Chapter 12: Stoichiometry 12.1 The Arithmetic of Equations.

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Presentation transcript:

Chapter 12: Stoichiometry 12.1 The Arithmetic of Equations

Example At a sandwich shop, the sandwich requires 2 pieces of bread, 3 slices of meat and 1 slice of cheese. You need to make 50 sandwiches. How much of each do you need?

Proportional Relationships I have 5 eggs. How many cookies can I make? 3/4 c. brown sugar 1 tsp vanilla extract 2 eggs 2 c. chocolate chips Makes 5 dozen cookies. 2 1/4 c. flour 1 tsp. baking soda 1 tsp. salt 1 c. butter 3/4 c. sugar

Using Balanced Chemical Equations Chemists use balanced chemical equations as a basis to calculate how much reactant is needed or product is formed in a reaction. The calculation of quantities in chemical reactions is a subject of chemistry called stoichiometry. 12.1

Interpreting Chemical Equations A balanced chemical equation can be interpreted in terms of different quantities, including numbers of atoms, molecules, or moles; mass; and volume. 12.1

Example: Balance and state in terms of molecules and moles C 3 H 8 + O 2 → CO 2 + H 2 O

Practice 1) NO + H 2 → N 2 + H 2 O 2) SiH 4 + NH 3 → Si 3 N 4 + H 2 3) H 2 + O 2 → H 2 O

12.1 Mass Conservation in Chemical Reactions –Mass and atoms are conserved in every chemical reaction.

Conceptual Problem 12.1

for Conceptual Problem 12.1

12.2 Chemical Calculations

Writing and Using Mole Ratios Mole-Mole Calculations –A mole ratio is a conversion factor derived from the coefficients of a balanced chemical equation interpreted in terms of moles. 12.2

Sample Problem 12.2

for Sample Problem 12.2

Practice 1) CH 4 + 2O 2 → CO 2 + 2H 2 O –How many mol of O 2 are required to react with 7.4 mol methane? –How many mol of CO 2 are produced by 2.6 mol O 2 ?

Practice 2) Calculate the number of moles of O 2 required to react with 4.30 mol propane: C 3 H 8 + 5O 2 → 3CO 2 + 4H 2 O

Example Determine the mass of sodium chloride produced when 1.25 mol chlorine gas reacts with sodium

Practice 1) TiO 2 + C + 2Cl 2 → TiCl 4 + CO 2 –If you begin with 1.25 mol TiO 2, what mass of Cl 2 gas is needed?

Practice 2) Sodium chloride is decomposed into its elements sodium and chlorine. How many grams of chlorine gas can be obtained from 2.50 mol NaCl?

Example If you began the reaction with 2.00 g of Al 2 O 3, how many moles of O 2 will you end up with?

Example If the reaction ended with 23.7 mol Al, how many grams of O 2 would it also end with?

Sample Problem 12.3

for Sample Problem 12.3

Practice 1) 2Al + 3I 2 → 2AlI 3 –Calculate the mass if I 2 needed to react with 35.0 g Al

Practice 2) 2NaOH + CO 2 → Na 2 CO 3 + H 2 O –Calculate the mass of CO 2 to react with 10.0 g NaOH –Calculate the mass of Na 2 CO 3 produced when 10.0 g NaOH reacts with excess CO 2

Other Stoichiometric Calculations –In a typical stoichiometric problem, the given quantity is first converted to moles. Then the mole ratio from the balanced equation is used to calculate the number of moles of the wanted substance. Finally, the moles are converted to any other unit of measurement related to the unit mole, as the problem requires. 12.2

Sample Problem 12.4

for Sample Problem 12.4

Sample Problem 12.5

for Sample Problem 12.5

Sample Problem 12.6

for Sample Problem 12.6

2KClO 3 → 2KCl + 3O 2 How many molecules of O 2 are formed from 5.45 g KClO 3 ? How many liters of O 2 are made when 9.83 g of KCl are formed?

12.2 Section Quiz. –1.How many moles of water are produced when 2.5 mol of O 2 react according to the following equation? –C 3 H 8 + 5O 2  3CO 2 + 4H 2 O a) 2.0 b) 2.5 c) 3.0 d) 4.0

–2.Given N 2 (g) + 3H 2 (g)  2NH 3 (g) what volume of H 2 is required to react with 3.00 L of N 2, and what volume of NH 3 is produced at 200°C? a) H 2 = 9.00 L, NH 3 = 6.00 L b) H 2 = 3.00 L, NH 3 = 3.00 L c) H 2 = 3.00 L, NH 3 = 6.00 L d) H 2 = 1.00 L, NH 3 = 1.50 L 12.2 Section Quiz

–3.Automotive airbags inflate using this reaction: 2NaN 3  2Na + 3N 2. How many grams of sodium azide are required to form 5.00 g of nitrogen gas? a) g b) g c) 7.74 g d) 1.36 g 12.2 Section Quiz

12.3 Limiting Reactant and Percent Yield

What does limiting mean? A sandwich consists of two slices of bread, 3 slices of meat, and one slice of cheese. For each of the following amounts, determine the number of sandwiches that can be made and what is left over: 6 bread, 10 meat, 4 cheese slices 10 bread, 6 meat, 8 cheese slices 25 bread, 15 meat, 12 cheese slices

Limiting and Excess Reagents In a chemical reaction, an insufficient quantity of any of the reactants will limit the amount of product that forms. –The limiting reagent is the reagent that determines the amount of product that can be formed by a reaction. 12.3

Limiting and Excess Reagents In the reaction of nitrogen and hydrogen, hydrogen is the limiting reagent. Nitrogen is the reagent that is not completely used up in the reaction. The reagent that is not used up is called the excess reagent. 12.3

Sample Problem 12.7

for Sample Problem 12.7

Sample Problem 12.8

for Sample Problem 12.8

Example 2Al + 3Cl 2 → 2AlCl 3 –10 g of Al react with 35 g Cl 2, what mass of AlCl 3 is produced? –What mass of which reactant is left after the reaction?

Practice 1) Fe 2 O 3 + 3CO → 2Fe + 3CO 2 –If 5.0 g Fe 2 O 3 reacts with 5.0 g CO, what mass of iron will be produced? –What mass of CO 2 will be produced?

Percent Yield The percent yield is a measure of the efficiency of a reaction carried out in the laboratory. A batting average is actually a percent yield. 12.3

Percent Yield –The theoretical yield is the maximum amount of product that could be formed from given amounts of reactants. –In contrast, the amount of product that actually forms when the reaction is carried out in the laboratory is called the actual yield. 12.3

Percent Yield The percent yield is the ratio of the actual yield to the theoretical yield expressed as a percent. 12.3

Sample Problem 12.9

for Sample Problem 12.9

Sample Problem 12.10

for Sample Problem 12.10

Practice 1) Al(OH) 3 + 3HCl → AlCl 3 + 3H 2 O –If 14 g of Al(OH) 3 is present, determine the theoretical yield of AlCl 3. –If the actual yield is 22.0 g, what is the percent yield?

Practice 2) 2NH 3 + CO 2 → CN 2 H 4 O + H 2 O –100 g of ammonia reacts with 100 g carbon dioxide and 120 g of urea is produced. Determine the percent yield.

12.3 Section Quiz. –1.In the reaction 3NO 2 + H 2 O  2HNO 3 + NO, how many grams of HNO 3 can form when 1.00 g of NO 2 and 2.25 g of H 2 O are allowed to react? a) g b) g c) 15.7 g d) 1.37 g

12.3 Section Quiz. –2.How many grams of H 2 O can be formed from 24.0 g O 2 and 6.00 g H 2 ? a) 30.0 g b) 27.0 g c) 54.0 g d) 13.5 g

3.Octane burns according to the following equation. 2C 8 H O 2  16CO H 2 O What is the percent yield if 14.6 g of CO 2 are produced when 5.00 g of C 8 H 18 are burned? a) 106% b) 94.8% c) 34.2% d) 62.5% 12.3 Section Quiz.