3 2 5 19 5 5 3 7 11 2 570 75154 15 70 165 38 21 110 50 57 ~ ~ ~ ~ CLUES ~ ~ ~ ~ Left\: 15= x 70= x x 165= x x 38= x Down:

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Presentation transcript:

~ ~ ~ ~ CLUES ~ ~ ~ ~ Left\: 15= __ x __ 70= __ x __ x __ 165= __ x __ x __ 38= __ x __ Down: 570= __ x __ x __ x __ 154= __ x __ x __ 75= __ x __ x __ Right/: 21= __ x __ 110= __ x __ x __ 50= __ x __ x __ 57= __ x __ MrV’s HexFactor #1 1.Factor each clue completely. Ex: 15 = 3 x 5, etc. 2.Find an intersection of 3 clues, and see if there is only one common factor. The top cell’s clues are 15, 570, is common: Fill it in and cross it off in each of the clues. 4.Fill in any others: 15’s missing factor is 5. 21’s is 7. 5.Repeat steps 2, 3 & 4 for each remaining cell. 15 / \ / \ 3 7 ? / \ / \ 2 95 / \ 5 19 Now go ahead and figure out the rest of the puzzle! ~ ~ ~ ~ CLUES ~ ~ ~ ~ Left\: 15= 3 x 5 70= 2 x 5 x 7 165= 3 x 5 x 11 38= 2 x 19 Down: 570= 2 x 3 x 5 x = 2 x 7 x 11 75= 3 x 5 x 5 /Right: 21= 3 x 7 110= 2 x 5 x 11 50= 2 x 5 x 5 57= 3 x 19    3

MrV’s HexFactor #1 Solution #1 1.Factor each clue completely. Ex: 15 = 3 x 5, etc. 2.Find an intersection where only one factor will fit: 15 = 3 x 5 and 21 = ? And 570 = ? 3.Fill in the factor and cross it off in the clues. 4.Then fill in any others that must fit. 5.Repeat steps 2, 3 & 4 for the remaining cells. ~ ~ ~ ~ CLUES ~ ~ ~ ~ Down: 570= 2 x 3 x 5 x = 2 x 7 x 11 75= 3 x 5 x 5 Left: 15= 3 x 5 70= 2 x 5 x 7 165= 3 x 5 x 11 38= 2 x 19 Right: 21= 3 x 7 110= 2 x 5 x 11 50= 2 x 5 x 5 57= 3 x 19 ~ ~ ~ ~ CLUES ~ ~ ~ ~ Down: 570= __ x __ x __ x __ 154= __ x __ x __ 75= __ x __ x __ Left: 15= __ x __ 70= __ x __ x __ 165= __ x __ x __ 38= __ x __ Right: 21= __ x __ 110= __ x __ x __ 50= __ x __ x __ 57= __ x __

~ ~ ~ ~ CLUES ~ ~ ~ ~ 33= __ x __ 42= __ x __ x __ 70= __ x __ x __ 91= __ x __ 104= __ x __ x __ x __ 105= __ x __ x __ 110= __ x __ x __ 110= __ x __ x __ 286= __ x __ x __ 330= __ x __ x __ x __ 364= __ x __ x __ x __ 910= __ x __ x __ x __ 1287= __ x __ x __ x __ MrV’s HexFactor # Factor each of the clues. Ex: 33 = 3 x 11, etc. 2.Find an intersection where only one factor will fit: 33 = 3 x 11 and 42 = 2 x 3 x 7 3.Fill in the factor, then fill in any others that fit. 4.Repeat steps 2 & 3 for the remaining cells ~ ~ ~ ~ CLUES ~ ~ ~ ~ 33= 3 x 11 42= 2 x 3 x 7 70= 3 x 5 x 7 91= 7 x = 2 x 2 x 2 x = 3 x 5 x 7 110= 2 x 5 x = 2 x 5 x = 2 x 11 x = 2 x 3 x 5 x = 2 x 2 x 7 x = 2 x 5 x 7 x = 3 x 3 x 11 x 13 Solution #2