Section 3.2 Solving Equations using Multiplication and Division.

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Presentation transcript:

Section 3.2 Solving Equations using Multiplication and Division.

Solving Equations Remember: to solve an equation, you must isolate the variable and it must have a coefficient of positive 1! To isolate the variable, get rid of everything around it by doing the OPPOSITE action

1) Solve. -5t = 60 To get the variable by itself, which number needs to be moved? -5 To move the -5, you have to do the opposite operation. What operation will we use? division

1) Solve -5t = t = (-12) = 60 1.Draw a vertical line to separate the equation into 2 sides 2.Divide both sides by -5 3.Simplify 4.Check your answer

2) Solve 15 = 6n = n 15 = 6(2.5) 1.Draw a vertical line 2.Divide both sides by 6 3.Simplify 4.Check your answer

3) Solve -3v = v = v = v = 43 4.v = 126 Answer Now

4) Solve You don’t like fractions? Let’s get rid of them! “Clear the fraction” by multiplying both sides of the equation by the denominator.

4) Solve 4 · · 4 x = Draw a vertical line 2.Clear the fraction – multiply both sides by 4 3.Simplify 4.Check your answer

3 · = 18 · 3 2x = x = 27 1.Draw a vertical line 2.Clear the fraction – multiply both sides by 3 3.Simplify 4.Divide both sides by 2 5.Simplify 6.Check your answer 5) Solve = 18

6) Which step clears the fraction in 1.Multiply by 3 2.Multiply by 5 3.Multiply by Multiply by -5 Answer Now

7) Solve 1.b = b = b = 14 4.b = 56 Answer Now

9/11/13 Homework: Workbook page 19