Q22.1 A spherical Gaussian surface (#1) encloses and is centered on a point charge +q. A second spherical Gaussian surface (#2) of the same size also encloses.

Slides:



Advertisements
Similar presentations
Conductors in Electrostatic Equilibrium
Advertisements

QUICK QUIZ 24.1 (For the end of section 24.1)
Gauss’s Law Electric Flux
The electric flux may not be uniform throughout a particular region of space. We can determine the total electric flux by examining a portion of the electric.
Rank the electric fluxes through each Gaussian surface shown in the figure from largest to smallest. Display any cases of equality in your ranking.
Chapter 22: The Electric Field II: Continuous Charge Distributions
Applications of Gauss’s Law
Lecture 6 Problems.
Gauss’s law and its applications
Week #3 Gauss’ Law September 7, What’s up Doc?? At this moment I do not have quiz grades unless I get them at the last minute. There was a short.
© 2012 Pearson Education, Inc. A spherical Gaussian surface (#1) encloses and is centered on a point charge +q. A second spherical Gaussian surface (#2)
C. less, but not zero. D. zero.
Phy 213: General Physics III Chapter 23: Gauss’ Law Lecture Notes.
Chapter 23 Gauss’ Law.
Chapter 23: Gauss’s Law Gauss’s Law is an alternative formulation of the relation between an electric field and the sources of that field in terms of electric.
Oregon State University PH 213, Class #8
Gauss’s Law PH 203 Professor Lee Carkner Lecture 5.
Electricity Electric Flux and Gauss’s Law 1 Electric Flux Gauss’s Law Electric Field of Spheres Other Gaussian Surfaces Point Charges and Spheres.
Average 68.4 Median Highest 100 Lowest 26 Section Section Section Section
Outline Applications of Gauss’s Law - The single Fixed Charge -Field of a sphere of charge -Field of a spherical shell -A Line of Charge Conductors and.
Physics for Scientists and Engineers II, Summer Semester 2009 Lecture 3: May 22 nd 2009 Physics for Scientists and Engineers II.
Slide 1 Electric Field Lines 10/29/08. Slide 2Fig 25-21, p.778 Field lines at a conductor.
General Physics 2, Lec 5, By/ T.A. Eleyan 1 Additional Questions (Gauss’s Law)
Chapter 23 Gauss’s Law.
4. Gauss’s law Units: 4.1 Electric flux Uniform electric field
General Physics 2, Lec 6, By/ T.A. Eleyan
Nadiah Alanazi Gauss’s Law 24.3 Application of Gauss’s Law to Various Charge Distributions.
Today’s agenda: Announcements. Gauss’ Law Examples. You must be able to use Gauss’ Law to calculate the electric field of a high-symmetry charge distribution.
Hw: All Chapter 5 problems and exercises. Outline Applications of Gauss’s Law - The single Fixed Charge -Field of a sphere of charge -Field of a spherical.
 Since a cube has 6 identical sides and the point charge is at the center problem1 - Charge in a Cube Q Q=3.76 nC is at the center of a cube. What is.
Charles Allison © 2000 Chapter 22 Gauss’s Law HW# 5 : Chap.22: Pb.1, Pb.6, Pb.24, Pb.27, Pb.35, Pb.46 Due Friday: Friday, Feb 27.
© 2012 Pearson Education, Inc. { Chapter 21 Electric Fields and Dipoles (cont.)
Gauss’ Law.
a b c Gauss’ Law … made easy To solve the above equation for E, you have to be able to CHOOSE A CLOSED SURFACE such that the integral is TRIVIAL. (1)
General Physics 2, Lec 5, By/ T.A. Eleyan 1 Additional Questions (Gauss’s Law)
Physics.
Gauss’s law : introduction
III.A 3, Gauss’ Law.
Gauss’s Law The electric flux through a closed surface is proportional to the charge enclosed The electric flux through a closed surface is proportional.
© 2012 Pearson Education, Inc. { Chapter 22 Applying Gauss’s Law.
Copyright © 2012 Pearson Education Inc. PowerPoint ® Lectures for University Physics, Thirteenth Edition – Hugh D. Young and Roger A. Freedman Lectures.
Definitions Flux—The rate of flow through an area or volume. It can also be viewed as the product of an area and the vector field across the area Electric.
Dr. Jie ZouPHY Chapter 24 Gauss’s Law (cont.)
Physics 2112 Unit 4: Gauss’ Law
Chapter 22 Gauss’ Law.
Copyright © 2009 Pearson Education, Inc. Chapter 22 Gauss’s Law.
ELECTRICITY PHY1013S GAUSS’S LAW Gregor Leigh
Introduction: what do we want to get out of chapter 24?
Tue. Feb. 3 – Physics Lecture #26 Gauss’s Law II: Gauss’s Law, Symmetry, and Conductors 1. Electric Field Vectors and Electric Field Lines 2. Electric.
Gauss’s Law Electric Flux Gauss’s Law Examples. Gauss’s Law What’s in the box ??
Gauss’s Law (III) Examples.
Physics 2113 Lecture: 09 MON 14 SEP
Physics 212 Lecture 4, Slide 1 Physics 212 Lecture 4 Today's Concepts: Conductors + Using Gauss’ Law.

Physics 2113 Lecture 13: WED 23 SEP EXAM I: REVIEW Physics 2113 Jonathan Dowling.
Unit 1 Day 11: Applications of Gauss’s Law Spherical Conducting Shell A Long Uniform Line of Charge An Infinitely Large, Thin Plane of Charge Experimental.
Chapter 28 Gauss’s Law 28.1 to 28.4.
Two charges of 16 pC and -65 pC are inside a cube with sides that are of 0.17 m length. Determine the net electric flux through the surface of the cube.
Charles Allison © 2000 Chapter 22 Gauss’s Law.. Charles Allison © 2000 Problem 57.
Copyright © 2009 Pearson Education, Inc. Applications of Gauss’s Law.
Copyright © 2012 Pearson Education Inc. PowerPoint ® Lectures for University Physics, Thirteenth Edition – Hugh D. Young and Roger A. Freedman Lectures.
24.2 Gauss’s Law.
4. Gauss’s law Units: 4.1 Electric flux Uniform electric field
Cultural enlightenment time. Conductors in electrostatic equilibrium.
Physics 212 Lecture 4 Gauss’ Law.
Gauss’s Law Gauss’s law uses symmetry to simplify electric field calculations. Gauss’s law also gives us insight into how electric charge distributes itself.
Chapter 22 Gauss’s Law.
Flux and Gauss’s Law Spring 2009.
E. not enough information given to decide Gaussian surface #1
C. less, but not zero. D. zero.
Presentation transcript:

Q22.1 A spherical Gaussian surface (#1) encloses and is centered on a point charge +q. A second spherical Gaussian surface (#2) of the same size also encloses the charge but is not centered on it. Compared to the electric flux through surface #1, the flux through surface #2 is 1. greater 2. the same 3. less, but not zero 4. zero 5. not enough information given to decide

A22.1 A spherical Gaussian surface (#1) encloses and is centered on a point charge +q. A second spherical Gaussian surface (#2) of the same size also encloses the charge but is not centered on it. Compared to the electric flux through surface #1, the flux through surface #2 is 1. greater 2. the same 3. less, but not zero 4. zero 5. not enough information given to decide

Q22.2 Two point charges, +q (in red) and –q (in blue), are arranged as shown. Through which closed surface(s) is the net electric flux equal to zero? 1. surface A 2. surface B 3. surface C 4. surface D 5. both surface C and surface D

A22.2 Two point charges, +q (in red) and –q (in blue), are arranged as shown. Through which closed surface(s) is the net electric flux equal to zero? 1. surface A 2. surface B 3. surface C 4. surface D 5. both surface C and surface D

Q22.3 A solid spherical conductor has a spherical cavity in its interior. The cavity is not centered on the center of the conductor. If a positive charge is placed on the conductor, the electric field in the cavity 1. points generally toward the outer surface of the conductor 2. points generally away from the outer surface of the conductor 3. is zero 4. not enough information given to decide

A22.3 A solid spherical conductor has a spherical cavity in its interior. The cavity is not centered on the center of the conductor. If a positive charge is placed on the conductor, the electric field in the cavity 1. points generally toward the outer surface of the conductor 2. points generally away from the outer surface of the conductor 3. is zero 4. not enough information given to decide

Q22.4 There is a negative surface charge density in a certain region on the surface of a solid conductor. Just beneath the surface of this region, the electric field 1. points outward, toward the surface of the conductor 2. points inward, away from the surface of the conductor 3. points parallel to the surface 4. is zero 5. not enough information given to decide

A22.4 There is a negative surface charge density in a certain region on the surface of a solid conductor. Just beneath the surface of this region, the electric field 1. points outward, toward the surface of the conductor 2. points inward, away from the surface of the conductor 3. points parallel to the surface 4. is zero 5. not enough information given to decide

Q22.5 For which of the following charge distributions would Gauss’s law not be useful for calculating the electric field? 1. a uniformly charged sphere of radius R 2. a spherical shell of radius R with charge uniformly distributed over its surface 3. a right circular cylinder of radius R and height h with charge uniformly distributed over its surface 4. an infinitely long circular cylinder of radius R with charge uniformly distributed over its surface 5. Gauss’s law would be useful for finding the electric field in all of these case

A22.5 For which of the following charge distributions would Gauss’s law not be useful for calculating the electric field? 1. a uniformly charged sphere of radius R 2. a spherical shell of radius R with charge uniformly distributed over its surface 3. a right circular cylinder of radius R and height h with charge uniformly distributed over its surface 4. an infinitely long circular cylinder of radius R with charge uniformly distributed over its surface 5. Gauss’s law would be useful for finding the electric field in all of these case