M May Pythagoras’ Theorem The square on the hypotenuse equals the sum of the squares on the other two sides.

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Presentation transcript:

M May Pythagoras’ Theorem The square on the hypotenuse equals the sum of the squares on the other two sides

M May c2 = a2 + b2c2 = a2 + b2

c 2 = a 2 + b 2 a = 12,b = 5 c 2 = c 2 = c 2 = 169 c = √169 c = 13 By Pythagoras’ Theorem

M May c 2 = a 2 + b 2 a = 15,c = = b = b 2 b 2 = b 2 = 400 b = √400 b = 20 By Pythagoras’ Theorem

M May Calculate x in each triangle (give answers to 1 dec pl). x 6 8 (a) x 7 3 (b) x 9 9 (c) x 2 9 (d) x 12 8 (e) x (f) 9 x 11 (g) x (h)

M May Calculate x in each triangle (give answers to 1 dec pl). x 6 8 (a) x 7 3 (b) x 9 9 (c) x 2 9 (d) By Pythagoras’ Th m. x 2 = x 2 = x 2 = 100 x = √ 100 x = 10 By Pythagoras’ Th m. x 2 = x 2 = x 2 = 58 x = √ 58 x = 7.6 By Pythagoras’ Th m. x 2 = x 2 = x 2 = 162 x = √ 162 x = 12.7 By Pythagoras’ Th m. x 2 = x 2 = x 2 = 85 x = √ 85 x = 9.2

M May Calculate x in each triangle (give answers to 1 dec pl). By Pythagoras’ Th m = x = x x 2 = x 2 = 80 x = √ 80 x = 8.9 By Pythagoras’ Th m = x = x x 2 = x 2 = 231 x = √ 231 x = 15.2 By Pythagoras’ Th m = x = x x 2 = x 2 = 40 x = √ 40 x = 6.3 By Pythagoras’ Th m = x = x x 2 = x 2 = 225 x = √ 225 x = 15 x 12 8 (e) 9 x 11 (g) x (h) x (f)