Project Crashing. c=6 e=9 b=6 a=7 f=8 g=5 d=4 Given the information below, what is the total additional cost to crash the project as much as possible?

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Presentation transcript:

Project Crashing

c=6 e=9 b=6 a=7 f=8 g=5 d=4 Given the information below, what is the total additional cost to crash the project as much as possible? Activity Normal Duration Crashed Duration Normal Cost Crashed Cost Additional Cost/day a b65 65 c d e9970 f g Project Duration Crash Activity Additional Cost New Critical Path 21-- acf Path Durations a c f = 21 a d g = 16 b e g = 20 if then cost result

a d g h e f c b PERT Example Activity Immediate Predecessor Optimistic Duration Most Likely Pessimistic Duration Expected Duration t e V t Variance a b c da777 eb81112 fc gb,d he,f91011 Critical path: Expected project duration T = Standard deviation of critical path σ cp = Prob(X > 48)? Prob(X < 43)? Prob(43 < X < 48)? Predict a completion date that you’re 80% sure you can meet.