The Shape of Covalent Molecules 1. VSEPR Theory 2. Different ways to draw covalent bond 3. Different shapes of molecules 4. Shapes of molecules with lone pair of electrons in the central atom 5. Predict the Shapes of molecules without multiple bonds 6. Shapes of Molecules with Multiple Bonds
VSEPR Theory Q. What is the charge of an electron carries? A. -ve Q. What will happen if two bond pairs of electrons are placed around a central atom? A. They will stay as far apart as possible to minimize the electronic repulsion. This is the key concept of VSEPR Theory. If you know the no. of electron pairs around the central atom, you can predict the shape of the molecule.
Different ways to draw covalent bond
Different shapes of molecules If there are 2 electron pairs, the shape of the molecule is ________ linear.
If there are 3 electron pairs, the shape of the molecule is ____________ trigonal planar
If there are 4 electron pairs, the shape of the molecule is ____________ tetrahedral
If there are 5 electron pairs, the shape of the molecule is ___________________ trigonal bipyramidal
If there are 6 electron pairs, the shape of the molecule is ____________ octahedral.
Shapes of molecules with lone pair of electrons in the central atom
Change of molecular shape 3 valence pairs of electrons Trigonal planar V-shaped
Trigonal pyramidal Tetrahedral V-shaped
Trigonal bipyramidal Unsymmetrical tetrahedral T-shaped Linear
Square pyramidal Square planar Octahedral
Predict the Shapes of molecules without multiple bonds 1. Count the no. of outermost e- in the central atom. 2. Add one if the particle has one negative charge or subtract one if it has one positive charge. 3. Add one for each bonding atom. 4. no. of pairs of e- = total / 2 5. no. of lone pair = no. of pairs of e- - no. of bonded atoms
e.g. 1, PCl4+ 1. Count the no. of outermost e- in the central atom. 5 ( P is group 5) 2. Add one if the particle has one negative charge or subtract one if it has one positive charge. 5 - 1 = 4 (the particle has 1 +ve charge) 3. Add one for each bonding atom. 4 + 4 = 8 (there are 4 Cl atoms) 4. no. of pairs of e- = total / 2 8 / 2 = 4 5. no. of lone pair = no. of pairs of e- - no. of bonded atoms 4 - 4 = 0 tetrahedral
e.g. 2, XeF2 1. Count the no. of outermost e- in the central atom. 8 ( Xe is group 0) 2. Add one if the particle has one negative charge or subtract one if it has one positive charge. 8 (the particle does not have charge) 3. Add one for each bonding atom. 8 + 2 = 10 (there are 2 F atoms) 4. no. of pairs of e- = total / 2 10 / 2 = 5 5. no. of lone pair = no. of pairs of e- - no. of bonded atoms 5 - 2 = 3 linear
Shapes of Molecules with multiple bonds Both e- pairs must stay together in a double bond or triple bond. We can treat them as single bonds. e.g. CO2 There are 2 double bonds and no lone pair. linear
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