Lesson 2 Ion Concentration. 1. What is the concentration of each ion in a 0.300 M AlCl 3 solution? AlCl 3  Al 3+ +3Cl -

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Lesson 2 Ion Concentration

1. What is the concentration of each ion in a M AlCl 3 solution? AlCl 3  Al 3+ +3Cl -

1. What is the concentration of each ion in a M AlCl 3 solution? AlCl 3  Al 3+ +3Cl M

1. What is the concentration of each ion in a M AlCl 3 solution? AlCl 3  Al 3+ +3Cl M

1. What is the concentration of each ion in a M AlCl 3 solution? AlCl 3  Al 3+ +3Cl M0.300 M0.900 M

2. What is the concentration of each ion in the solution formed by dissolving 80.0 g of CaCl 2 in mL of water? Molarity=

2. What is the concentration of each ion in the solution formed by dissolving 80.0 g of CaCl 2 in mL of water? Molarity=80.0 g x 1 mole g

2. What is the concentration of each ion in the solution formed by dissolving 80.0 g of CaCl 2 in mL of water? Molarity=80.0 g x 1 mole g L

2. What is the concentration of each ion in the solution formed by dissolving 80.0 g of CaCl 2 in mL of water? Molarity=80.0 g x 1 mole g L =1.20 M

2. What is the concentration of each ion in the solution formed by dissolving 80.0 g of CaCl 2 in mL of water? Molarity=80.0 g x 1 mole g L =1.20 M CaCl 2  Ca 2+ +2Cl -

2. What is the concentration of each ion in the solution formed by dissolving 80.0 g of CaCl 2 in mL of water? Molarity=80.0 g x 1 mole g L =1.20 M CaCl 2  Ca 2+ +2Cl M

2. What is the concentration of each ion in the solution formed by dissolving 80.0 g of CaCl 2 in mL of water? Molarity=80.0 g x 1 mole g L =1.20 M CaCl 2  Ca 2+ +2Cl M2.40 M

3. If 40.0 mL of M Potassium chloride solution is added to 60.0 mL of M Calcium nitrate solution, what is the resulting concentration of all ions? KCl  K + +Cl x0.400 M =0.160 M0.160 M Dilution Factor Ca(NO 3 ) 2  Ca 2+ +2NO x0.600 M =0.360 M0.720 M 100.0

4. If the [Cl - ] = M, calculate the number of grams AlCl 3 that would be dissolved in 3.00 L of water.

4. If the [Cl - ] = M, calculate the number of grams AlCl 3 that would be dissolved in 3.00 L of water. AlCl 3  Al 3+ +3Cl M

4. If the [Cl - ] = M, calculate the number of grams AlCl 3 that would be dissolved in 3.00 L of water. AlCl 3  Al 3+ +3Cl M0.600 M

4. If the [Cl - ] = M, calculate the number of grams AlCl 3 that would be dissolved in 3.00 L of water. AlCl 3  Al 3+ +3Cl M0.200 M0.600 M

4. If the [Cl - ] = M, calculate the number of grams AlCl 3 that would be dissolved in 3.00 L of water. AlCl 3  Al 3+ +3Cl M0.200 M0.600 M 3.00 L

4. If the [Cl - ] = M, calculate the number of grams AlCl 3 that would be dissolved in 3.00 L of water. AlCl 3  Al 3+ +3Cl M0.200 M0.600 M 3.00 L x mole 1 L

4. If the [Cl - ] = M, calculate the number of grams AlCl 3 that would be dissolved in 3.00 L of water. AlCl 3  Al 3+ +3Cl M0.200 M0.600 M 3.00 L x mole x g = 1 L 1 mole

4. If the [Cl - ] = M, calculate the number of grams AlCl 3 that would be dissolved in 3.00 L of water. AlCl 3  Al 3+ +3Cl M0.200 M0.600 M 3.00 L x mole x g = 80.1 g 1 L 1 mole

5. If the [SO 4 2- ] = M in 20.0 mL of Ga 2 (SO 4 ) 3, determine the [Ga 3+ ] and the molarity of the solution.

Ga 2 (SO 4 ) 3  2Ga 3+ +3SO 4 2-

5. If the [SO 4 2- ] = M in 20.0 mL of Ga 2 (SO 4 ) 3, determine the [Ga 3+ ] and the molarity of the solution. Ga 2 (SO 4 ) 3  2Ga 3+ +3SO M

5. If the [SO 4 2- ] = M in 20.0 mL of Ga 2 (SO 4 ) 3, determine the [Ga 3+ ] and the molarity of the solution. Ga 2 (SO 4 ) 3  2Ga 3+ +3SO M0.900 M

5. If the [SO 4 2- ] = M in 20.0 mL of Ga 2 (SO 4 ) 3, determine the [Ga 3+ ] and the molarity of the solution. Ga 2 (SO 4 ) 3  2Ga 3+ +3SO M0.600 M0.900 M

5. If the [SO 4 2- ] = M in 20.0 mL of Ga 2 (SO 4 ) 3, determine the [Ga 3+ ] and the molarity of the solution. Ga 2 (SO 4 ) 3  2Ga 3+ +3SO M0.600 M0.900 M Do not use the 20.0 mL!

6. Write the formula, complete, and net ionic equation for the reaction: Ca (s) +H 2 SO 4(aq) →

6. Write the formula, complete, and net ionic equation for the reaction: Ca (s) +H 2 SO 4(aq) → H 2(g) +CaSO 4(s) low solubility

6. Write the formula, complete, and net ionic equation for the reaction: Ca (s) +H 2 SO 4(aq) → H 2(g) +CaSO 4(s) low solubility Ca (s) +2H + + SO 4 2- → H 2(g) +CaSO 4(s) only break up aqueous!

6. Write the formula, complete, and net ionic equation for the reaction: Ca (s) +H 2 SO 4(aq) → H 2(g) +CaSO 4(s) low solubility Ca (s) +2H + + SO 4 2- → H 2(g) +CaSO 4(s) only break up aqueous! Ca (s) +2H + + SO 4 2- → H 2(g) +CaSO 4(s) nothing cancels!