 Solve the following…  6 = x + 2  4 = q + 13  23 = b - 19  5b = 145  -7y = 28  2/3q = 18  1/5x = 2/7

 Step 1: Always add or subtract  Step 2: Always multiply or divide  To solve, use these steps Identify the operations and undo them using inverse operations

 2x + 3 =15 Step 1: Need to subtract 3 since it is inverse of addition  2x + 3 – 3 =  2x = 12 Step 2: Need to divide 12 by 2 since it is inverse of multiplication  2x/2 = 12/2 X = 6 Check Answers by plugging in 2(6) + 3 = 15

 5 = t/2 – 3  Step 1: Add 3 to both sides since it is inverse of subtraction  = t/s –  8 = t/2  Step 2: Multiply by 2 on both sides since it is inverse of division  8 x 2 = t/2 x 2

 T=16  Check Answers by pulling in

 2 + a/4 = -1  3n – 4 = 11  5x + 12 = -13  6 = m/7 - 3

Write an equation for this word problem. 1/2a + 5 = 18 Solve A = 26

REMEMBER STEPSCHECK ANSWERS  X-7 =  6 = x – 2 4  d – 3 = 6 5  a + 10 = 4 2

 Members of a car-sharing program pay a fee of $50 per month plus $7.65 for every hour they use a car. A member’s bill was $ last month. How many hours did the customer use a car last month?  Equation: $7.65h + 50 = $  Solution: 13 hours