Statics, Fourteenth Edition R.C. Hibbeler Copyright ©2016 by Pearson Education, Inc. All rights reserved. In-Class Activities: Check Homework Reading Quiz.

Slides:



Advertisements
Similar presentations
Frames and Machines.
Advertisements

MOMENT OF A COUPLE (Section 4.6)
“Dynamics by Hibbeler,” Dr. S. Nasseri, MET Department, SPSU Today’s Objectives: Students will be able to: 1.Apply the three equations of motion for a.
EQUATIONS OF EQUILIBRIUM & TWO- AND THREE-FORCE MEMEBERS
WEDGES AND FRICTIONAL FORCES ON FLAT BELTS
PLANAR KINETIC EQUATIONS OF MOTION: TRANSLATION (Sections )
CTC / MTC 222 Strength of Materials
Students will be able to: a) Determine the forces on a wedge.
TRUSSES–THE METHOD OF SECTIONS (Section 6.4)
More Truss Analysis Problems
INTERNAL FORCES (Section 7.1)
FRAMES AND MACHINES (Section 6.6)
EQUATIONS OF EQUILIBRIUM & TWO- AND THREE-FORCE MEMEBERS
Engineering Mechanics: Statics
Chapter 6 Structural Analysis Section 6.6 FRAMES AND MACHINES
MECHANICS OF MATERIALS 7th Edition
MOMENT OF A COUPLE Today’s Objectives: Students will be able to
SIMPLE TRUSSES, THE METHOD OF JOINTS, & ZERO-FORCE MEMBERS
Students will be able to:
Copyright © 2010 Pearson Education South Asia Pte Ltd
Today’s Objectives: Students will be able to :
Students will be able to: a) understand and define moment, and,
EQUATIONS OF MOTION: RECTANGULAR COORDINATES
EQUATIONS OF EQUILIBRIUM & TWO- AND THREE-FORCE MEMBERS
Today’s Objectives: Students will be able to:
Engineering Mechanics: Statics
1 ENGINEERING MECHANICS STATICS & DYNAMICS Instructor: Eng. Eman Al.Swaity University of Palestine College of Engineering & Urban Planning Chapter 6: Structural.
RIGID BODY EQUILIBRIUM IN 3-D (Sections 5.5 – 5.7)
Today’s Objective: Students will be able to:
Students will be able to:
SIMPLE TRUSSES, THE METHOD OF JOINTS, & ZERO-FORCE MEMBERS
Statics, Fourteenth Edition R.C. Hibbeler Copyright ©2016 by Pearson Education, Inc. All rights reserved. In-Class Activities: Check Homework Reading Quiz.
EQUATIONS OF EQUILIBRIUM IN 2-D
EQUATIONS OF EQUILIBRIUM & TWO- AND THREE-FORCE MEMEBERS
FRAMES AND MACHINES Today’s Objectives: Students will be able to: a) Draw the free body diagram of a frame or machine and its members. b) Determine the.
MOMENT ABOUT AN AXIS Today’s Objectives:
EQUATIONS OF EQUILIBRIUM & TWO- AND THREE-FORCE MEMEBERS In-Class Activities: Check Homework, if any Reading Quiz Applications Equations of Equilibrium.
REDUCTION OF A SIMPLE DISTRIBUTED LOADING
READING QUIZ Answers: 1.D 2.A
THE METHOD OF SECTIONS In-Class Activities: Check Homework, if any Reading Quiz Applications Method of Sections Concept Quiz Group Problem Solving Attention.
CHARACTERISTICS OF DRY FRICTION & PROBLEMS INVOLVING DRY FRICTION
WEDGES AND FRICTIONAL FORCES ON FLAT BELTS
Statics, Fourteenth Edition R.C. Hibbeler Copyright ©2016 by Pearson Education, Inc. All rights reserved. In-Class activities: Check Homework Reading Quiz.
EQUATIONS OF MOTION: CYLINDRICAL COORDINATES
PLANAR KINETIC EQUATIONS OF MOTION: TRANSLATION
Dynamics, Fourteenth Edition R.C. Hibbeler Copyright ©2016 by Pearson Education, Inc. All rights reserved. In-Class Activities: Check Homework Reading.
RELATIVE MOTION ANALYSIS: VELOCITY
COMPOSITE BODIES Today’s Objective:
KINETIC ENERGY, WORK, PRINCIPLE OF WORK AND ENERGY
Dynamics, Fourteenth Edition R.C. Hibbeler Copyright ©2016 by Pearson Education, Inc. All rights reserved. Today’s Objectives: Students will be able to:
Today’s Objectives: Students will be able to:
EQUATIONS OF MOTION: ROTATION ABOUT A FIXED AXIS
EM 304 Lecture 1 Syllabus What is “Mechanics of materials”?
Statics, Fourteenth Edition R.C. Hibbeler Copyright ©2016 by Pearson Education, Inc. All rights reserved. In-Class Activities: Check homework, if any Reading.
FRAMES AND MACHINES In-Class Activities: Check Homework, if any Reading Quiz Applications Analysis of a Frame/Machine Concept Quiz Group Problem Solving.
Statics, Fourteenth Edition R.C. Hibbeler Copyright ©2016 by Pearson Education, Inc. All rights reserved. In-Class Activities: Check Homework, if any Reading.
Statics, Fourteenth Edition R.C. Hibbeler Copyright ©2016 by Pearson Education, Inc. All rights reserved. In-class Activities: Check Homework Reading Quiz.
Dynamics, Fourteenth Edition R.C. Hibbeler Copyright ©2016 by Pearson Education, Inc. All rights reserved. Today’s Objectives: Students will be able to:
Students will be able to:
FRAMES AND MACHINES Today’s Objectives: Students will be able to:
EQUATIONS OF EQUILIBRIUM & TWO- AND THREE-FORCE MEMEBERS
Statically Determine of Beams and Frames
FRAMES AND MACHINES Today’s Objectives: Students will be able to:
Students will be able to:
Students will be able to:
FRAMES AND MACHINES Today’s Objectives: Students will be able to:
Students will be able to:
Shear Force & Bending Moment Diagrams
Engineering Mechanics : STATICS
Presentation transcript:

Statics, Fourteenth Edition R.C. Hibbeler Copyright ©2016 by Pearson Education, Inc. All rights reserved. In-Class Activities: Check Homework Reading Quiz Applications Types of Internal Forces Steps for Determining Internal Forces Concept Quiz Group Problem Solving Attention Quiz Today’s Objective: Students will be able to: 1.Use the method of sections for determining internal forces in 2-D load cases. INTERNAL FORCES

Statics, Fourteenth Edition R.C. Hibbeler Copyright ©2016 by Pearson Education, Inc. All rights reserved. 1. In a multiforce member, the member is generally subjected to an internal _________. A) Normal force B) Shear force C) Bending moment D) All of the above. 2. In mechanics, the force component V acting tangent to, or along the face of, the section is called the _________. A) Axial force B) Shear force C) Normal force D) Bending moment READING QUIZ

Statics, Fourteenth Edition R.C. Hibbeler Copyright ©2016 by Pearson Education, Inc. All rights reserved. Why are the beams tapered? Internal forces are important in making such a design decision. In this lesson, you will learn about these forces and how to determine them. Beams are structural members designed to support loads applied perpendicularly to their axes. Beams can be used to support the span of bridges. They are often thicker at the supports than at the center of the span. APPLICATIONS

Statics, Fourteenth Edition R.C. Hibbeler Copyright ©2016 by Pearson Education, Inc. All rights reserved. Usually such columns are wider/thicker at the bottom than at the top. Why? A fixed column supports these rectangular billboards. APPLICATIONS (continued)

Statics, Fourteenth Edition R.C. Hibbeler Copyright ©2016 by Pearson Education, Inc. All rights reserved. Why might have this been done? The shop crane is used to move heavy machine tools around the shop. The picture shows that an additional frame around the joint is added. APPLICATIONS (continued)

Statics, Fourteenth Edition R.C. Hibbeler Copyright ©2016 by Pearson Education, Inc. All rights reserved. Then we need to cut the beam at B and draw a FBD of one of the halves of the beam. This FBD will include the internal forces acting at B. Finally, we need to solve for these unknowns using the E-of-E. For example, we want to determine the internal forces acting on the cross section at B. But, first, we first need to determine the support reactions. B The design of any structural member requires finding the forces acting within the member to make sure the material can resist those loads. B INTERNAL FORCES

Statics, Fourteenth Edition R.C. Hibbeler Copyright ©2016 by Pearson Education, Inc. All rights reserved. The loads on the left and right sides of the section at B are equal in magnitude but opposite in direction. This is because when the two sides are reconnected, the net loads are zero at the section. In two-dimensional cases, typical internal loads are normal or axial forces (N, acting perpendicular to the section), shear forces (V, acting along the surface), and the bending moment (M). INTERNAL FORCES (continued)

Statics, Fourteenth Edition R.C. Hibbeler Copyright ©2016 by Pearson Education, Inc. All rights reserved. 1. Take an imaginary cut at the place where you need to determine the internal forces. Then, decide which resulting section or piece will be easier to analyze. 2. If necessary, determine any support reactions or joint forces you need by drawing a FBD of the entire structure and solving for the unknown reactions. 3. Draw a FBD of the piece of the structure you’ve decided to analyze. Remember to show the N, V, and M loads at the “cut” surface. 4. Apply the E-of-E to the FBD (drawn in step 3) and solve for the unknown internal loads. STEPS FOR DETERMINING INTERNAL FORCES

Statics, Fourteenth Edition R.C. Hibbeler Copyright ©2016 by Pearson Education, Inc. All rights reserved. Solution 1.Plan on taking the imaginary cut at C. It will be easier to work with the right section (from the cut at C to point B) since the geometry is simpler and there are no external loads. Given: The loading on the beam. Find:The internal forces at point C. Plan:Follow the procedure!! EXAMPLE

Statics, Fourteenth Edition R.C. Hibbeler Copyright ©2016 by Pearson Education, Inc. All rights reserved. Applying the E-of-E to this FBD, we get  +  F x = B x = 0; +  M A = − B y ( 9 ) + 18 ( 3 ) = 0 ; B y = 6 kip 2. We need to determine B y. Use a FBD of the entire frame and solve the E-of-E for B y. BxBx 3 ft9 ft AyAy ByBy 18 kip 3 ft FBD of the entire beam: EXAMPLE (continued)

Statics, Fourteenth Edition R.C. Hibbeler Copyright ©2016 by Pearson Education, Inc. All rights reserved. 3. Now draw a FBD of the right section. Assume directions for V C, N C and M C. 6 kip VCVC MCMC NCNC 4.5 ft C B 4. Applying the E-of-E to this FBD, we get  +  F x = N C = 0; N C = 0  +  F y = – V C – 6 = 0; V C = – 6 kip +  M C = – 6 (4.5) – M C = 0 ; M C = – 27 kip ft EXAMPLE (continued)

Statics, Fourteenth Edition R.C. Hibbeler Copyright ©2016 by Pearson Education, Inc. All rights reserved. 1. A column is loaded with a vertical 100 N force. At which sections are the internal loads the same? A) P, Q, and R B) P and Q C) Q and R D) None of the above. P Q R 100 N 2. A column is loaded with a horizontal 100 N force. At which section are the internal loads largest? A) P B) Q C) R D) S P Q R 100 N S CONCEPT QUIZ

Statics, Fourteenth Edition R.C. Hibbeler Copyright ©2016 by Pearson Education, Inc. All rights reserved. GROUP PROBLEM SOLVING I Given: The loading on the beam. Find:The internal forces at point C. Plan:Follow the procedure!! Solution: 1. Plan on taking the imaginary cut at C. It will be easier to work with the left section (point A to the cut at C) since the geometry is simpler.

Statics, Fourteenth Edition R.C. Hibbeler Copyright ©2016 by Pearson Education, Inc. All rights reserved. GROUP PROBLEM SOLVING I (continued) 2. First, we need to determine A x and A y using a FBD of the entire frame. Applying the E-of-E to this FBD, we get  +  F x = A x = 0 ; A x = – 400 N +  M B = – A y (5) – 400 (1.2) = 0 ; A y = – 96 N 400 N ByBy AxAx AyAy Free Body Diagram

Statics, Fourteenth Edition R.C. Hibbeler Copyright ©2016 by Pearson Education, Inc. All rights reserved. GROUP PROBLEM SOLVING I (continued) 3. Now draw a FBD of the left section. Assume directions for V C, N C and M C as shown. 4. Applying the E-of-E to this FBD, we get  +  F x = N C – 400 = 0; N C = 400 N  +  F y = – V C – 96 = 0; V C = – 96N +  M C = 96 (1.5) + M C = 0 ; M C = -144 N m 96 N VCVC MCMC NCNC 1.5 m A 400 N C

Statics, Fourteenth Edition R.C. Hibbeler Copyright ©2016 by Pearson Education, Inc. All rights reserved. Solution: 1. Make an imaginary cut at C. Why there? Which section will you pick to analyze via the FBD? Given: The loading on the beam. Find:The internal forces at point C. Plan: Follow the procedure!! Why will it be easier to work with segment AC? GROUP PROBLEM SOLVING II

Statics, Fourteenth Edition R.C. Hibbeler Copyright ©2016 by Pearson Education, Inc. All rights reserved. +  M A = T ( 2.5 ) − 1800 (6) = 0 ; T = 4320 lb  +  F x = A x − 4320 = 0 ; A x = 4320 lb  +  F y = A y − 1800 = 0 ; A y = 1800 lb 2. Determine the reactions at A, using a FBD and the E- of-E for the entire frame. GROUP PROBLEM SOLVING II (continued) T AxAx AyAy 1800 lb 6 ft Free Body Diagram

Statics, Fourteenth Edition R.C. Hibbeler Copyright ©2016 by Pearson Education, Inc. All rights reserved. 3. A FBD of section AC is shown below. GROUP PROBLEM SOLVING II (continued) VCVC MCMC NCNC 1.5 ft A C 450 lb 1.5 ft FBD of Section AC 4320 lb 1800 lb 4. Applying the E-of-E to the FBD, we get  +  F x = N C = 0 ; N C = – 4320 lb  +  F y = 1800 – 450 – V C = 0 ; V C = 1350 lb +  M C = – 1800 (3) (1.5) + M C = 0 ; M C = 4725 lb  ft

Statics, Fourteenth Edition R.C. Hibbeler Copyright ©2016 by Pearson Education, Inc. All rights reserved. 2. A column is loaded with a horizontal 100 N force. At which section are the internal loads the lowest? A) P B) Q C) R D) S P Q R 100N S 1. Determine the magnitude of the internal loads (normal, shear, and bending moment) at point C. A) (100 N, 80 N, 80 N m) B) (100 N, 80 N, 40 N m) C) (80 N, 100 N, 40 N m) D) (80 N, 100 N, 0 N m ) C 0.5m 1 m 80 N 100 N ATTENTION QUIZ

Statics, Fourteenth Edition R.C. Hibbeler Copyright ©2016 by Pearson Education, Inc. All rights reserved.