AZOT. Nitrogen was discovered by Daniel Rutherford at 1772 in Scotland. Origin of name: from the Greek words "nitron genes" meaning "nitre" and "forming"

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Presentation transcript:

AZOT

Nitrogen was discovered by Daniel Rutherford at 1772 in Scotland. Origin of name: from the Greek words "nitron genes" meaning "nitre" and "forming" and the Latin word "nitrum" (nitre is a common name for potassium nitrate, KNO 3 )discoveredOrigin of name

Eldesi NH 4 NO 2 = N 2 + 2H 2 0 2NaN 3 = 3N 2 + 2Na (NH 4 ) 2 Cr = N 2 + Cr H 2 0 3CuO + 2NH 3 = N 2 + 3Cu + 3H Fe + 6KN0 3 = 3N 2 + 3K Fe Mg + 12HNO 3 = N 2 + 5Mg(N0 3 ) 2 + 6H 2 0

N 2 = 2N H 298 = 945,3 kj/mol 6Li+N 2 =2Li 3 N 3Ca+N 2 =Ca 3 N 2 CI 3 N +3H 2 0= 3HClO+NH 3 Na 3 N + 3H 2 0 = 3NaOH + NH 3

Li 3 N + AlN = Li 3 AlN 2 5Li 3 N + Ge 3 N 4 = 3Li5CeN 3 N 2 + 3H 2 = 2NH 3 2NH 4 Cl + Ca(OH) 2 = 2NH 3 + 2H CaCl 2

2NH 3 = NH NH 2- 2H20 = H 3 O + + OH - 2Na + 2NH 3 = 2NaNH 2 + H 2 PCl 5 + 8NH 3 = PN(NH 2 ) 2 + 5NH 4 Cl S0 2 Cl 2 + 4NH 3 = S0 2 (NH 2 ) 2 + 2NH 4 Cl

NH 3 + H 2 0 = NH 4 0H NH 3 + HCl = NH 4 Cl 2NH 3 + H 2 S0 4 = (NH 4 ) 2 S0 4

2Al + 2NH 3 = 2AlN + 3H 2 3Mg + 2NH 3 = Mg 3 N 2 + 3H 2 2K + 2NH 3 = 2KNH 2 + H 2 Ca + NH 3 = CaNH + H 2

4NH = 2N 2 + 6H 2 0 4NH 3 + 5O 2 = 4NO + 6H 2 0 2NH 3 + NaCIO = N 2 H 4 + NaCl + H 2 0 NH 3 + NaClO = NH 2 Cl + NaOH NH 2 Cl + NH 3 = NH 2 -NH 2 + HCl NaOH + HCl = NaCl + H20

4KMnO 4 + 5N 2 H 4 + 6H 2 SO 4 = 5N 2 + 4MnSO4 + 2K 2 SO H 2 O N 2 H 4 + O 2 = N 2 + 2H 2 0 3NaNH 2 + NaNO 3 = NaN 3 + 3NaOH + NH 3 2NaN 2 + H 2 S0 4 = 2HN 3 + Na 2 S0 4 N 2 H 4 + HN0 2 = HN 3 + 2H 2 0 HNa =H + + Na - K. =

2NaN 3 = 2Na + 3N 2 3HN(N 2 ) + 9HCl + 2Au = 2AuCl 3 + 3N 2 + 3NH 4 Cl HN 3 + 2KMn H 2 S0 4 = 15N 2 + K 2 S MnS H 2 O HN 3 + 4H 2 =3NH 2 HN H = NH20H + 2H 2 0 NH 2 OH + HCl = (HONH 3 )Cl 2NH 2 0H + H 2 S0 4 = (HONH 3 ) 2 S0 4

2NH 2 0H + I 2 + 2KOH = N 2 + 2KI + 4H 2 O 2NH 2 0H + 4FeS H 2 S0 4 = (NH 4 ) 2 S Fe 2 (S0 4 ) 3 + 2H 2 O 3NH 2 0H = H 3 N + N 2 + 3H2O NH 4 NO 3 = N H 2 0

2NaN Na + 2H 2 0 = Na 2 N NaOH 3Cu + 8HNO 3 = 2NO + 3Cu(NO 3 ) 2 + 4H20 NaN0 2 + FeCI 2 + 2HCl = NO + FeCl 3 + NaCl + H 2 0 3KN0 2 +KNO 3 + Cr = 4NO + 2K 2 Cr0 4

N2 + O 2 = 2NO 2NO + Cl 2 = 2NOCI Na + NO= NaNO [Fe(H 2 0)6 ]S0 4 + NO = [Fe(H 2 O)5NO]SO 4 + H 2 O NO + NO 2 = N HN0 2 + H 2 S = S + 2NO + 2H 2 0 5NaNO 2 + 2KMn H 2 S0 4 = 5NaNO 3 +2MnS0 4 +K 2 S0 4 +3H 2 O

NO + HNO 3 = HN0 3 3HNO 2 = HN NO + H 2 O NaN0 3 + C = NaNO 2 + CO NaN0 3 + Pb = NaNO 2 + PbO NaN0 3 + Fe = NaN0 2 + FeO Cu + 4HN0 3 = Cu(N0 3 ) + 2NO 2 + 2H 2 O 2Pb(N0 3 ) 2 = 2PbO + 4NO 2 + O 2 2NO 2 + H 2 O = HN0 2 + HN0 3

2NO 2 + 2KOH = KNO 2 + KNO 3 + H 2 O 2HNO 3 + P 2 O 5 = 2N HPO 3 4AgNO 3 + 2Cl 2 = 2N 2 O 5 + 4AgCl + O 2 N 2 O = N 2 O NaNO 3 + H 2 S0 4 = 2HN0 3 + Na 2 S0 4 N 2 +O 2 = 2NO 4NO + 2H 2 O = 4HNO 3

N 2 + 3H 2 = 2NH 3 4NH = 4NO + 6H 2 O 4NO + 2H 2 O + 3O 2 = 4HNO 3 4HN0 3 = 4NO 2 + 2H 2 O + O 2 NO 2 =7HNO 3 = 7NO =7N 2 O = 7N 2 =7NH 3 (NH 4 NO 3 ) Au + 3HCl + HN0 3 = AuCl 3 + NO + 2H 2 O AuCl 3 + HCl = H[AuCl 4 ] 6HCl + 2HN0 3 = 2NO + 3Cl 2 + 4H 2 O 2NO + Cl 2 = 2NOCI AuCl 3 + NOCI = (NO)[AuCl 4 ]