless String The system in the figure consists of two point masses carried by a weightless string subjected to the constant tension T. Assume small transverse displacements y 1 (t) and y 2 (t) and derive the differential equations of motion. The natural frequencies of the system The modal vectors 4

[AO] Example: Two Masses on Weightless String Assume L 1 =L 2 =L 3 = L and m 1 =m 2 =m and derive The natural frequencies of the system The modal vectors. Plot the modal vectors 5

[AO] Example: Two Masses on Weightless String Assume the following ICs: 6 Obtain the response of the system Explain your results

[New Topic] Generalized Coordinate Coupling (is of two types: Dynamic and Static) Determine the EOM for system below (Rigid Shaft on Bearings) 7 It boils down to this: Nondiagonal mass matrix in the matrix-vector form of the EOM indicates dynamic coupling of the generalized coordinates Nondiagonal stiffness matrix in the matrix-vector form of the EOM indicates static coupling Sometimes you can have both types of coupling together Often times, the choice of generalized coordinates used to capture the dynamics of the system will determine the nature of coupling in your problem See example at right

[AO] Example, Part 1 Choice of generalized coordinates as indicated in the figure 8

9 [AO] Example, Part 2 Choice of generalized coordinates as indicated in the figure

[Second Installment] Review of Matrix Algebra Focus on the eigenvalue problem Vibration without eigenvalue analysis is like nachos without chips We have to deal with it In the end, you’ll like it (who doesn’t like good nachos?) The eigenvalue problem: Someone gives you a matrix [A] You need to find a vector {u} which has this nice property that multiplying it by [A] (like in [A]{u}) gets you a multiple of the original vector {u}: 10 If you find such an {u}, you just identified an eigenvector of matrix A Incidentally, is called the eigenvalue associated with the eigenvector {u} that you just found

[Cntd] Review of Matrix Algebra Find the eigenvectors and associated eigenvalues of matrix [A] below. 11

[Cntd] Review of Matrix Algebra How do you solve an eigenvector problem? Solve first for eigenvalues, then solve for eigenvectors This starts to sound familiar with the vibration problem: we first solve for the natural frequencies (the eigenvalues) and then found the modal vectors (the eigenvectors) Keep in mind this parallel 12 Going back to the original question, if you want to find nontrivial {x}, it better be that the following determinant is zero (see two lectures ago to understand why):