Stereographic projection

Slides:



Advertisements
Similar presentations
11.6 Surface Area and Volumes of Spheres
Advertisements

Lesson 12—Working with Space Groups How to convert a space group to a point group Adding the translational elements Calculating the coordinates of the.
THE ELLIPSE. The Ellipse Figure 1 is ellipse. Distance AB and CD are major and minor axes respectively. Half of the major axis struck as a radius from.
Point Groups (Crystal Classes)
10 Conics, Parametric Equations, and Polar Coordinates
APPLICATION OF VECTOR ADDITION
Stereographic projection
Introduction to Mineralogy Dr. Tark Hamilton Chapter 6: Lecture Crystallography & External Symmetry of Minerals Camosun College GEOS 250 Lectures:
III Crystal Symmetry 3-1 Symmetry elements (1) Rotation symmetry
Honors Geometry Section 10.3 Trigonometry on the Unit Circle
II Crystal Structure 2-1 Basic concept
Polar Coordinates Objective: To look at a different way to plot points and create a graph.
Introduction and point groups Stereographic projections Low symmetry systems Space groups Deformation and texture Interfaces, orientation relationships.
(The figures in this section of your text are especially important)
Integral Calculus One Mark Questions. Choose the Correct Answer 1. The value of is (a) (b) (c) 0(d)  2. The value of is (a) (b) 0 (c) (d) 
Drill Calculate:.
PARAMETRIC EQUATIONS AND POLAR COORDINATES 9. Usually, we use Cartesian coordinates, which are directed distances from two perpendicular axes. Here, we.
Stereonets Solving geometerical problems – displays geometry and orientation os lines and planes. It is a three-dimensional protractor. With a normal protractor,
Stereographic Projection
Field trip this Saturday! We will leave from the loading dock at 7:30 AM sharp! HYDRATE... or else! BRING >1 GALLON OF WATER!
13.2 Angles and Angle Measure
3.4 Area and Circumference 1 Circle A circle is a plane figure that consists of all points that lie the same distance from a fixed point. The fixed point.
Structural Geology Stereographic Projections
Surface Area of Cones and Spheres Cone – The circular counterpart of a pyramid. Every cone has one face that is its base. This base is a circular region.
It is therefore drawn in the Front View
(SEC. 7.3 DAY ONE) Volumes of Revolution DISK METHOD.
POLAR COORDINATES (Ch )
Problem: A vertical cone, base diameter 75 mm and axis 100 mm long,
On The Graph Name that Transform- ation Lesson 3 Vocabulary Prisms Lesson 4 Vocabulary
Section Plane Through Apex Section Plane Through Generators Section Plane Parallel to end generator. Section Plane Parallel to Axis. Triangle Ellipse Parabola.
Terrestrial Coordinate System
f30 G1 G A a F B E C D T F A1 A G G1 B C G A 50 G1 A1
1 Combining rotation axes Should be obvious that: C 1 C 2 = C 3 C1C1 C2C2 C1C1 C2C2 C3C3 C3C3.
X-ray diffraction. Braggs' law = 2d hkl sin  hkl X-ray diffraction From this set of planes, only get reflection at one angle -  From this set of planes,
Divide into meridian sections – Gore development
This is the trace of the strain tensor. In general the trace of the strain tensor gives area change in 2-D and volume change in 3-D The principal axes.
Chapter 9 DISTRIBUTED FORCES: MOMENTS OF INERTIA x y y dx x The rectangular moments of inertia I x and I y of an area are defined as I x = y 2 dA I y =
PAP: Perpendicular to HP and 45o to VP.
Problem For the 5 x 3 x -in. angle cross
Crystallography ll.
Copyright © Cengage Learning. All rights reserved. 16 Vector Calculus.
PRESENTATION ON INTERSECTION OF SOLIDS by Mr.Venkata Narayana Mr.A.S.Pavan Kumar Department of Mechanical Engineering SNIST.
Construction of the true size of a plane figure Plane figures in the horizontal/vertical/profile projecting planes 1. Determine the true size of a triangle.
SECTION 2.1 EQ: How do the x- and y-coordinates of a point in the Cartesian plane relate to the legs of a right triangle?
References: Dexter Perkins, 2002, Mineralogy, 2nd edition. Prentice Hall, New Jersey, 483 p. Bloss, F.D., 1971, Crystallography and Crystal Chemistry:
Constraints. Constraints in Inventor ? Constraints Defined Constraint - The state of being restricted or confined within prescribed bounds.
9.2 Latitude and longitude
Point Groups (Crystal Classes)
Crystal Forms
Basic Crystallography for X-ray Diffraction Earle Ryba.
Design and Communication Graphics
Unit Circle ( √3, 1 ) 2 2 ( 1, √3 ) 2 2 ( √2, √2 ) ˚ 45˚ 60˚
GEOMETRY CHAPTER 11 SUMMARY. Three-dimensional figures, or solids, can be made up of flat or curved surfaces. Each flat surface is called a face. An edge.
1 Crystals possess different symmetry elements. The definite ordered arrangement of the faces and edges of a crystal is known as `crystal symmetry’. CRYSTAL.
Crystal Structure and Crystallography of Materials
Writing Equations of Circles. Remember Equation: (x-h) 2 +(y-k) 2 =r 2 Center (h, k) Radius = r So, to write the equation of a circle, we need the center.
Objective: Use unit circle to define trigonometric functions. Even and odd trig functions. Warm up 1.Find and. 2.Give the center and radius of a circle.
1 CHAPTER 2C- Mohr’s Circle Dr. Zuhailawati Hussain EBB 334 Mechanical Metallurgy.
Lecture 5: Hemispherical Projection & Slopes
CURVES IN ENGINEERING.
Chapter V. The Sphere 48. The equation of the sphere
Unit 3 Parallel and Perpendicular Lines Review Problems
Divide into meridian sections – Gore development
X-ray diffraction.
Materials Science and Metallurgy Course C6: Crystallography
Crystallography H. K. D. H. Bhadeshia Introduction and point groups
A movement of a figure in a plane.
CURVE TRACING.
A B C c b a c A B H= a(sinB) B = drill plunge a =(cSinA/SinC)
Fundamentals of Geodesy
Presentation transcript:

Stereographic projection *Any plane passing the center of the reference sphere intersects the sphere in a trace called great circle * A plane can be represented by its great circle or pole, which is the intersection of its plane normal with the reference sphere

Stereographic projection

Pole on upper sphere can also be projected to the horizontal (equatorial) plane

Projections of the two ends of a line or plane normal on the equatorial plane are symmetrical with respect to the center O.

Projections of the two ends of a line or plane normal on the equatorial plane are symmetrical with respect to the center O. U P’ X P’ P O O P L

A great circle representing a plane is divided to two half circles, one in upper reference sphere, the other in lower sphere Each half circle is projected as a trace on the equatorial plane The two traces are symmetrical with respect to their associated common diameter

N W E S

The position of pole P can be defined by two angles f and r

The position of projection P’ can be obtained by r = R tan(r/2)

The trace of each semi-great circle hinged along NS projects on WNES plane as a meridian

As the semi-great circle swings along NS, the end point of each radius draws on the upper sphere a curve which projects on WNES plane as a parallel

The weaving of meridians and parallels makes the Wulff net

Two projected poles can always be rotated along the net normal to a same meridian (not parallel) such that their intersecting angle can be counted from the net

P : a pole at (F1,1) NMS : its trace

The projection of a plane trace and pole can be found from each other by rotating the projection along net normal to the following position

Terms about zone Zone axis Zone pole: direct projection of a zone axis Zone plane : the plane ⊥ zone axis Zone circle: intersection of a zone plane with the reference circle

Zone circle and zone pole

Trace of P2’: zone circle If P2’ is the projection of a zone axis, then all poles of the planes parallel to the zone axis lie on the trace of P2’ P2’: zone pole Trace of P2’: zone circle

Rotation of a poles about NS axis by a fixed angle: the corresponding poles moving along a parallel *Pole A1 move to pole A2 *Pole B1 moves 40° to the net end then another 20° along the same parallel to B1’ corresponding to a movement on the lower half reference sphere, pole corresponding to B1’ on upper half sphere is B2

m: mirror plane F1: face 1 F2: face 2 N1: normal of F1 N2: normal of N2 N1, N2 lie on a plane which is 丄to m

A plane not passing through the center of the reference sphere intersects the sphere on a small circle which also projects as a circle, but the center of the former circle does not project as the center of the latter.

Projection of a small circle centered at Y

Rotation of a pole A1 along an inclined axis B1: B1B3  B2  B2  B3  B1 A1A1  A2  A3  A4  A4 A plane not passing through the center of the reference sphere intersects the sphere on a small circle which also projects as a circle.

Rotation of a pole A1 along an inclined axis B1:

A small circle with center C’, after projection, Small circle  circle A1, A4, D (centering at C) and C’ B1

Rotation of 3 directions along b axis

Rotation of 3 directions along b axis

Rotation of 3 directions along b axis

Standard coordinates for crystal axes

Standard coordinates for crystal axes

Standard coordinates for crystal axes

Standard coordinates for crystal axes

Projection of a monoclinic crystal -110 -1-10 -a 0-1-1 01-1 x x -b +b +C 0-11 011 +a 110 1-10

Projection of a monoclinic crystal

Projection of a monoclinic crystal

Projection of a monoclinic crystal

(a) Zone plane (stippled) (b) zone circle with zone axis ā, note [100]•[0xx]=0

Location of axes for a triclinic crystal: the circle on net has a radius of a along WE axis of the net

Zone circles corresponding to a, b, c axes of a triclinic crystal

Standard projections of cubic crystals on (a) (001), (b) (011)

d/(a/h)=cosr, d/(b/k)=coss, d/(c/l)=cost h:k:l=acosr : bcoss : ccost measure 3 angles to calculate hkl

The face poles of six faces related by -3 axis that is (a) perpendicular (b) oblique to the plane of projection

Homework assignment Textbook of Bloss 4-3 p1(f=60, =50), p2 (f=-70, =35) 4-5 A (f=-50, =45), B (f=20, =90) 4-8 p (f=50, =40)

Prob. 4-3 Answer sinsinf sincosf cos p1(f=60, =50) 0.6634 0.3830 0.6428 p2(f=-70, =35) -0.5390 0.1962 0.8192 C=AxB/|AxB| 0.1935 -0.91765 0.3471 C (zone axis) f= 168.10, =69.69 p1^p2 = 75.87

Prob. 4-5 Answer sinsinf sincosf cos A (f=-50, =45) -0.5417 0.4545 0.7071 B (f=20, =90) 0.3420 0.9397 C=AxB/|AxB| -0.6848 0.2418 C (face pole) f=-70.6, (F=109.4) =133.2 (=46.8) A^B = 76

4-8 Answer f=-106, =-30 (a) (b) f=-106,  = -30 f= -88,  = 60

*great circle WNES is projected to W’N’E’S’ *Pole P is projected to P’