1 Functions CS 202 Epp section ??? Aaron Bloomfield.

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Presentation transcript:

1 Functions CS 202 Epp section ??? Aaron Bloomfield

2 Definition of a function A function takes an element from a set and maps it to a UNIQUE element in another set

3 Function terminology RZ f Domain Co-domain Pre-image of 4 Image of 4.3 f maps R to Z f(4.3)

4 More functions “a” “bb“ “cccc” “dd” “e” A string length function ABCDFABCDF Alice Bob Chris Dave Emma A class grade function DomainCo-domain A pre-image of 1 The image of A

5 Even more functions “a” “bb“ “cccc” “dd” “e” Not a valid function! Also not a valid function! aeiouaeiou Some function… Range

6 Function arithmetic Let f 1 (x) = 2x Let f 2 (x) = x 2 f 1 +f 2 = (f 1 +f 2 )(x) = f 1 (x)+f 2 (x) = 2x+x 2 f 1 *f 2 = (f 1 *f 2 )(x) = f 1 (x)*f 2 (x) = 2x*x 2 = 2x 3

7 One-to-one functions aeioaeio A one-to-one function aeioaeio A function that is not one-to-one A function is one-to-one if each element in the co-domain has a unique pre-image –Meaning no 2 values map to the same result

8 More on one-to-one Injective is synonymous with one-to-one –“A function is injective” A function is an injection if it is one-to-one Note that there can be un-used elements in the co-domain aeioaeio A one-to-one function

9 Onto functions aeioaeio A function that is not onto A function is onto if each element in the co- domain is an image of some pre-image –Meaning all elements in the right are mapped to aeiouaeiou An onto function

aeiouaeiou An onto function More on onto Surjective is synonymous with onto –“A function is surjective” A function is an surjection if it is onto Note that there can be multiply used elements in the co-domain

11 Onto vs. one-to-one Are the following functions onto, one-to-one, both, or neither? abcabc abcdabcd abcdabcd abcdabcd abcabc 1-to-1, not onto Onto, not 1-to-1 Both 1-to-1 and ontoNot a valid function Neither 1-to-1 nor onto

12 Bijections Consider a function that is both one-to-one and onto: Such a function is a one-to-one correspondence, or a bijection abcdabcd

13 Identity functions A function such that the image and the pre- image are ALWAYS equal f(x) = 1*x f(x) = x + 0 The domain and the co-domain must be the same set

14 Inverse functions RR f Let f(x) = 2*x f -1 f(4.3) f -1 (8.6) Then f -1 (x) = x/2

15 More on inverse functions Can we define the inverse of the following functions? An inverse function can ONLY be done defined on a bijection abcabc abcdabcd What is f -1 (2)? Not onto! What is f -1 (2)? Not 1-to-1!

16 Compositions of functions Let (f ○ g)(x) = f(g(x)) Let f(x) = 2x+3Let g(x) = 3x+2 g(1) = 5, f(5) = 13 Thus, (f ○ g)(1) = f(g(1)) = 13

17 Compositions of functions gf f ○ g g(a) f(a) (f ○ g)(a) g(a) f(g(a)) a A BC

18 Compositions of functions gf f ○ g g(1) f(5) (f ○ g)(1) g(1)=5 f(g(1))=13 1 R RR Let f(x) = 2x+3Let g(x) = 3x+2 f(g(x)) = 2(3x+2)+3 = 6x+7

19 Compositions of functions Does f(g(x)) = g(f(x))? Let f(x) = 2x+3Let g(x) = 3x+2 f(g(x)) = 2(3x+2)+3 = 6x+7 g(f(x)) = 3(2x+3)+2 = 6x+11 Function composition is not commutative! Not equal!

20 Graphs of functions Let f(x)=2x+1 Plot (x, f(x)) This is a plot of f(x) x=1 f(x)=3 x=2 f(x)=5

21 Useful functions Floor:  x  means take the greatest integer less than or equal to the number Ceiling:  x  means take the lowest integer greater than or equal to the number round(x) = floor(x+0.5)

22 Sample floor/ceiling questions Find these values  1.1   1.1   -0.1   -0.1   2.99     ½+  ½   ½  +  ½  + ½   ½+1  =  3/2  = 1  ½  =  3/2  = 2

23 Ceiling and floor properties Let n be an integer (1a)  x  = n if and only if n ≤ x < n+1 (1b)  x  = n if and only if n-1 < x ≤ n (1c)  x  = n if and only if x-1 < n ≤ x (1d)  x  = n if and only if x ≤ n < x+1 (2)x-1 <  x  ≤ x ≤ =  x  < x+1 (3a)  -x  = -  x  (3b)  -x  = -  x  (4a)  x+n  =  x  +n (4b)  x+n  =  x  +n

24 Ceiling property proof Prove rule 4a:  x+n  =  x  +n –Where n is an integer –Will use rule 1a:  x  = n if and only if n ≤ x < n+1 Direct proof! –Let m =  x  –Thus, m ≤ x < m+1 (by rule 1a) –Add n to both sides: m+n ≤ x+n < m+n+1 –By rule 4a, m+n =  x+n  –Since m =  x , m+n also equals  x  +n –Thus,  x  +n = m+n =  x+n 

25 Factorial Factorial is denoted by n! n! = n * (n-1) * (n-2) * … * 2 * 1 Thus, 6! = 6 * 5 * 4 * 3 * 2 * 1 = 720 Note that 0! is defined to equal 1

26 Proving function problems Let f be a function from A to B, and let S and T be subsets of A. Show that

27 Proving function problems f(SUT) = f(S) U f(T) Will show that each side is a subset of the other Two cases! Show that f(SUT)  f(S) U f(T) –Let b  f(SUT). Thus, b=f(a) for some a  S U T –Either a  S, in which case b  f(S) –Or a  T, in which case b  f(T) –Thus, b  f(S) U f(T) Show that f(S) U f(T)  f(S U T) –Let b  f(S) U f(T) –Either b  f(S) or b  f(T) (or both!) –Thus, b = f(a) for some a  S or some a  T –In either case, b = f(a) for some a  S U T

28 Proving function problems f(S∩T)  f(S) ∩ f(T) Let b  f(S∩T). Then b = f(a) for some a  S∩T This implies that a  S and a  T Thus, b  f(S) and b  f(T) Therefore, b  f(S) ∩ f(T)

29 Proving function problems Let f be an invertible function from Y to Z Let g be an invertible function from X to Y Show that the inverse of f○g is: –(f○g) -1 = g -1 ○ f -1

30 Proving function problems Thus, we want to show, for all z  Z and x  X The second equality is similar

31 End of lecture on 30 March 2007