© 2012 Pearson Education, Inc. Oxidation-Reduction Reactions An oxidation occurs when an atom or ion loses electrons. A reduction occurs when an atom or.

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Presentation transcript:

© 2012 Pearson Education, Inc. Oxidation-Reduction Reactions An oxidation occurs when an atom or ion loses electrons. A reduction occurs when an atom or ion gains electrons. One cannot occur without the other.

© 2012 Pearson Education, Inc. Oxidation Numbers To determine if an oxidation–reduction reaction has occurred, we assign an oxidation number to each element in a neutral compound or charged entity.

© 2012 Pearson Education, Inc. Oxidation Numbers Elements in their elemental form have an oxidation number of 0. The oxidation number of a monatomic ion is the same as its charge.

© 2012 Pearson Education, Inc. Oxidation Numbers Nonmetals tend to have negative oxidation numbers, although some are positive in certain compounds or ions. – Oxygen has an oxidation number of −2, except in the peroxide ion, in which it has an oxidation number of −1. – Hydrogen is −1 when bonded to a metal, +1 when bonded to a nonmetal.

© 2012 Pearson Education, Inc. Oxidation Numbers Nonmetals tend to have negative oxidation numbers, although some are positive in certain compounds or ions. – Fluorine always has an oxidation number of −1. – The other halogens have an oxidation number of −1 when they are negative; they can have positive oxidation numbers, however, most notably in oxyanions.

© 2012 Pearson Education, Inc. Oxidation Numbers The sum of the oxidation numbers in a neutral compound is 0. The sum of the oxidation numbers in a polyatomic ion is the charge on the ion.

© 2012 Pearson Education, Inc. Displacement Reactions In displacement reactions, ions oxidize an element. The ions, then, are reduced.

© 2012 Pearson Education, Inc. Displacement Reactions In this reaction, silver ions oxidize copper metal: Cu(s) + 2Ag + (aq)  Cu 2+ (aq) + 2Ag(s)

© 2012 Pearson Education, Inc. Displacement Reactions The reverse reaction, however, does not occur: Cu 2+ (aq) + 2Ag(s)  Cu(s) + 2Ag + (aq) x

© 2012 Pearson Education, Inc. Activity Series