Have Notes and HW out on your desk. Work on p. 503 #1 – 4 (Remember yesterday. If you waste my time at the beginning, I will hold on to you and waste your time at the end) Bellringer

SPI Determine and use the appropriate trigonometric ratio for a right triangle to solve a contextual problem.

Why would we need more than our two special right triangles?? Because there are many right triangles besides just a or ! We need a way to find side lengths in ALL right triangles Special Right Triangles

S O H C A H T O A SOHCAHTOA

SINE OPPOSITE HYPOTENUSE COSINE ADJACENT HYPOTENUSE TANGENT OPPOSITE ADJACENT SOHCAHTOA

“Opposite” means the *SIDE* that is furthest away from the given *ANGLE* “Adjacent” means the *SIDE* that is attached to the given *ANGLE* Opposite/Adjacent

These are RATIOS!! So can be written in several ways: First, if given the diagram, your answer should be as a fraction or decimal (depending on the question) Second, if given of a degree, your answer will definitely be a decimal using your calculator Trigonometric Ratios

1.Figure out what pieces you have. Use that to decide which ratio are we going to use. 2.Set up that ratio with the angle on one side 3.Set up the ratio using SOHCAHTOA of lengths on the other side If x is on top, multiply If x is on the bottom, divide To Find a Side Length

Work on p. 510 #1 – 7 which will be turned in today!! When you turn this in, you will receive a worksheet which will be due tomorrow For +5 points on the HW assignment, write/draw your own story and solve it. Classwork/Homework