Lesson #28 - Surface Area of Prisms.

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Presentation transcript:

Lesson #28 - Surface Area of Prisms

A=pr2 A=bh 2 =p(6cm)2 =36p cm2 =(4m)(3m) 2 =113.1 cm2 =6 m2 5 m 4 m 1) Area of a Circle Area of a Triangle 3 m 4 m 5 m 6 cm A=pr2 A=bh 2 =p(6cm)2 =36p cm2 =(4m)(3m) 2 =113.1 cm2 =6 m2

A=(b1+b2)(h) A=apothem(P) 2 2 =(5mm)(6)(4mm) =(2cm+4cm)(3cm) 2 2 Area of a Polygon Area of a Trapezoid 3 cm 4 cm 2 cm 4 mm 5 mm A=apothem(P) 2 A=(b1+b2)(h) 2 =(5mm)(6)(4mm) 2 =(2cm+4cm)(3cm) 2 =60 mm2 =9 cm2

A=6s2 =6(3cm)2 A=54 cm2 2) TSA of a Cube 3 cm Homework Take-Up- 5 minutes

3) TSA of a prism 5 cm 21 cm Homework Take-Up- 5 minutes

4) TSA of a cylinder 5 cm 10 cm r=5 cm h=10 cm A cube has 6 equal area si

Homework Pg. 178 #3-5 Pg. 179 #6,8 & 12 Pg. 181 # 14ab,15